The d- and f- Block Elements Test

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The d- and f- Block Elements Test - 13

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Weekly Quiz Competition

Question 1
1 / -0

Which one of the following ion exhibits colour in aqueous solution ?

A
Sc$$^{3+}$$

B
Ni$$^{2+}$$

C
Ti$$^{4+}$$

D
Zn$$^{+2}$$

Solution

Only $$Ni^{+2}$$ has incomplete d-orbitals $$d^8$$ so it is colourfull. $$Sc^{+3}, Ti^{+4}; d^0$$ configuration and $$Zn^{+2}, d^{10}$$ configuration so they are colourless.
Question 2
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The Lanthanoid contraction refers to:

A
valence electrons of the Lanthanide series

B
ionic radius of the series

C
the density of the series

D
nuclear mass of the series

Solution

Lanthanide contraction is a term used to describe the greater than expected decrease in ionic radii of the elements in the lanhtanide series from atomic number 57 i.e. lanthanum to 71 lutetium, which results in smaller than otherwise expected ionic radii for the subsequent elements starting with 72 i.e. hafnium.
Question 3
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The radius of $$La^{3+}$$ (atomic number of La $$=$$ 57) is 1.06A. Which one of the following given values will be closest to the radius of $$Lu^{3+}$$? (atomic number of Lu=71)

A
1.40A

B
1.06A

C
0.85A

D
1.60A

Solution

As we move from left to right in a raw, radii decreases.
So radii of $$Lu^{+3}$$ should be lesser than 1.06A.
Question 4
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Which of the following elements belongs to actinide series?

A
Lu

B
Gd

C
Th

D
La

Solution

Lu, Gd and La belongs to lanthanide series and Th belongs to actinide series.

Option C is correct.
Question 5
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The atomic and ionic radii (M$$^{3+}$$ ions) of Lanthanide elements decrease with increase in atomic number. This effect is called:

A
Lanthanoid contraction

B
f-f transition

C
Actinoid contraction

D
shielding effect

Solution

The greater-than-expected decrease in ionic radii of the elements in the lanthanide series is called lanthanoid contraction. The effect results from poor shielding of nuclear charge (nuclear attractive force on electrons) by 4f electrons; the 6s electrons are drawn towards the nucleus, thus resulting in a smaller atomic radius.
Question 6
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The ion which shows maximum paramagnetic character among the bivalent ions of the first transition metal series is :

A
Co$$^{2+}$$

B
Cu$$^{2+}$$

C
Cr$$^{2+}$$

D
Fe$$^{2+}$$

E
Mn$$^{2+}$$

Solution

$$Mn^{2+}$$ ion show maximum paramagnetic character among the bivalent ions of first transition metal series.

Electronic configuration of $$Mn^{2+}$$ is $$[Ar] 4s^0 3d^5$$. In this ion $$d$$- orbital is half filled and has 5 unpaired electrons, thus it shows maximum paramagnetic character.

Hence, option E is correct.
Question 7
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Which of the following lanthanide is commonly used ?

A
Lanthanium

B
Nobelium

C
Thorium

D
Cerium

Solution

Cerium is the major component of mischmetal alloy (just under 50%). The best-known use for this alloy is in flints for cigarette lighters. This is because cerium will make sparks when struck. The only other element that does this is iron.

Cerium(Ill) oxide has uses as a catalyst. It is used in the inside walls of self-cleaning ovens to prevent the build-up of cooking residues. It is also used in catalytic converters. Cerium(III) oxide nanoparticles are being studied as an additive for diesel fuel to help it burn more completely and reduce exhaust emissions.

Cerium sulfide is a non-toxic compound that is a rich red colour. It is used as a pigment.

Cerium is also used in flat-screen TVs, low-energy light bulbs and floodlights.
Question 8
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The first and last elements of actinides are:

A
Actinium and Thorium

B
Actinium and Nobelium

C
Actinium and Mendelevium

D
Actinium and Lawrencium

Solution

We have 15 elements in actinides. They are from atomic number 89 to 103 Actinium, Thorium, Protactinium, Uranium, Neptunium, Plutonium, Americium, Curium, Berkelium, Californium, Einsteinium, Fermium, Mendelevium, Nobelium, Lawrencium. Hence, from these list we could say that Actinium is the first and Lawrencium is the last element in actinides.
Question 9
1 / -0

The highest magnetic moment is shown by the transition metal with the configuration:

A
$${3d}^{2}$$

B
$${3d}^{5}$$

C
$${3d}^{7}$$

D
$${3d}^{9}$$

Solution

The transition metal with most unpaired electrons shows the highest magnetic moment.

$${3d}^{2}$$ = 2 unpaired electron.

$${3d}^{5}$$ =5 unpaired electron.

$${3d}^{7}$$ =3 unpaired electron.

$${3d}^{9}$$ =1 unpaired electron.

Option A, B, C and D have 2,5,3 and 1 unpaired electrons respectively.

Hence the correct solution is B.
Question 10
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5f series elements are known as_______

A
Lanthanides

B
Representative elements

C
Transition elements

D
Actinides

Solution

Actinides are also called the 5f series.

Filling up of the 5f orbitals after actinium (Z = 89) gives the 5f-inner transition series known as the actinoid series.

Option D is correct.

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Re-Attempt Weekly Quiz Competition

The d- and f- Block Elements Test - 13

Result

The d- and f- Block Elements Test - 13

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Question 1

Sc$$^{3+}$$

Ni$$^{2+}$$

Ti$$^{4+}$$

Zn$$^{+2}$$

Solution

Question 2

valence electrons of the Lanthanide series

ionic radius of the series

the density of the series

nuclear mass of the series

Solution

Question 3

1.40A

1.06A

0.85A

1.60A

Solution

Question 4

Lu

Gd

Th

La

Solution

Question 5

Lanthanoid contraction

f-f transition

Actinoid contraction

shielding effect

Solution

Question 6

Co$$^{2+}$$

Cu$$^{2+}$$

Cr$$^{2+}$$

Fe$$^{2+}$$

Mn$$^{2+}$$

Solution

Question 7

Lanthanium

Nobelium

Thorium

Cerium

Solution

Question 8

Actinium and Thorium

Actinium and Nobelium

Actinium and Mendelevium

Actinium and Lawrencium

Solution

Question 9

$${3d}^{2}$$

$${3d}^{5}$$

$${3d}^{7}$$

$${3d}^{9}$$

Solution

Question 10

Lanthanides

Representative elements

Transition elements

Actinides

Solution

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