Self Studies

Biomolecules Test - 65

Result Self Studies

Biomolecules Test - 65
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    Thiol group is present on:-
    Solution

  • Question 2
    1 / -0
    Enzyme which catalyse the joining of C - O, C - S, C - N, P - O bonds : 
    Solution

  • Question 3
    1 / -0
    The ultimate product of hydrolysis of starch is :
    Solution
    starch is the polymer of glucose hence, on it’s hydrolysis we get glucose as a product.\text{starch is the polymer of glucose hence, on it's hydrolysis we get glucose as a product.}
  • Question 4
    1 / -0
    Cobalt as a rare element is essential in the synthesis of this vitamin _______.
    Solution
    (D) Vitamin B12B_{12}
    Because cobalt is also an essential trace element for humans and found at center of B12B_{12} and produces red blood cells.

  • Question 5
    1 / -0
    Which enzyme is responsible for the fermentation of sugar or molasses? 
    Solution
    Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and CO2CO_2. It occurs naturally in yeasts. Zymase activity varies among yeast strains.
    So, the correct option is option B.
  • Question 6
    1 / -0
    Ninhydrin reagent react with α\alpha-amino acids to give a purple colour. In the reaction of ninhydrin with pheyl alanine.Which of the following responsible for this colour? 
    Solution

  • Question 7
    1 / -0
    L-alanine and D-alanine 
    Solution
    Enantiomers are a pair of molecules that are mirror images of each other. L-alanine and D-alanine are enantiomers.
  • Question 8
    1 / -0
    Three of the following statements about enzymes are correct and one is wrong. Which one is wrong?
    Solution

    Correct option: C

    Explanation:

    Enzymes are the biological catalyst that catalyzes biological reactions within a narrow range of temperature and pH.
    Certain thermophiles have enzymes that remain functional even at very high temperatures. 
    Most of the enzymes are proteins in nature but a few enzymes are RNA in nature. They are called catalytic RNAs or ribozymes.

  • Question 9
    1 / -0
    Item 'I'
    (compound)
    Item 'II'
    (reagent)


    (A) Lysine(P)I-naphthol
    (B)Furfural(Q)ninhydrin
    (C) Benzyl alcohol(R) KMnO4KMnO_4
    (D)Styrene(S)ceric ammonium
    Solution
    Lysine - Ninhydrin

    Furfural - I naphthol

    Benzyl alcohol - ceric ammonium

    Styrene - KMnO4KMn{O}_{4}

    Option A is correct
  • Question 10
    1 / -0
    A compound with molecular mass 180is acylated. with [image] to get a compound with molecular mass 390. The no. of amino group present per molecule of the former compound is: 

    Solution
    Acylation of an amine group is represented as follows

    RNH2+CH3COClRNHCOCH3+HClR-NH_2+CH_3COCl\rightarrow RNHCOCH_3+HCl

    Since, each COCH3-COCH_3 group displace one H-atom in the single step so 

    increase in mass for each step= 42u42u

    Increaseinmassduetoacylation,Δm}MassafteracylationMassbeforeacylation\therefore \left.\begin{matrix}Increase\,in\,mass\,due\,to\\acylation,\Delta m \end{matrix}\right\}Mass\,after\, acylation-Mass\,before\,acylation
                            
                            =(390180)u=(390-180)u
                           
                            =210u=210u

    No.ofacylationineachmolecules,n}increaseinmassduetoacylationMassofeachCOCH3unit\therefore \left.\begin{matrix}No.of\,acylation\,in\,each\\molecules,n \end{matrix}\right\}\dfrac{increase\,in\,mass\,due\,to\,acylation}{Mass\,of\,each-COCH_3unit}
                             
                            =210u42u=5=\dfrac{210u}{42u}=5

    Numberofaminogrouppresentpermolecule}=5\therefore \left.\begin{matrix}Number\,of\,amino\,group\,present\\per\,molecule\end{matrix}\right\}=5

    (B) 55 is correct.
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now