Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 83

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Question 1
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Directions For Questions

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The compound (G) is:

A

B

C

D

Solution

Hence, Option "A" is the correct answer.
Question 2
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Which of the following pentoses will be optically active ?

A
All

B
II and III

C
I

D
II

Solution

All are optically active.
Question 3
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Optical activity is shown by :

A
Glucose

B
Fructose

C
Sucrose

D
All of these

Solution

Glucose and sucrose are dextrorotatory Fructose isleavorotatory.
Question 4
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$$C_6H_5CHO+HCN\rightarrow C_6H_5-$$ $$C_{\mid_OH}^{\mid ^{H}}-CH$$
The product would be

A
A racemate

B
Optically active

C
A meso compound

D
A mixture of diastereomers

Solution

$$C_6H_5CHO+HCN\rightarrow C_6H_5\overset { \underset { | }{ H } }{ \underset { \overset { | }{ OH } }{ C } } -CH$$ is optically active.
Question 5
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Directions For Questions

[passage-footer]Out of the four choices (a),(b),(c), and (d), only one is correct or wrong.[/passage-footer]

...view full instructions

Which statement is wrong in the formation of (B) from (A)

A
It proceeds by $$SN^2$$ mechanism.

B
The configuration of product (B) is $$D-form$$

C
It proceeds by $$SN^1$$ mechanism.

D
The Walden inversion occurs.

Solution

As the amount of $$NaOH$$ in reaction B is more than in reaction A, thus reaction B proceeds through $$S_{N1}$$ mechanism.
Question 6
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Directions For Questions

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Compound $$(B)$$ is:

A

B

C

D

Solution

Compound B is represented by option B.
Question 7
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An enantiomerically pure acid is treated with racemic mixture of an alcohol having one chiral carbon. The ester formed will be:

A
Optically active mixture

B
Pure enantiomer

C
Meso-compound

D
Racemic mixture

Solution

$$(d)or(+)RCOOH+(dl)or (\pm)R'OH)\rightarrow (dd)or(+)(+)RCOOR'(I)$$ and $$(dl)or(+)(-)RCOOR'(II)$$

When optically active acid reacts with racemic mixture of alcohol, it forms two types (I and II) of isomeric esters. In each, the configuration of chiral centre of acid would remain the same. So, the mixture would be optically active

Option A is correct.
Question 8
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Which of the following methods is not suitable for the preparation of $$RX$$?

A
Halogenation of alkane

B
$$ROH$$ and $$PX_3$$

C
$$ROH$$ and $$HX$$

D
Alkene and $$HX$$

Solution

$$R-H+X_2 \underset{High\ temp. 400^oC}{\underrightarrow {\ U.V.light}}\ R-X+HX$$

It is a drastic method as it requires high temperature or catalyst $$CuCl_2, FeCl_3, FeBr_3$$ etc.

2. $$ROH+PX_3 \to 3RX+H_3PO_3$$

3. $$ROH+HX\to R-X+H_2O$$

(2), (3), and (4) are feasible.

Option A is correct.
Question 9
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Which of the following would be hydrolysed most readily?

A
$$EtBr$$

B
$$MeBr$$

C

D

Solution

Hydrolysis occurs through $$S_N1$$ mechanism

Allyl halide undergoes substitution ($$S_N1$$) very easily.

Option D is correct.
Question 10
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Product (C) is:

A

B

C

D
None

Solution

$$ Ph-Br + CH_3-Br \xrightarrow{AlCl_3+ Benzene \ as \ solvent} \ Ph-CH_3$$

The product is (C) = Toluene