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Surface Chemistry Test - 59

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Surface Chemistry Test - 59
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  • Question 1
    1 / -0
    The graph of the effect of catalyst on activation energy is given below. Fill up the blanks $$X$$ and $$Y$$ with appropriate statements.

    Solution
    In the presence of a catalyst, the activation energy is reduced between reactant and product. The intermediate is formed faster in presence of catalyst followed by an alternate and short pathway. Hence, X would be energy of activation with catalyst and Y  is the energy of activation without the catalyst.

    Option C is correct.
  • Question 2
    1 / -0
    Which of the following factors are responsible for the increase in the rate of a surface catalyzed reaction?
    (i) A catalyst provides proper orientation for the reactant molecules to react.
    (ii) The heat of adsorption of reactants on a catalyst helps reactant molecules to overcome activation energy.
    (iii) The catalyst increases the activation energy of the reaction.
    Solution

      • Catalyst orients the molecules properly, so that reaction occurs
      • The heat of adsorption of reactant molecules on a catalyst helps reactants to overcome the activation energy
      • A catalyst increases the rate of reaction by decreasing the energy of activation. 
      • Hence (i) and (ii) are the correct options.

    • Question 3
      1 / -0
      Which is a characteristic of a catalyst?
      Solution

      Some properties of catalysts are:

      1. A catalyst improves the speed of a reaction.

      2. A catalyst takes part in the reaction even though it will not be consumed or used up in the course of the reaction.

      3. A catalyst makes the reaction faster by giving an alternative path with lower activation energy.

      4. In a reversible reaction, a catalyst accelerates the reaction in both directions. Therefore, the inclusion of a catalyst will not change the equilibrium point.

      Thus the only the third statement is true.

      The correct option is C.

    • Question 4
      1 / -0
      The volume of gases $${ H }_{ 2 },\ { CH }_{ 4 },\ { CO }_{ 2 }$$, and $${ NH }_{ 3 }$$ adsorbed by $$1 g $$ of charcoal at $$288K$$ are in the order:
      Solution

      The amount of gas adsorbed by a solid depends on the nature of the gas. In general, easily liquefiable gases having higher critical temperatures are easily adsorbed because they have strong van der Waal's forces.

      The increasing order of critical temperature is $$NH_3>CO_2>CH_4>H_2$$

      The volume of gases $$H_2, CH_4, CO_2, NH_3$$ adsorbed by 1g of charcoal at 288K are in the order: $$NH_3>CO_2>CH_4>H_2$$.

      Hence option D is correct.

    • Question 5
      1 / -0
      Which of the following statements about the catalyst is true?
      Solution
      A catalyst is an agent used to accelerate the rate of reaction by decreasing activation energy as activation energy as activation energy is the barrier needed to be crossed by reactants to perform a reaction.
    • Question 6
      1 / -0
      The nature of colloidal solution of methylene blue and haemoglobin is _______ and ________ respectively.
      Solution
      The nature of colloidal solution depends upon the charge on particles of the dispersed phase and on the basis of that they are classified into positively or negatively charged.
      Hemoglobin and methylene blue both are positively charged colloidal solutions.
      Hence, option $$A$$ is correct.
    • Question 7
      1 / -0
      When $$ AgNO_3 (aq) $$ reacts with excess of iodine, we get :
    • Question 8
      1 / -0
      Artificial smoke screens are made by  
    • Question 9
      1 / -0
      Which of the following methods is used for sol destruction?
      Solution
      When an electrolyte is added to the sol, colloidal particles are neutralized by the adsorption of oppositely charged ions formed from the dissociation of the electrolyte.
      These neutral particles will eventually get aggregated resulting in the formation of a precipitate.

      Therefore the sol will be destroyed by the addition of an electrolyte.

      Hence option D is correct.
    • Question 10
      1 / -0
      Adam's catalyst is
      Solution

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