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Biomolecules Test - 65

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Biomolecules Test - 65
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Thiol group is present on:-
    Solution

  • Question 2
    1 / -0
    Enzyme which catalyse the joining of C - O, C - S, C - N, P - O bonds : 
    Solution

  • Question 3
    1 / -0
    The ultimate product of hydrolysis of starch is :
    Solution
    $$\text{starch is the polymer of glucose hence, on it's hydrolysis we get glucose as a product.}$$
  • Question 4
    1 / -0
    Cobalt as a rare element is essential in the synthesis of this vitamin _______.
    Solution
    (D) Vitamin $$B_{12}$$
    Because cobalt is also an essential trace element for humans and found at center of $$B_{12}$$ and produces red blood cells.

  • Question 5
    1 / -0
    Which enzyme is responsible for the fermentation of sugar or molasses? 
    Solution
    Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and $$CO_2$$. It occurs naturally in yeasts. Zymase activity varies among yeast strains.
    So, the correct option is option B.
  • Question 6
    1 / -0
    Ninhydrin reagent react with $$\alpha$$-amino acids to give a purple colour. In the reaction of ninhydrin with pheyl alanine.Which of the following responsible for this colour? 
    Solution

  • Question 7
    1 / -0
    L-alanine and D-alanine 
    Solution
    Enantiomers are a pair of molecules that are mirror images of each other. L-alanine and D-alanine are enantiomers.
  • Question 8
    1 / -0
    Three of the following statements about enzymes are correct and one is wrong. Which one is wrong?
    Solution

    Correct option: C

    Explanation:

    Enzymes are the biological catalyst that catalyzes biological reactions within a narrow range of temperature and pH.
    Certain thermophiles have enzymes that remain functional even at very high temperatures. 
    Most of the enzymes are proteins in nature but a few enzymes are RNA in nature. They are called catalytic RNAs or ribozymes.

  • Question 9
    1 / -0
    Item 'I'
    (compound)
    Item 'II'
    (reagent)


    (A) Lysine(P)I-naphthol
    (B)Furfural(Q)ninhydrin
    (C) Benzyl alcohol(R) $$KMnO_4$$
    (D)Styrene(S)ceric ammonium
    Solution
    Lysine - Ninhydrin

    Furfural - I naphthol

    Benzyl alcohol - ceric ammonium

    Styrene - $$KMn{O}_{4}$$

    Option A is correct
  • Question 10
    1 / -0
    A compound with molecular mass 180is acylated. with [image] to get a compound with molecular mass 390. The no. of amino group present per molecule of the former compound is: 

    Solution
    Acylation of an amine group is represented as follows

    $$R-NH_2+CH_3COCl\rightarrow RNHCOCH_3+HCl$$

    Since, each $$-COCH_3$$ group displace one H-atom in the single step so 

    increase in mass for each step= $$42u$$

    $$\therefore \left.\begin{matrix}Increase\,in\,mass\,due\,to\\acylation,\Delta m \end{matrix}\right\}Mass\,after\, acylation-Mass\,before\,acylation$$
                            
                            $$=(390-180)u$$
                           
                            $$=210u$$

    $$\therefore \left.\begin{matrix}No.of\,acylation\,in\,each\\molecules,n \end{matrix}\right\}\dfrac{increase\,in\,mass\,due\,to\,acylation}{Mass\,of\,each-COCH_3unit}$$
                             
                            $$=\dfrac{210u}{42u}=5$$

    $$\therefore \left.\begin{matrix}Number\,of\,amino\,group\,present\\per\,molecule\end{matrix}\right\}=5$$

    (B) $$5$$ is correct.
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