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Aldehydes Ketones and Carboxylic Acids Test - 7

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Aldehydes Ketones and Carboxylic Acids Test - 7
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following statements is not correct?

    Solution

    Aldehydes and ketones have polar C=O group therefore they undergo nucleophilic addition reactions. The oxygen being electronegative have a delta (small) negative charge and thus C attached to oxygen bears positive charge. Thus this electrophilic C attracts a nucleophile to add to its double bond. thus aldehydes and ketones undergo nucleophilic addition reactions.

  • Question 2
    1 / -0

    In Hell – Volhard Zelinsky reaction, the reagents used are

    Solution

    In HVZ we use Br2 in presence of Red P4. Phosphorus reacts with bromine to give phosphorus tribromide, and this converts the carboxylic acid into an acyl bromide.

  • Question 3
    1 / -0

    Compound 'A' undergoes formation of cyanohydrins which on hydrolysis gives lactic acid (CH3CHOHCOOH). Therefore, compound 'A' is

    Solution

    Cyanohydrin formation from aldehydes  or ketones followed by complete hydrolysis is used to produce alpha hydroxycarboxylic acids.

    CH3CHO + HCN →CH3CH(OH)CN  

    CH3CH(OH)CN + H3O+ → CH3CH(OH)COOH
    and on complete hydrolysis CN converts to COOH.

  • Question 4
    1 / -0

    The compound which forms acetaldehyde when heated with dilute NaOH is

    Solution

    CH3CHCl2 + OH- → CH3CH(OH)2 →→ CH3CHO + H2O

    Gem diols like (CH3CH(OH)2 ) are generally not stable. The 2 -OH group attached to same C removes H2O and forms carbonyl compounds.

  • Question 5
    1 / -0

    For making distinction between 2 – pentanone and 3 – pentanone the reagent to be employed is

    Solution

    2-pentanone ( CH3COCH2CH2CH3 ) will give iodoform test (reaction with I2 + NaOH ) because of presence  CH3CO- group and yellow precipitate will be formed but 3-pentanone (CH3CH2COCH2CH3 ) does not have CH3CO-  group hence will not give iodoform test. 

    CH3COCH2CH2CH3 + I2 + NaOH →→ CHI3 (yellow precipitate)  + CH3CH2CH2COO-Na+

    CH3CH2COCH2CH3 + I2 + NaOH →→ No reaction

  • Question 6
    1 / -0

    The product formed in Aldol condensation is

    Solution

    In aldol, we get beta hydroxyl aldehyde/Ketone which undergo further dehydration to give alpha beta unsaturated aldehyde / ketone.

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