Surface Chemistry Test

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Surface Chemistry Test - 71

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Weekly Quiz Competition

Question 1
1 / -0

Amongst the following chemical reactions, the one representing homogeneous catalysis is

A
$$N_{2}(g)+3H_{2}(g)\overset{Fe}{\rightarrow}2NH_{3}(g)$$

B
$$2SO_{2}(g)+O_{2}(g)\overset{2NO}{\longrightarrow}2SO_{3}(g)+2NO(g)$$

C
$$CO(g)+3H_{2}(g)\overset{Ni}{\rightarrow}CH_{4}(g)+{H_{2}O}$$

D
$$2SO_{2}(g)+O_{2}(g)\overset{V_{2}O_{5}}{\rightarrow}2SO_{3}(g)$$

Solution

$$2SO_{2}(g)+O_{2}(g)\overset{2NO}{\longrightarrow}2SO_{3}(g)+2NO(g), $$ reaction mixture and catalyst are present in the same gas phase.
Question 2
1 / -0

Platinised asbestos helps in the formation of $$SO_{3}$$, from $$SO_{2}$$ and $$O_{2}$$. But, if even a small amount of $$As_{2}O_{3}$$ acts here as

A
A positive catalyst

B
A negative catalyst

C
An autocatalyst

D
A poison

Solution

$$ 2SO_{2}+O_{2}\xrightarrow[As_{2}S_{3}(posion)]{Platinised\ asbestos\ (catalyst)}2SO_{3} $$

Here even a small amount of $$As_{2}O_{3}$$ acts as a poison for the reaction which decreases the yield of the desired product of the reaction.
Question 3
1 / -0

A catalyst is substance which

A
Increase the equilibrium concentration of the product

B
Changes the equilibrium constant of the reaction

C
Shortens the time to reach equilibrium

D
Supplies energy to the reaction

Solution

A catalyst is a substance which alters the rate of reaction by decreasing activation energy and shortens the time to reach equilibrium.
Question 4
1 / -0

The decomposition of hydrogen peroxide can be slowed by the addition of a small amount of acetamide. The latter acts as a

A
Detainer

B
Stopper

C
Promoter

D
Inhibitor

Solution

Inhibitors are also catalysts but they slow down the rate of reaction. They are also called negative catalyst.
Question 5
1 / -0

Catalyst used in hydrogenation of oils is

A
Pt

B
Mo

C
Fe

D
Ni

Solution

$$ Oil+H_{2}\xrightarrow{{Ni-catalyst}} Ghee $$.

The catalyst used in the hydrogenation of oil is $$Ni.$$
Question 6
1 / -0

Addition of catalyst in a system

A
Increases equilibrium concentration

B
No effect on equilibrium concentration

C
Decreases equilibrium concentation

D
Increases rate if forward reaction and decreases rate of backward reaction

Solution

Catalyst has no effect on equilibrium concentrations. It only helps to attain equilibrium concentration faster.

It lowers the activation energy of both forward and backward reactions to same extent.
Question 7
1 / -0

In the titration between oxalic acid and acidified potassium permanganate, the manganous salt formed catalyzes the reaction. The manganous salt is

A
A promoter

B
A positive catalyst

C
An autocatalyst

D
None of these

Solution

In the titration between oxalic acid and acidified potassium permanganate, the manganous salt formed during the reaction and catalyzes the reaction. The manganous salt acts as an autocatalyst because the rate of reaction depends on the manganous ions formed, so manganous ions catalyze the reaction.
Hence option C is correct.
Question 8
1 / -0

Platinized asbestos is used as a catalyst in the manufacture of $$H_{2}SO_{4}$$. It is an example of

A
Heterogeneous catalyst

B
Autocatalyst

C
Heterogeneous catalyst

D
Induced catalyst

Solution

$$ \underset{(g)}{2SO_{2}}+ \underset{(g)}{O_{2}}\xrightarrow[Asbestos]{Platinized}2SO_{3} $$ ;

It is an example of heterogenous catalyst as the phase are different.
Question 9
1 / -0

The example of heteropolar sol is:

A
Starch sol in water

B
Rubber sol in water

C
Protein sol in water

D
Sulphur sol

Solution

Protein sol in water is a example of heteropolar sol.

Option C is correct.
Question 10
1 / -0

In Bredig's arc method some alkali is added because_____

A
It increase electrical conductance

B
To obtain molecular colloid

C
To obtain colloidal particles of same size

D
To stabilise the sol

Solution

The purpose of alkali is to act as a stabilizer of the sols.

Option D is correct.

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Re-Attempt Weekly Quiz Competition

Surface Chemistry Test - 71

Result

Surface Chemistry Test - 71

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Question 1

$$N_{2}(g)+3H_{2}(g)\overset{Fe}{\rightarrow}2NH_{3}(g)$$

$$2SO_{2}(g)+O_{2}(g)\overset{2NO}{\longrightarrow}2SO_{3}(g)+2NO(g)$$

$$CO(g)+3H_{2}(g)\overset{Ni}{\rightarrow}CH_{4}(g)+{H_{2}O}$$

$$2SO_{2}(g)+O_{2}(g)\overset{V_{2}O_{5}}{\rightarrow}2SO_{3}(g)$$

Solution

Question 2

A positive catalyst

A negative catalyst

An autocatalyst

A poison

Solution

Question 3

Increase the equilibrium concentration of the product

Changes the equilibrium constant of the reaction

Shortens the time to reach equilibrium

Supplies energy to the reaction

Solution

Question 4

Detainer

Stopper

Promoter

Inhibitor

Solution

Question 5

Pt

Mo

Fe

Ni

Solution

Question 6

Increases equilibrium concentration

No effect on equilibrium concentration

Decreases equilibrium concentation

Increases rate if forward reaction and decreases rate of backward reaction

Solution

Question 7

A promoter

A positive catalyst

An autocatalyst

None of these

Solution

Question 8

Heterogeneous catalyst

Autocatalyst

Heterogeneous catalyst

Induced catalyst

Solution

Question 9

Starch sol in water

Rubber sol in water

Protein sol in water

Sulphur sol

Solution

Question 10

It increase electrical conductance

To obtain molecular colloid

To obtain colloidal particles of same size

To stabilise the sol

Solution

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