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Haloalkanes and Haloarenes Test - 68

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Haloalkanes and Haloarenes Test - 68
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  • Question 1
    1 / -0
    Out of the following, the alkene that exhibits optical isomerism is:
    Solution
    $$ \begin{array}{l} \text { As, } C^{*} \text { has } 4 \text { different groups }  \text { attached to it, so it is a chiral } \text { carbon. } \\ \text { so, above compound is optically } \text { active. } \end{array} $$

  • Question 2
    1 / -0
    Which of  the following reactions is not correctly matched?
    Solution
    Reaction in option $$B$$ is not correctly matched. Etards reaction is an organic transformation in which alkyl group $$(-CH_3)$$ bonded to an aromatic (benzene) ring undergoes oxidization and becomes an aldehyde functional group.   

    Also, the reaction given in option $$B$$ is Swarts reaction. Here when methyl bromide reacts with silver fluoride, it decomposes and gives rise to methyl fluoride and silver bromide.  
  • Question 3
    1 / -0
    Arrange the following alkyl halides in decreasing order of the rate of $$\beta$$-elimination reaction with alcoholic $$KOH$$. 
    (I) $$ CH_{ 3 }-\overset { \overset { H }{ | }  }{ \underset { \underset { CH_{ 3 } }{ | }  }{ C }  } -CH_{ 2 }Br$$
    (II) $$CH_3-CH_2-Br$$
    (III)  $$CH_3-CH_2-CH_2-Br$$
    Solution
    More the number of $$\beta$$- substituents (alkyl groups), more stable alkene it will form on $$\beta$$- elimination and more will be the reactivity.

    Hence, the decreasing order of the rate of $$\beta$$-elimination reaction with alcoholic $$KOH$$ is $$\rightarrow$$
    $$\underset{2 \; \beta-substituents}{I} > \underset{1 \; \beta-substituents}{III} > \underset{0 \; \beta-substituents}{II}$$.
  • Question 4
    1 / -0
    Ethyl iodide and n-propyl iodide are allowed to undergo Wurtz reaction. The alkane which will not be obtained in this reaction is:
    Solution
           $$CH_3CH_2I+CH_3CH_2CH_2I$$
    (Wurtz reaction) $$\downarrow Na$$
    $$\underset {butane}{CH_3CH_2CH_2CH_3}+\underset {hexane}{CH_3CH_2CH_2CH_2CH_2CH_3}+\underset {pentane}{CH_3CH_2CH_2CH_2CH_3}$$

    Ethyl iodide and n-propyl iodide are allowed to undergo Wurtz reaction and they form butane and hexane as self-addition products and pentane as cross addition product.

    $$\therefore$$ So, propane will not be formed.
  • Question 5
    1 / -0
    Which of alkyl halides exhibits complete racemisation in $$S_N1$$ reaction?
    Solution
    All the molecules undergoing $$S_N1$$ reaction shows racemisation as there is formation of 2 types of product in equal amount. Out of all these 4 alkyl halides , $$C_6H_5CH_2Cl $$ i.e benzylic chloride has the strongest tendency to undergo $$S_N1$$ here thus leading to formation of racemic mixture as it contains benzylic carbocation which is most stable. 
  • Question 6
    1 / -0
    Match the reaction given in column I and II :

    Solution
    (A) Secondary alkyl halide$$\rightarrow  SN^1$$ nucleophilic substitution.
    (B)Primary alkyl halide $$\rightarrow  SN^2$$ nucleophilic substitution 
    (C)$$CH_3CH=CH_2+HBr\rightarrow CH_3CH_2CH_2Br$$   Kharasch Effect
    (D)$$CH_3-CH_2Br\rightarrow CH_2=CH_2+HBr$$ $$E_2$$  elimination
  • Question 7
    1 / -0
    Which of the following alkane cannot be prepared by Wurtz's reaction in good yield?
    Solution
    Wurtz reaction is a reaction in which alkyl halide is converted to alkane by Na/ether. It is limited to the synthesis of symmetrical alkanes.
    (Image ) As this molecule involves ring strain the reaction will be of poor yield.

  • Question 8
    1 / -0
    Which of the following alkyl halides will undergo $$S_N1$$ reaction most readily?
    Solution
    All options given are alkyl halide (tertiary) so all will form tertiary carbocation.

    But order of leaving group ability Is $$I^-$$ > $$Br^-$$ > $$Cl^-$$ > $$F^-$$

    $$S_{N}{1}$$ mechanism goes through formation of carbocation.

    More easily leaving group leaves more easily the carbocation will form.

    Option D is correct.
  • Question 9
    1 / -0
    Match the column I with column II.
    Columns I Columns II 
    ACarbon tetrachloride iPaint remover 
    BMethylene chloride iiRefrigerators and air conditioners 
    CDDTiiiFire extinguisher 
    DFreonsivNon biodegradable insectiside 
    Solution
    A) Carbon tetrachloride is colorless, non-inflammable, and is used as a fire extinguisher. 

    B) Methylene chloride is used as a paint remover. 

    C) DDT is a chlorinated organic and non-biodegradable insecticide. 

    D) Freons are produced for aerosol propellants, refrigerators, and air conditioners. 

    Hence, option D is correct.
  • Question 10
    1 / -0
    In which of the following reactions, it proceeds via free radical mechanism?
    Solution

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