Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 66

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Weekly Quiz Competition

Question 1
1 / -0

The total number of monohalogenated products formed by halogenation of $2, 4, 4$ -trimethylhexane are:

A
$5$

B
$7$

C
$6$

D
$8$

E
$9$

Solution

Total number of monohalogenated products of $2, 4, 4$ -trimethylhexane are six.

$(i)$ $2$ monohalogenated products by replacing two $-C{ H }_{ 3 }$ groups at ${ C }_{ 2 }$ and ${ C }_{ 4 }$ position.

$(ii)$ $4$ monohalogenated products by replacing $H$ by $Cl$ at ${ C }_{ 2 },{ C }_{ 3 },{ C }_{ 5 },{ C }_{ 6 }$ positions. Thus, total $6$ isomers are possible.
Question 2
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The reaction of 1-bromo-3-chlorocyclobutane with metallic sodium in dioxane under reflux condition gives:

A

B

C

D

Solution
Question 3
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In the following reaction, identify the product.

A
$\underset{\,\,\,OH}{\underset{|}{C}}\!\!\!H_2-\underset{CH_3}{\underset{|}{C}H}-C_2H_5$

B
$C_2H_5-\underset{OH}{\underset{|}{C}H}-CH_2CH_3$

C
$C_2H_5-CH_2-\!\!\underset{\,\,OH}{\underset{|}{C}}\!\!H - CH_3$

D
$C_2H_5-CH = CH - CH_3$

Solution

$\begin{array}{l}\text { Ethyl Magnesium Bromide undergoes S}_N {2} \text { type of reaction with the epoxy bond in the prescence } \\\text { of ether medium. Hence option (C) is correct. }\end{array}$
Question 4
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Bromo ethane and isoproply chloride with metallic sodium in ether forms :

A
Pentane

B
2-methyl butane

C
3-methyl butane

D
2:3 dimethyl butane
Question 5
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Which of the following applies in the reaction?

${ CH }_{ 3 }CH(Br){ CH }_{ 2 }{ CH }_{ 3 }\xrightarrow [ ]{ Alc.KOH }$ ?

(I) ${ CH }_{ 3 }CH=CH-{ CH }_{ 3 }$ (major product)
(II) ${ CH }_{ 2 }=CH{ CH }_{ 2 }{ CH }_{ 3 }$ (minor product)

A
Hofmann's rule

B
Saytzeff's rule

C
Kharasch effect

D
Markovnikov’s rule

Solution

This reaction is governed by Saytzeff's rule. According to this rule, the elimination of $\beta$ -hydrogen atom takes place from the carbon having the less number of H-atoms or in other words, a stable alkene is formed (More substituted alkene is more stable)
Question 6
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Which one of the following will show optical isomerism?

A
$\begin{matrix} & H & \\ & | & \\ HO- & C & -C{ O }_{ 2 }H \\ & | & \\ & H & \end{matrix}$

B
$\begin{matrix} & H & \\ & | & \\ C{ H }_{ 3 }- & C & -C{ O }_{ 2 }H \\ & | & \\ & OH & \end{matrix}$

C
$\begin{matrix} & C{ H }_{ 3 } & \\ & | & \\ C{ H }_{ 3 }- & C & -C{ O }_{ 2 }H \\ & | & \\ & H & \end{matrix}$

D
$\begin{matrix} & C{ H }_{ 3 } & \\ & | & \\ C{ H }_{ 3 }- & C & -C{ O }_{ 2 }H \\ & | & \\ & Cl & \end{matrix}$

Solution

Hint:

The full form of IUPAC is the International Union of Pure and Applied Chemistry.

Explanation:

The core carbon atom of $2-hydroxypropanoic-acid$ is connected to four distinct groups. The molecule is known as a chiral molecule, and the carbon atom is known as a chiral carbon atom. As a result, optical isomerism is observed in $2-hydroxypropanoic acid.$

Final answer:

The correct answer is option (B).
Question 7
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Which of the given molecules are optically active?

A
(i) and (iii)

B
(ii) and (iii)

C
(i), (ii) and (iii)

D
(i) and (ii)

Solution
Question 8
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Anisole can be prepared by the action of methyl iodide on sodium phenate. The reaction is called:

A
Wurtz reaction

B
Williamson's reaction

C
Fittig's reaction

D
Etard's reaction

Solution

Anisole can be prepared by the action of methyl iodide on sodium phenate. The reaction is called Williamson's reaction.
$\displaystyle \underset { \displaystyle \text { phenol } }{ C_6H_5-OH} + NaOH \rightarrow \underset { \displaystyle \text { sodium phenoxide } }{ C_6H_5-ONa} \xrightarrow {\underset { \displaystyle \text { methyl iodide } }{ CH_3-I}} \underset { \displaystyle \text { anisole } }{ C_6H_5-O-CH_3}$

Williamson's reaction can be used for the preparation of simple as well as mixed ethers.
Question 9
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Which one of the following shows ${ S }_{ N }1$ reaction most readily?

A

B

C

D

Solution

${ S }_{ N }1$ reaction is most favorable for tertiary halide. (Since the tertiary carbocation is more stable)
Question 10
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In electrophilic aromatic substitution reactions of chlorobenzene, the ortho/para-directing ability of chlorine is due to its _______.

A
positive inductive effect $(+I)$

B
negative inductive effect $(-I)$

C
positive resonance effect $(+R)$

D
negative resonance effect $(-R)$

Solution

In electrophilic aromatic substitution reactions of chlorobenzene, the $ortho /para$ ability of chlorine is due to its positive resonance effect ( $+R$ ).