Solutions Test -17

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Solutions Test -17

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Question 1
1 / -0

Molarity of 4% NaOH solution is

A
0.1 M

B
0.5 M

C
0.01 M

D
1.0 M

Solution

M = 4 × 10/40

= 1 M
Question 2
1 / -0

The unit of molality is

A
Mole per litre

B
Mole per kilogram

C
Per mole per litre

D
Mole liter

Solution

The unit of molality is mole per kilogram.
Question 3
1 / -0

Which pair from the following will not form an ideal solution?

A
CCl₄+SiCl₄

B
H₂O + C₄H₉OH

C
C₂H₅Br + C₂H₅I

D
C₆H₁₄+ C₇H₁₆

Solution

H₂O and C₄H₉OH do not form ideal solution because there is hydrogen bonding between H₂O and C₄H₉OH.
Question 4
1 / -0

The freezing point of 1 percent solution of lead nitrate in water will be

A
Below 0°C

B
0°C

C
1°C

D
2°C

Solution

Dissolution of a non-volatile solute lowers the freezing pt. of the solution H₂O.
Question 5
1 / -0

When benzoic acid dissolves in benzene, the observed molecular mass is

A
244

B
61

C
366

D
122

Solution

Benzoic acid in benzene undergoes association through intermolecular hydrogen bonding.
Question 6
1 / -0

Acetic acid dissolved in benzene shows a molecular weight of

A
60

B
120

C
180

D
240

Solution

Molecular weight of CH₃COOH = 60

Hence the molecular weight of acetic acid in benzene = 2 × 60 =120.

In benzene acetic acid exist as dimer due to intermolecular H-bonding.
Question 7
1 / -0

The vapour pressure of a deliquescent substance is:

A
equal to the atmospheric pressure

B
equal to that of the water vapour in air

C
greater than that of the water vapour in air

D
less than that of the water vapour in air

Solution

Deliquescence is a process by which a substance absorbs moisture from the atmosphere until it dissolves in the absorbed water & forms a solution.

Deliquescence occurs when the vapour pressure of the solution that is formed is less than the partial pressure of water in the air.

All soluble salts will deliquesce if the air is sufficiently humid.

Hence, the correct option is $\text{D}$
Question 8
1 / -0

Which of the following plots represents an ideal binary mixture?

A
Plot of $P_{total} \ v/s \ 1/X$ is linear ( $X_{B}$ = mole fraction of 'B' in liquid phase).

B
Plot of $P_{total} \ v/s \ Y_{A}$ is linear $(Y_{B}=$ mole fraction of 'A' in vapour phase)

C
Plot of $\dfrac{1}{P_{total}} \ v/s \ Y_{A}$ is linear

D
Plot of $\dfrac{1}{P_{total}} \ v/s \ Y_{B}$ is non linear

Solution

The relationship between the total pressure and the mole fraction of A in the vapour phase is $\dfrac {1}{P_{total}}=\dfrac {y_A}{P_A^o}+\dfrac {y_B}{P_B^o}$
Hence, the plot of $\dfrac{1}{P_{total}} \ vs \ Y_{A}$ is linear.
Question 9
1 / -0

Which of the following represents correctly the changes in thermodynamic properties during the formation of 1 mol of an ideal binary solution.

A

B

C

D

Solution

When 1 mole of an ideal binary solution is prepared, the enthalpy of mixing is 0 $J mol^{-1}0$
As the mole fraction increases, the free energy change of mixing first decreases, reaches a minimum value and then increases.
With increase in the mole fraction, the value of the term $T \Delta S_{mix}$ first increases, reaches a maximum value and then decreases.
Hence, option C correctly represents the changes in thermodynamic properties during the formation of 1 mole of an ideal binary solution.
Question 10
1 / -0

The Van't Hoff factor for a dilute aqueous solution of glucose is :

A
$Zero$

B
$1.0$

C
$1.5$

D
$2.0$

Solution

Glucose is a non electrolyte. It does not dissociate in ions.
The vant Hoff factor (i) for dilute aqueous solution of glucose is $i= \dfrac {n(observed)} {n(theoretical)}=\dfrac {(1) } {1}=1$
Question 11
1 / -0

The incorrect statement is:

A
Vapour pressure of a liquid always increases by increasing temperature.

B
Vapour pressure only depends on temperature and not on the nature of substance.

C
Vapour pressure does not depend on the quantity of the liquid taken and the surface area of the liquid.

D
Vapour pressure is not a colligative property & is independent of the concentration of the liquid.

