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The d- and f- Block Elements Test - 26

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The d- and f- Block Elements Test - 26
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  • Question 1
    1 / -0
    The position in the periodic table to which the $$Al$$ metal belongs : 
    Solution

    Electronic configuration of aluminium is $$[Ne] 3s^{2}3p^{1}$$.

    In the above configuration, the valence electron enters into p-orbital. So $$Al$$ is a p-block element.

    Hence option D is correct.

  • Question 2
    1 / -0
    Which one of the following forms a colorless solution in aqueous medium?
    Solution
    $$Cr^{3+}$$ = $$3d^3$$ = coloured

    $$Ti^{3+}$$ =  $$3d^1$$ = coloured

    $$V^{3+}$$ =  $$3d^2$$ = coloured

    $$Sc^{3+}$$ has electron configuration of [Ar] $$4s^0  3d^0$$. Therefore without any unpaired electrons it forms a colorless solution in aqueous medium. 
  • Question 3
    1 / -0
    Which of the following electronic configuration will be associated with the lowest magnetic moment?
    Solution
    The magnetic moment, $$ \mu_s = \sqrt {n(n+2)}  \mu_B$$ where n is the number of unpaired electrons.

     $$ d^2$$ has 2 unpaired electrons, $$ d^3$$ has 3 unpaired electrons, $$ d^4$$ has 4 unpaired electrons and $$ d^9$$ has 1 unpaired electron. 

    Hence $$ d^9$$ will have the lowest magnetic moment.
  • Question 4
    1 / -0
    Magnetic moments of $$Cr(Z=24)$$, $${Mn} (Z=25)$$ and $${Fe}(Z=26)$$, are $$x ,y , z$$. 

    They are in order:
    Solution


     n = number of unpaired electrons. Greater the number of unpaired electrons, greater will be the magnetic moment.

    $$ Cr$$ =  6 unpaired electron

    $$ Mn$$ = 5 unpaired electron

    $$Fe$$ = 4 unpaired electron
     .
    Therefore the order of magnetic moment is $$ x>y>z$$.

    Hence,option C is correct. 

  • Question 5
    1 / -0
    Which of the following elements do not show the properties characteristics of $$d$$-block elements:
    Solution
    All are d-block elements except zinc, cadmium and mercury have partially filled d-orbitals. But, zinc, cadmium and mercury have completely filled d-orbitals and they exhibit common oxidation state.
  • Question 6
    1 / -0
    Which of the ions will give colorless aqueous solution?
    Solution
    $${Ni}^{2+}$$ is light green, $${Fe}^{2+}$$ is pale green, 

    $${Cu}^{2+}$$ is blue and $${Cu}^{1+}$$ is colorless in aqueous solution as its outermost configuration is $$3d^{10}$$ so thei is no unpaired electron which causes colour.

    Hence ,option D is correct.
  • Question 7
    1 / -0
    Which of the following belongs to the actinoids series of elements?
    Solution
    $$ _{92}U$$, Uranium, is a part of the actinoids series of elements. 
  • Question 8
    1 / -0
    Maximum magnetic moment is shown by:
    Solution
    Magnetic moment increases with the increase in number of unpaired electrons. 

    $$ d^5$$ has 5 unpaired electrons .

    $$ d^6$$  has 4 unpaired electrons 

    $$d^7$$has 3 unpaired electrons 
     
    $$ d^8$$ has 2 unpaired electrons.  

    Hence,option A is correct.
  • Question 9
    1 / -0
    Arrange the following ions in order of their magnetic moment:

    $$(i) {V}^{4+}$$ $$(ii) {Mn}^{4+}$$ $$(iii) {Fe}^{3+}$$ $$(iv){Ni}^{2+}$$

    [Atomic number of $$V=23, Mn=25,Fe=26,Ni=28$$]
    Solution
    The transition metal with more unpaired electrons corresponds to the higher magnetic moment. 

    $$ V^{4+}\rightarrow4s^0 3d^1$$, 1 unpaired electron;  

    $$ Mn^{4+}\rightarrow4s^0 3d^3$$, 3 unpaired electron;  

    $$ Fe^{3+}\rightarrow4s^0 3d^5$$, 5 unpaired electron and  

    $$ Ni^{2+}\rightarrow4s^0 3d^8$$, 2 unpaired electron.

    Hence, option B is correct.
  • Question 10
    1 / -0
    Lanthanoids contraction is caused due to:
    Solution
     The imperfect shielding of outer s orbital electrons by 4f electrons from the nuclear charge results in greater than expected decrease in ionic radii of the elements in the lanthanide series known as lanthanide contraction.
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