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Surface Chemistry Test - 16

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Surface Chemistry Test - 16
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  • Question 1
    1 / -0
    Blood contains:
    Solution
    Blood is an emulsion. It consists of negatively charged colloidal particles which are albuminoid substances. Due to this colloidal nature of blood, it is possible to stop the bleeding of blood by applying a ferric chloride solution to wound.

    Hence, option B is correct.
  • Question 2
    1 / -0
    $$CO + H_2{\rightarrow } CH_3 OH$$ 

    Which catalyst is used in the above reaction?
    Solution
    $$2H_2 + CO \rightarrow CH_3OH$$ with ZnO/CuO as a catalyst. 
    and
    Ni catalyst is used in a process called steam reforming where methane is mixed with steam at high temperature to create hydrogen gas and carbon monoxide.
  • Question 3
    1 / -0

    Directions For Questions

    $$1$$ g of activated charcoal has a surface area $${10}^{3}\ {m}^{2}$$. One molecule of $$N{H}_{3}$$ having diameter $$0.3$$ nm is supposed to be adsorbed on complete surface of charcoal forming unilayer adsorption. The activated charcoal is brought in contact with $$100$$ mL of $$2\ M$$ $$N{H}_{3}$$ solution.

    ...view full instructions

    The moles of $$HCl$$ required to neutralise left $$N{H}_{3}$$ solution after adsorption is:
    Solution
    Total moles of $$N{H}_{3}$$ adsorbed on surface $$=\displaystyle\frac{1.415\times {10}^{22}}{6.023\times {10}^{23}} =0.0235$$.

    Moles of $$N{H}_{3}$$ before adsorption $$=\displaystyle\frac{100\times 2}{1000}= 0.2$$.
    So, moles of $$N{H}_{3}$$ left after adosrption $$=$$ moles of $$HCl$$ required $$= 0.2 - 0.0235 = 0.175$$.
  • Question 4
    1 / -0
    Mention catalyst in the following reaction:
    $$KClO_3 \rightarrow  KCl + O_2$$ 
    Solution
    Option (A) is correct.
    The catalyst used for the reaction $$KClO_3 \rightarrow  KCl + O_2$$ reaction is $$MnO_2$$.The $$MnO_2$$, causes the reaction to take place more rapidly at a lower temperature.
    The given reaction is a decomposition reaction of potassium chlorate used to obtain oxygen.
  • Question 5
    1 / -0
    The catalyst used in making $$H_2SO_4$$ in contact process is :
    Solution
    The contact process is the current method of producing sulfuric acid in the high concentrations needed for industrial processes. Platinum used to be the catalyst for this reaction. However, as it is susceptible to reacting with arsenic impurities in the sulfur feedstock, vanadium(V) oxide $$(V_2O_5)$$ is now preferred.
  • Question 6
    1 / -0
    Which of the following element is responsible for oxidation of water to $$O_2$$ is biological processes?
    Solution
     Water oxidation is catalyzed by a manganese-containing cofactor contained in photosystem II known as the oxygen-evolving complex. Manganese is an important cofactor, and calcium and chloride are also required for the reaction to occur.
  • Question 7
    1 / -0
    Mention catalyst in the following reaction:

    $$C_2H_4 {\rightarrow } CH_3 CHO$$  
    Solution
    The catalyst used for the conversion $$C_2H_4 {\rightarrow } CH_3 CHO$$  is $$PdCl_2$$.

    The given reaction is called Wacker's process. It is used to prepare aldehyde by hydrolysis of alkene in the presence of $$PdCl_2$$. The reaction can be given as follow:

    $$H_2C=CH_2 + PdCl_2 + H_2O \rightarrow CH_3CHO + 2HCl + Pd^{2+}$$

    For the above reaction, the catalyst is a two-component system consisting of $$PdCl_2$$ and $$CuCl_2$$. 

    Option (C) is correct.
  • Question 8
    1 / -0
    Decomposition of $$H_2O_2$$ is prevented in presence of :
    Solution
    Decomposition of $$H_2O_2$$ is prevented in the presence of acetanilide. Acetanilide acts as a stabilizer which when added to the solutions retards the decomposition. 
  • Question 9
    1 / -0
    On adding few drops of dilute $$HCl$$ or $$FeCl_3$$ to freshly precipitated ferric hydroxide, a red coloured colloidal solution is obtained. This phenomenon is known as :
    Solution
    The phenomenon of converting a freshly precipitated mass into colloidal state by the action of solute or solvent is known as peptization.

    In biochemistry, dialysis is the process of separating molecules in solution by the difference in their rates of diffusion through a semi-permeable membrane, such as dialysis tubing.

    Dissolution is the process by which a solute forms a solution in a solvent. The solute, in the case of solids, has its crystalline structure disintegrated as separate ions, atoms and molecules form.

    Hence, option A is the correct answer.
  • Question 10
    1 / -0
    The colloidal system in which the disperse phase and dispersion medium are both liquids is known as:
    Solution
    Emulsions are the colloidal solutions of two immiscible liquids in which one liquid acts as the dispersed phase and the other as the dispersion medium. 
    In emulsion, the suspended droplets (dispersed phase) are larger than the particles of dispersion medium. 
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