Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 47

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Weekly Quiz Competition

Question 1
1 / -0

What should be the correct IUPAC name for diethylbromomethane?

A
1 - Bromo- 1, 1 - diethylmethane

B
3 - Bromopentane

C
1 - Bromo-1 - ethylpropane

D
1 - Bromopentane

Solution

The correct IUPAC name for diethylbromomethane is 3 - Bromopentane. It has molecular formula $$ C_5H_{11}Br$$.

Therefore $$B$$ is the correct option.
Question 2
1 / -0

Which of the following reactants is suitable for preparation of methane and ethane by using one step only?

A
$$H_2C = CH_2$$

B
$$CH_3OH$$

C
$$CH_3-Br$$

D
$$CH_3-CH_2-OH$$

Solution

$$2CH_3-Br+Na \longrightarrow \underset {Ethane}{CH_3-CH_3}+2NaBr$$
Mechansim:-
The above reaction is Wurtz reaction., in which alkane are produced from alkyl halide in presence of metal.
Thus, this above method can be used to prepare Ethane.

$$CH_3-Br \xrightarrow []{LiAlH_4}CH_4+Br^-$$
Mechanism:-
$$LiAlH_4$$ produce $$H^{\circleddash}$$ ion which acts as nucleophile and undergoes nucleophilic substitution gives alkane.
$$Li^+$$ $$Al\overset {-}{H_4}$$
$$LiAlH_4$$ reduce alkyl halide to alkane.
Thus the above reactant can give methane and ethane in $$1$$ step.
Question 3
1 / -0

Rank in the order of increasing acidic strength:

A
$$A < B < C$$

B
$$A < C < B$$

C
$$B < A < C$$

D
$$B < C < A$$

Solution

The greater $$I$$ effect is favorable or greater acidic strength. The $$-I$$ effect of aldehyde group is greater than the ester group. Due to this $$C$$ will be most acidic. In $$A$$ and $$B$$, $$B$$ will be less acidic as it has $$-I$$ effect sort of localized due to ester group being on a single carbon. In $$A$$ it is more delocalized is not effective on more by adjacent carbons.
Hence, the required order is- $$B<A<C$$.
Question 4
1 / -0

Match the column I with column II and with column III.

A
a - q - w; b - s - x; c - p - y; d - q - z

B
a - b - x; q - s - z; c - p - w; d - q - x

C
a - q - x; b - s - z; c - p - w; d - q - x

D
a - s - x; b - p - z; c - q - w; d - q - x

Solution

$$(a)$$ As refer to the IMAGE $$01\rightarrow$$ Due to geometrical Isomerism, it has structure at $$C-2$$

$$(b)$$ As refer to the IMAGE $$02\rightarrow$$ Possible structure has $$4$$ isomers and $$5$$ stereoisomers.

$$(c)$$ As refer to the IMAGE $$03\rightarrow$$ Only at terminal carbons same for any substitution.

$$(d)$$ As refer to the IMAGE $$04\rightarrow$$ Structure are $$3$$ stereoisomers.
Question 5
1 / -0

For the given Question (1,2,3) consider the following reaction.
Which halogen will give the best yield of a single monohalogenation product ?

A
$$F_2$$

B
$$Cl_2$$

C
$$Br_2$$

D
$$I_2$$

Solution

For monohalogenation product we prefer bromination as compared to flourination or chlorination to cleave the $$H-C$$ bond requires $$397Kj/mol$$ and $$H-Br$$ is formed which has bond dissociation energy of $$366Kj/mol$$. From Bond energy value we can say that bromination is more selective.
Question 6
1 / -0

$$CH_3 - \overset{CH_3}{\overset{|}{C}}H - CH_3 \xrightarrow{Cl_2/hv} \ product$$

Major product in the above reaction is :

A
$$CH_3 - \overset{CH_3}{\overset{|}{C}}H - CH_2 - Cl$$

B
$$CH_3 -\underset {Cl} {\overset{CH_3}{\overset{|}{\underset{|}{C}}}} - CH_3$$

C
$$CH_3 - CH_2 - CH_2 - Cl$$

D
$$CH_3 - \underset{Cl} {\underset{|}C}H - CH_2 - CH_3$$

Solution
Question 7
1 / -0

Reaction of $$C_6H_5CH_2Br$$ with aqueous sodium hydroxide follows ___________.

A
$$S_N1$$ mechanism

B
$$S_N2$$ mechanism

C
Any of the above two depending upon the temperature of reaction

D
Saytzeff rule

Solution

In aqueous media $$SN^1$$ mechanism follow.In this reaction stable carbocation get form as intermediate.
Question 8
1 / -0

$$\underrightarrow{AgNO_3} (A)$$;
Which statement is incorrect in respect of the above reaction?

A
Product is aromatic

B
product has high dipole moment

C
Product has less resonance energy

D
Product is soluble in polar-solvent

Solution
Question 9
1 / -0

$$\underset{a}{CH_3 }\, - \,\underset{b}{CH_2 }\, - \,\underset{c} {CH_2} \, - \,\underset{d} CH_2 \, - \, F$$
Arrange the hydrogens $$a, b, c, d,$$ in decreasing order of their reactivities towards chlorination:

A
$$a > b > c > d$$

B
$$b > c > d > a$$

C
$$b > c > a > d$$

D
$$c > b > a > d$$

Solution

Among all of them hydrogen 'b' will be most leachive towards chlorination as it is $$2^o$$ hydrogen and it will get less electronegativity of fluorine atom and 'd' will be least stable as it is adjacent to the fluorine atom and does not have $$3^o-2^o$$ hydrogen.
Question 10
1 / -0

2,4-hexadiyne $$(C_6 H_6)$$ is allowed to react with $$Li$$ in $$NH_3$$(liq). The product obtained is treated with 1 equivalent of $$Cl_2$$ $$CCl_4$$. Which of the following constitutional isomers are possible products ?

A
I and II

B
II and III

C
I and IV

D
I and III

Solution

Constitutional isomers that are possible products are as shown in the above image.