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Surface Chemistry Test - 24

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Surface Chemistry Test - 24
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  • Question 1
    1 / -0
    Animal charcoal is used in decolorising colour of liquids because it is a good :
    Solution
    Adsorbate adsorbs impurities from surface of substance

    Animal charcoal is good adsorbate. The impurities adsorb on its surface and thus it decolourises colour of liquids.
  • Question 2
    1 / -0
    Toothpaste and mud are examples of :
    Solution
    Mud and toothpaste are example of sol in which dispersed phase is solid and dispersion medium it s liquid.
  • Question 3
    1 / -0
    The physical adsorption of gases on the solid surface is due to:
    Solution
    When the force of attraction existing between adsorbate and adsorbent are weak Vanderwaal forces of attraction, the process is called Physical Adsorption or Physisorption. When the force of attraction existing between adsorbate and adsorbent are chemical forces of attraction or chemical bond, the process is called Chemical Adsorption.
  • Question 4
    1 / -0
    Match the columns.
    I)Dusta)Gel
    II)Milkb)Emulsion
    III)Toothpastec)Solid aerosol
    IV)Opald)Sol
    Solution
    Dust is a solid aerosol, dispersion medium in it is gas and the dispersed phase is solid. 

    Opal is a gel and dispersed phase in it is liquid and the dispersion medium is solid. 

    Toothpaste is a sol where the dispersed phase is solid and the dispersion medium is liquid. 

    Also, milk is an emulsion.
  • Question 5
    1 / -0
    Peptization denotes:
    Solution
    $$Explanation:$$ 

      Peptization is a process in which  colloidal solution is prepared by adding electrolyte to a precipitate. The electrolyte is added called as peptizing agent. This peptization process also called as deflocculation.

      Example: when the ferric chloride solution is added to the ferric hydroxide precipitate, it gives sol of ferric hydroxide.

      Therefore , we can say that in peptization, precipitate breaks and disperse into a colloidal solution.

    $$Final\ Answer:$$ Option $$C$$.

     
  • Question 6
    1 / -0
    Find the false statement for chemical catalysts ?
    Solution
    The statement (D) is the incorrect statement regarding chemical catalysts. Catalyst only increases the rates of forward and reverse reactions. It does not affect the position of the equilibrium.
  • Question 7
    1 / -0
    In the presence of a catalyst, the heat evolved or absorbed during the reaction:
    Solution
    The enthalpy change value of the reaction will not be affected by a catalyst. A catalyst will only lower the required activation energy for the reactions. Since it will lower the activation energy for both the forward and reverse reactions to the same extent, the net change in enthalpy is zero. 
  • Question 8
    1 / -0
    When two immiscible liquids are shaken together vigorously, it may form :
    Solution
    When two immiscible liquids are shaken together vigorously, it may form a colloidal dispersion.
    The solute particles (disperse phase) are suspended in solvent (dispersion medium).
    The disperse phase particles are small enough not to settle and not to be seen under microscope.
  • Question 9
    1 / -0
    Peptisation is a process in which:
    Solution
    Peptisation is a method of preparation of colloids in which a freshly formed precipitate is stirred with a peptizing agent (suitable electrolyte). The adsorption of the ions of the electrolyte by the particles of the precipitate leads to peptisation.
  • Question 10
    1 / -0
    Which of the following rules states that with the increase of every $${ 10 }^{ \circ  }C$$ temperature the rate of metabolic activity gets doubled?
    Solution
    Van't Hoff's rule states that the velocity or the metabolic activity is doubled for every rise of 10$$^0$$C in temperature. 

    Bergmann's rule states that species of larger size are found in colder environments and species of smaller size are found in warmer environments. 

    Allen's rule states that body form is linear in warm climates and more rounded and compact in cold climates. Round body shapes give a smaller surface area to volume ratio. 

    Jordon's rule states that fin ray, vertebrae or scale numbers increase with the decrease in temperature.

    Thus, the correct answer is option A.
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