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Haloalkanes and...

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  • Question 1
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    Directions For Questions

    $$S_N$$ reaction is given by these compounds, which have a nucleophilic group and a good leaving EWG. It should be stable after leaving with bonding pair of $$\overline { e } $$'s and it should have high polarisability.
    Nucleophilic aliphatic substitution reaction is mainly of two types $${S_N}{1}$$ and $${S_N}{2}.{S_N}{1}$$ mechanism is a two-step process. Reaction velocity of $${S_N}{1}$$ depends only on the concentration of the substrate. It proceeds via the formation of carbocation, optically active substrate gives $$\oplus $$ and $$\ominus $$ forms of the product.
    In most of the cases, the product usually consists of $$5-20$$% inverted and $$(95-80)$$% racemised species. The more stable is the carbocation, th egreater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic is the solvent, the greater is the proportion of inversion.

    ...view full instructions

    Which of the following gives $${S_N}{1}$$ reaction?

  • Question 2
    1 / -0

    Directions For Questions

    $$S_N$$ reaction is given by these compounds, which have a nucleophilic group and a good leaving EWG. It should be stable after leaving with bonding pair of $$\overline { e } $$'s and it should have high polarisability.
    Nucleophilic aliphatic substitution reaction is mainly of two types $${S_N}{1}$$ and $${S_N}{2}.{S_N}{1}$$ mechanism is a two-step process. Reaction velocity of $${S_N}{1}$$ depends only on the concentration of the substrate. It proceeds via the formation of carbocation, optically active substrate gives $$\oplus $$ and $$\ominus $$ forms of the product.
    In most of the cases, the product usually consists of $$5-20$$% inverted and $$(95-80)$$% racemised species. The more stable is the carbocation, th egreater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic is the solvent, the greater is the proportion of inversion.

    ...view full instructions

    For the reaction given, which substrate will give maximum racemisation?

  • Question 3
    1 / -0

    Explain the relative rate of $$E2$$ reaction of the given compounds.

  • Question 4
    1 / -0

    Directions For Questions

    $$S_N$$ reaction is given by these compounds, which have a nucleophilic group and a good leaving EWG. It should be stable after leaving with bonding pair of $$\overline { e } $$'s and it should have high polarisability.
    Nucleophilic aliphatic substitution reaction is mainly of two types $${S_N}{1}$$ and $${S_N}{2}.{S_N}{1}$$ mechanism is a two-step process. Reaction velocity of $${S_N}{1}$$ depends only on the concentration of the substrate. It proceeds via the formation of carbocation, optically active substrate gives $$\oplus $$ and $$\ominus $$ forms of the product.
    In most of the cases, the product usually consists of $$5-20$$% inverted and $$(95-80)$$% racemised species. The more stable is the carbocation, th egreater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic is the solvent, the greater is the proportion of inversion.

    ...view full instructions

    Fugacity power of which group will be maximum?

  • Question 5
    1 / -0

    Directions For Questions

    $$S_N$$ reaction is given by these compounds, which have a nucleophilic group and a good leaving EWG. It should be stable after leaving with bonding pair of $$\overline { e } $$'s and it should have high polarisability.
    Nucleophilic aliphatic substitution reaction is mainly of two types $${S_N}{1}$$ and $${S_N}{2}.{S_N}{1}$$ mechanism is a two-step process. Reaction velocity of $${S_N}{1}$$ depends only on the concentration of the substrate. It proceeds via the formation of carbocation, optically active substrate gives $$\oplus $$ and $$\ominus $$ forms of the product.
    In most of the cases, the product usually consists of $$5-20$$% inverted and $$(95-80)$$% racemised species. The more stable is the carbocation, th egreater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic is the solvent, the greater is the proportion of inversion.

    ...view full instructions

    Which of the following will give $$S_N$$ reaction?

  • Question 6
    1 / -0

    Compound $$(A)$$ on reaction with $${NH}_{2}{NH}_{2}+OH$$ gives:

  • Question 7
    1 / -0

    Directions For Questions

    $$S_N$$ reaction is given by these compounds, which have a nucleophilic group and a good leaving EWG. It should be stable after leaving with bonding pair of $$\overline { e } $$'s and it should have high polarisability.
    Nucleophilic aliphatic substitution reaction is mainly of two types $${S_N}{1}$$ and $${S_N}{2}.{S_N}{1}$$ mechanism is a two-step process. Reaction velocity of $${S_N}{1}$$ depends only on the concentration of the substrate. It proceeds via the formation of carbocation, optically active substrate gives $$\oplus $$ and $$\ominus $$ forms of the product.
    In most of the cases, the product usually consists of $$5-20$$% inverted and $$(95-80)$$% racemised species. The more stable is the carbocation, th egreater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic is the solvent, the greater is the proportion of inversion.

    ...view full instructions

    Which of the following give $${S_N}{1}$$ reaction?
    Select the correct answer.

  • Question 8
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    $$\beta$$-Elimination or anti-elimination reaction is carried out with base $$({ B }^{ \overset { .. }{ \ominus  }  })$$ as shown.
    The following bases are used.
    $$(I) \overset { \ominus \quad  }{ OH } $$  $$(II) R{ O }^{ \ominus  }$$  $$(III) RCO{ O }^{ \ominus  }$$  $$(IV) \overset { \ominus  }{ C } N$$  $$(V) N{ O }_{ 3 }^{ \ominus  }$$
    The decreasing order of reactivity for the above elimination is :

  • Question 9
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    Consider the given reactions:
    Which statement(s) is/are wrong?

  • Question 10
    1 / -0

    Directions For Questions

    Isopropyl bromide was treated separately with sodium t-butoxide and sodium ethoxide under two different conditions.
    Reaction I:
    Treatment of isopropyl bromide with $$({Me}_{3}CONa) $$ at $${40}^{o}C$$ gave almost exlusively compound $$(A) ({C}_{3}{H}_{6})$$
    Reaction II
    Treatment of $$(i-PrBr)$$ with $$NaO{C}_{2}{H}_{5}$$ at $${30}^{o}C$$ yielded compound $$(A)({C}_{3}{H}_{6})$$ along with a small amount of an ether $$(B)({C}_{5}{H}_{12}O)$$.

    Compound $$(A)$$ was readily oxidised by a neutral solution of cold dil. $$KMn{O}_{4}$$ to give a brown precipitate.

    ...view full instructions

    Which of the following represents the intermediate T.S for the formation of compound $$(B)$$?

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