Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 54

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Weekly Quiz Competition

Question 1
1 / -0

n-Propyl chloride reacts with sodium metal in dry ether to give:

A
$$CH_{3} - CH_{2} - CH_{2} - CH_{2} - CH_{2} - CH_{3}$$

B
$$CH_{3} - CH_{2} - CH_{3}$$

C
$$CH_{3} - CH_{2} - CH_{2} - CH_{3}$$

D
$$CH_{3} - CH_{2} - CH_{2} - CH_{2} - CH_{2} - CH_{2} - CH_{3}$$

Solution

Wurtz reaction
$$n(CH_{3} CH_{2} CH_{2} Cl) \underset {dry\ ether}{\xrightarrow {Na}} CH_{3} - (CH_{2})_{4} - CH_{3}$$.

n-Propyl chloride reacts with sodium metal in dry ether to give n-hexane. The reaction is called a Wurtz reaction.

Hence, the correct option is $$A$$
Question 2
1 / -0

The major product formed in the following reaction is :

A

B

C

D

Solution
Question 3
1 / -0

The IUPAC name of Westron is:

A
1,1,2,2-tetrachloroethane

B
1,1,2,2-tetrachloroethene

C
1,2-dichloroethyne

D
1,3,3,3-tetrachloroprop-l-yne

Solution

The IUPAC name of Westron is 1,1,2,2- Tetrachloroethane.

Since, option (A) is correct .
Question 4
1 / -0

The given reaction is:

A
$$ S_{N^1} $$

B
$$ S_{N^2} $$

C
$$ E_1 $$

D
$$ E_2 $$

Solution

The given reaction is $$S_N1$$ reaction. The $$S_N1$$ reaction is a substitution reaction in organic chemistry. $$'S_N'$$stands for 'Nucleophilic substitution', and the $$'1'$$ says that the rate-determining step is unimolecular. Thus, the rate equation is often shown as having first-order dependence on electrophile and zero-order dependence on nucleophile. Hence correct answer is option A.
Question 5
1 / -0

The correct order of reactivity of following alkyl halides for $$ S_{N^1} $$ reaction is:

A
$$ R-I> R-Br>R-Cl> R-F $$

B
$$ R-F>R-Cl>R-Br>R-I$$

C
$$ R-F>R-Br>R-Cl >R-I$$

D
$$R-Cl>R-I>R-Br>R-F$$

Solution

Reactivity of alkyl halides towards $$SN_1$$ nucleophilic substitution reaction is $$3^o > 2^o > 1^o$$ because, in $$SN_1$$ nucleophilic reaction, the first and the slow step is the formation of a carbocation. A tertiary carbocation is more stable than a secondary carbocation which is more stable than a primary carbocation.

The reactivity of the alkyl halide is decided by the ease with which the halide leaves the substrate. As per the leaving ability, the order is $$I>Br>Cl>F$$. So, the order of the reaction is $$R-I>R-Br>R-Cl>R-F$$.

$$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (A)}$$
Question 6
1 / -0

Which of the following reactions will yield $$2, 2-dibromo-propane$$?

A
$$H_{2}C = CHBr + HBr$$

B
$$CH_{3}C \equiv CCH_{3} + 2HBr$$

C
$$CH_{3}C \equiv CH + 2HBr$$

D
$$CH_{3}CH = CHBr + HBr$$

Solution
Question 7
1 / -0

Select the optically inactive compound among the following:

A

B

C

D

Solution
Question 8
1 / -0

In the halogenation of aromatic nucleus, the halogen carrier, is used to generate the species.

A
$$Cl\bullet$$

B
$$Cl^{+}$$

C
$$Cl^{-}$$

D
$$Cl$$

Solution

It generates $$Cl^+$$
Question 9
1 / -0

In Raschig's process for the preparation of chlorobenzene, the reactants are

A
$$C_{6}H_{6}$$ and $$Cl_{2}$$

B
$$C_{6}H_{5}OH$$ and $$PCl_{5}$$

C
$$C_{6}H_{6} + HCl + O_{2}$$

D
$$C_{6}H_{5}OH$$ and $$HCl$$

Solution
Question 10
1 / -0

In the presence of iron catalyst, benzene reacts with chlorine to form

A
Chlorobenzene

B
Benzene hexachloride

C
Hexachlorobenzene

D
None of these

Solution