Solution

The vapour pressure depends on the temperature and the nature of substance.
Question 12
1 / -0

The air in a room has 15 gm of water vapour per cubic meter of its volume. However the saturation of one cubic meter of volume requires 20gm of water vapour then relative humidity is :

A
$50$ %

B
$75$ %

C
$20$ %

D
$25$ %

Solution

Relative humidity = $\displaystyle\ \frac{m}{M}\times$ 100%
Where m is the mass of vapour actually present in certain volume of air & M is the mass required to saturate the air fully of that volume.
So, R.H = $\displaystyle\ \frac{15}{20}\times100$ = 75%
Question 13
1 / -0

If liquids A and B form an ideal solution, then :

A
the entropy of mixing will be zero

B
the Gibbs free energy of mixing will be zero

C
the Gibbs free energy as well as the entropy of mixing both will be zero

D
the enthalpy of mixing will be zero

Solution

For an ideal solution, we know that :-
a) $V_{mix}=0$
b) $H_{mix}=0$
c) $\Delta$ $G_{mix}=-ve$
Final Answer : Hence, option $D$ is correct.
Question 14
1 / -0

The vapour pressure of water depends upon :

A
surface area of container

B
volume of container

C
temperature

D
all of the above

Solution

The vapour pressure of water depends upon temperature.Vapor pressures have an exponential relationship with temperature and always increase as temperature increases.
It is independent of surface area and volume of container.
Question 15
1 / -0

Which condition is not satisified by an ideal solution?

A
$\Delta H_{ mixing}=0$

B
$\Delta V_{ mixing}=0$

C
$\Delta S_{ mixing}=0$

D
Obeyance of Raoult's law

Solution

Option (C) is correct.
For an ideal solution, $\Delta H_{mixing}=0; \Delta V_{mixing}=0$ and its should obey Raoult's law.
Question 16
1 / -0

Which characteristic the weak intermolecular forces of attraction in a liquid?

A
High boiling point

B
High vapour pressure

C
High critical temperature

D
High heat of vaporization

Solution

High vapour pressure leads to the weak intermolecular forces of attraction in a liquid.Weaker are the intermolecular forces of attractions, more is the tendency for evaporation, more is vapour pressure, lower is boiling point.

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Solutions Test -17

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Solutions Test -17

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Question 1

0.1 M

0.5 M

0.01 M

1.0 M

Solution

Question 2

Mole per litre

Mole per kilogram

Per mole per litre

Mole liter

Solution

Question 3

CCl4+SiCl4

H2O + C4H9OH

C2H5Br + C2H5I

C6H14 + C7H16

Solution

Question 4

Below 0°C

0°C

1°C

2°C

Solution

Question 5

244

61

366

122

Solution

Question 6

60

120

180

240

Solution

Question 7

equal to the atmospheric pressure

equal to that of the water vapour in air

greater than that of the water vapour in air

less than that of the water vapour in air

Solution

Question 8

Plot of Ptotal v/s 1/XP_{total} \ v/s \ 1/XPtotal​ v/s 1/X is linear ( XBX_{B}XB​= mole fraction of 'B' in liquid phase).

Plot of Ptotal v/s YAP_{total} \ v/s \ Y_{A}Ptotal​ v/s YA​ is linear (YB=(Y_{B}=(YB​= mole fraction of 'A' in vapour phase)

Plot of 1Ptotal v/s YA\dfrac{1}{P_{total}} \ v/s \ Y_{A}Ptotal​1​ v/s YA​ is linear

Plot of 1Ptotal v/s YB\dfrac{1}{P_{total}} \ v/s \ Y_{B}Ptotal​1​ v/s YB​ is non linear

Solution

Question 9

Solution

Question 10

ZeroZeroZero

1.01.01.0

1.51.51.5

2.02.02.0

Solution

Question 11

Vapour pressure of a liquid always increases by increasing temperature.

Vapour pressure only depends on temperature and not on the nature of substance.

Vapour pressure does not depend on the quantity of the liquid taken and the surface area of the liquid.

Vapour pressure is not a colligative property & is independent of the concentration of the liquid.

Solution

Question 12

505050%

757575%

202020%

252525%

Solution

Question 13

the entropy of mixing will be zero

the Gibbs free energy of mixing will be zero

the Gibbs free energy as well as the entropy of mixing both will be zero

CCl₄+SiCl₄

H₂O + C₄H₉OH

C₂H₅Br + C₂H₅I

C₆H₁₄+ C₇H₁₆

Plot of $P_{total} \ v/s \ 1/X$ is linear ( $X_{B}$ = mole fraction of 'B' in liquid phase).

Plot of $P_{total} \ v/s \ Y_{A}$ is linear $(Y_{B}=$ mole fraction of 'A' in vapour phase)

Plot of $\dfrac{1}{P_{total}} \ v/s \ Y_{A}$ is linear

Plot of $\dfrac{1}{P_{total}} \ v/s \ Y_{B}$ is non linear

$Zero$

$1.0$

$1.5$

$2.0$

$50$ %

$75$ %

$20$ %

$25$ %

$\Delta H_{ mixing}=0$

$\Delta V_{ mixing}=0$

$\Delta S_{ mixing}=0$