Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 43

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Weekly Quiz Competition

Question 1
1 / -0

The reagents required for the following two-step transformation are?

A
(i) $$HBr$$, benzoyl peroxide, (ii) $$CH_3CN$$

B
(i) $$HBr$$, (ii) $$NaCN$$

C
(i) $$Br_2$$; (ii) $$NaCN$$

D
(ii) $$NaBr$$; (ii) $$NaCN$$

Solution
Question 2
1 / -0

The best yield of given product can be obtained by using which set of reactants $$X$$ and $$Y$$ respectively

A
$$PhLi+$$ Neopentyl chloride

B
$$PhMgBr+$$ Neopentyl bromide

C
$$t-Bu+MgBr+$$ Benzyl bromide

D
Benzylchloride$$+$$ t-Butyl chloride

Solution

Given: In the given reaction the catalyst provided is Ether.
Solution: Usually, metallic reactions (Grignard's reaction) take place in the presence of ether. Since Grignard's Reagents are highly reactive compounds, they react with any compound present so as to obtain a proton in the presence of di-ethyl ether.

In the options provided, since the B option has a Grignard' Reagent present which is $$PhMgBr $$, it will react with Neopentyl Bromide $$(CH_3)_3C-CH_2Br$$ and form the given product as shown in the above picture.

So, the Correct option : B
Question 3
1 / -0

$$CH_3.CH_2O\overset{CH_3}{\overset{|}{C}}H.CH_2.CH_2CH_2Cl$$
The correct IUPAC name of the given compound is:

A
2-ethoxy-5-chloropentane

B
1-chloro-4-ethoxy-4-methylbutane

C
1-chloro-4-ethoxypentane

D
ethyl-1-chloropentylether

Solution

$$CH_3-CH_2-O-\overset{5CH_3}{\overset{|}{\underset{4}{CH}}}-\underset{3}{CH_2}-\underset{2}{CH_2}-\underset{1}{CH_2}-Cl$$
$$1-chloro-4-Ethoxypentane$$
Parent chain is pentane
Question 4
1 / -0

Which of the following will be most reactive for $$S_N1$$ reaction?

A
$$(CH_3)_3C-Cl$$

B
$$(CH_3)_2CH-Cl$$

C
$$(CH_3)_2N-CH_2Cl$$

D
$$(CH_3)_3C-Br$$

Solution

Solution
Alkyl group are electron giving groups therefore it stabilises the Positive charge of C atom to which halide is connected.
Therefore that compound become most reactive
Hence Option A and B are more reactive than B,C because A,B have 3 alkyl groups present .
Among A and B , Option A is more reactive because it has more electronegative halide than option B
The correct option is A
Question 5
1 / -0

Which does not have conjugate system?

A
$$CH_{2} = CHCl$$

B
$$CH_{2} = CHCHO$$

C
$$CH_{3}CH = CH_{2}$$

D

Solution

it can not show any conjugation because there are no adjacent carbons to transfer the bond.
Question 6
1 / -0

Which one of the following is best catalyst for the reaction shown below ?
$${ CH }_{ 3 }({ CH }_{ 2 }{ ) }_{ 8 }{ CH }_{ 2 }{ Br }\overset { KCN }{ \underset { benzene }{ \longrightarrow } } { CH }_{ 3 }({ CH }_{ 2 }{ ) }_{ 8 }{ CH }_{ 2 }CN$$

A

B

C

D

Solution

Conversion of Hato-alkane to cynadine requires ethanolic potasium cynade generally.But the reaction catalyses with the help of phenyl-chloro methane because it catalyses SN' unimolecular.
Question 7
1 / -0

Which of the following compounds is optically active?

A

B

C

D

Solution

Refer to image 01
Optically inactive due to centre of symmetry.
Refer to image 02
Both the wedges (are on the same side of plane$$\rightarrow$$ Optically active
Question 8
1 / -0

Among the following, the optically inactive compound is :

A

B

C

D

Solution

a) Here aminos are optically active all the attached $$3$$ groups are different, thus making it available for pyramidal inversion. (Ref. Image [a])

b) Same in the case of phosphines but the rate of inversion is lesser than that of aminos. (Ref. Image [b])

c) Allenes exohibit optical activity, if these is no condition like $$a = b$$ or $$e = d$$ (Ref. Image [c])

d) Chiral carbon $$\rightarrow$$ optically active. (Ref. Image [d])
Question 9
1 / -0

Rank the following in order of decreasing rate in an $$E_{2}$$ reaction.

A
$$a > b > c$$

B
$$c > a > b$$

C
$$c > b > a$$

D
$$b > a > c$$

Solution

Among $$(a), (c)$$ [ both having same no. of $$\beta$$ hydro gens ], decreasing rate of $$E_{2}$$ reaction, $$b > a > c$$
Question 10
1 / -0

Identify the major product, X.

A

B

C

D

Solution

$$\text { hence option B is correct. }$$