Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 81

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Weekly Quiz Competition

Question 1
1 / -0

The major product of the above reaction is:

A

B

C

D

Solution
Question 2
1 / -0

Which of the following has highest melting point?

A
$$ BeCl_2 $$

B
$$ MgCl_2 $$

C
$$ CaCl_2 $$

D
$$ BaCl_2 $$

Solution
Question 3
1 / -0

The complex / complex ion, which shows optical activity is :

A
$$[Cr (H_2O)_4Cl_2]^+$$

B
$$[Co(H_2O)_2(NH_3)_2Cl_2]^+$$

C
$$[Co(NH_3)_6]^{3+}$$

D
$$[Co(CN)_5(NC)]$$

Solution
Question 4
1 / -0

Decreasing order of melting point of compound $$I - IV$$ follows:

A
$$IV > III > II > I$$

B
$$I > II > III > IV$$

C
$$II > III > IV > I$$

D
$$II > IV > III > I$$

Solution

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Question 5
1 / -0

The nitration of a compound is due to the

A
$$NO_2$$

B
$$NO_3$$

C
$$NO$$

D
$$NO_2^+$$

Solution

The process of nitration takes place as below

$$HONO_2+ 2H_2SO_4 \rightleftarrows H_3O^+ +2HSO_4^- +\underset{(nitronium\ ion)}{ NO_2^+}$$
The electrophile responsible for nitration is $$NO_2^+$$ ion.
Question 6
1 / -0

Meso-tartaric acid is

A
optically inactive

B
optically active because of molecular symmetry

C
optically inactive due to external compensation

D
optically active because of asymmetric carbon atom

Solution

Meso isomer have two achiral carbon with opposite spin so it becomes optically inactive.
Question 7
1 / -0

Which is optically active

A
$$CH_2Cl_2$$

B
$$CHCl_3$$

C
Meso form of tartaric acid

D
Glyceraldehyde

Solution
Question 8
1 / -0

The IUPAC name of: $$\begin{matrix} { ClH }_{ 2 }C-C=C-{ CH }_{ 2 }Cl \\ |\qquad | \\ Br\qquad Br \end{matrix}$$

A
$$2,3$$ dibromo$$-1,4-$$dichlorobut$$-2-$$ene

B
$$1,4-$$dichloro$$-2,3-$$bromobutane$$-2$$

C
Dichlorodibromobutane

D
Dichlorodibromobutane
Question 9
1 / -0

In the reaction $$CH_3 -Br + 2Na + Br - CH_3 \rightarrow $$, the product called

A
Wurtz reaction

B
Aldol condensation

C
Perth's reaction

D
Levit reaction

Solution

this is the $$Wurtz reaction.$$

Typically, you would react two alkyl halides to form an alkane that consists of their respective R groups. So, as an example, you would have:
$$CH_3Br+CH_3Cl$$$$ \xrightarrow[]{Na(s)}$$$$CH_3CH_3$$
(with loss of NaCl and then NaBr )
Question 10
1 / -0

Which of the following compounds is optically active?

A
$$(CH_3)_2CHCH_2OH$$

B
$$CH_3CH_2OH$$

C
$$CCl_2F_2$$

D
$$CH_3CHOHC_2H_5$$

Solution

$$\begin{matrix} & & OH & & & \\ & & | & & & \\ { CH }_{ 3 } & - & C^* & - & H & \\ & & | & & & \\ & & { C }_{ 2 }{ H }_{ 5 } & & & \end{matrix}$$

In this structure chiral carbon is present that is why it is optically active.