The d- and f- Block Elements Test

Result

The d- and f- Block Elements Test - 30

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

The total spin and magnetic moment for the atom with atomic number 25 are respectively________________

A
$$\pm$$3, $$\sqrt{48}$$ BM

B
$$\pm$$3, $$\sqrt{35}$$ BM

C
$$\pm$$$$\frac{3}{2}$$, $$\sqrt{48}$$ BM

D
$$\pm$$$$\frac{5}{2}$$, $$\sqrt{35}$$ BM
Question 2
1 / -0

Which of the following is not a heavy metal?

A
$$Cu$$

B
$$Hg$$

C
$$Pb$$

D
$$K$$

Solution

A heavy metal is any relatively dense metal. Density criteria range from above $$3.5g/cm^3$$ to above $$7g/cm^3$$. Atomic numbers of heavy metals are generally greater than 20. $$Cu, Hg$$ and $$Pb$$ are heavy metals but $$K$$ is not a heavy metal. So answer is D.
Question 3
1 / -0

The approximate size of the nucleus of $$_{28}^{64}Ni$$ is:

A
3 fm

B
4 fm

C
5 fm

D
2 fm

Solution

Approximate size of the nucleus is given by,

$$R_A=1.25 \times {A}^{\frac{1}{3}} fm$$, for this given nucleus $$A=64$$, and $$Z=28$$,

Therefore size of this nucleus,

$$R_{64}=1.25 \times {64}^{\frac{1}{3}} fm=5.0 fm$$

So, option 'C' is correct.
Question 4
1 / -0

In the general electronic configuration,
$$(n-2)f^{1-14} (n-1)d^{01} ns^2$$ (where n = 7) the configuration will be of:

A
lanthenides

B
actinides

C
transition elements

D
none

Solution

General electronic configuration is given:
$$(n -2) f^{1 -14} (n -1) d^{0 1} ns^2 ,where ( n =7 )$$
$$5f^{1 -14} 6d^{0 1 }ns^2$$
The seventh period $$(n=7)$$ is similar to the sixth period with the successive filling up of the 7s, 5f, 6d and 7p orbitals and includes most of the man-made radioactive elements. This period will end at the element with atomic number 118 which would belong to the noble gas family. Filling up of the 5f orbitals after actinium $$(Z=89)$$ gives the 5f-inner transition series known as the Actinoid Series.
Question 5
1 / -0

The decreasing order of solubility of silver halide is:

A
$$AgI > AgBr > AgCl > AgF$$

B
$$AgF > AgCl > AgBr > AgI$$

C
$$AgCl > AgF > AgBr > AgI$$

D
$$AgBr > AgF > AgI > AgCl$$

Solution

The decreasing order of solubility of silver halide is $$\displaystyle AgF > AgCl > AgBr > AgI $$
On moving down the group of halogens, the ionic size increases and hydration energy decreases. Hence, the solubility decreases.
Question 6
1 / -0

The point of dissimilarity between lanthanides and actinides is:

A
three outermost shells are partially filled

B
they show oxidation of $$+3$$ ( common)

C
they are called inner transition elements

D
they are radioactive in nature

Solution

Lanthanides and actinides both are not radioactive. Except promethium all lanthanides are non-radioactive. While all actinides are radioactive.
Question 7
1 / -0

The pair that referred as 'chemical twins' is:

A
Ac, Cf

B
Hf, Ta

C
Tc, Re

D
La, Ac

Solution

Due to the presence of $$f$$-electrons, the nuclear is not screened effectively. Thus, the atom radius of elements of second transition series (i.e., Nb, Mo, Tc, etc) is similar to that of corresponding third transition series elements (i.e., Ta, W, Re).

Hence, Nb-Ta; Mo-W or Tc-Re are called chemical twins.
Question 8
1 / -0

Select a ferromagnetic material from the following?

A
Dioxygen

B
Chromium (IV) oxide

C
Benzene

D
Dihydrogen monoxide

Solution

Chromium (IV) dioxide is considered to be ferromagnetic. The ferromagnetic properties of these compounds allow them to be used in data tape, a way to store information.
So, answer is B.
Question 9
1 / -0

Select the coloured compound amongst the following.
(At. no, $$\text{Ti = 22, Cr = 24, Cu = 29, Zn = 30}$$)

A
$$Ti{Cl}_{4}$$

B
$$Cr{Cl}_{3}$$

C
$$Zn{Cl}_{2}$$

D
$$CuCl$$

Solution

Electronic configuration of transition metal ions in each salt is:
$$Ti^{4+ }$$: $$[Ar]$$

$$Cr^{3+ }$$: $$[Ar]3d^3$$

$$Zn^{2+ }$$: $$[Ar]3d^{10}$$

$$Cu^{1+ }$$: $$[Ar]3d^{10}$$

Therefore electrons in d-orbital of $$Cr^{3+ }$$ can be excited, resulting in the coloured compound.

Option B is correct.
Question 10
1 / -0

Generally transition elements and their salts are coloured due to presence of___________

A
coloured compounds and ions

B
coloured anions and cations

C
coloured particles and ions

D
unpaired electrons

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

The d- and f- Block Elements Test - 30

Result

The d- and f- Block Elements Test - 30

Score

-

Rank

-

SHARING IS CARING

Question 1

$$\pm$$3, $$\sqrt{48}$$ BM

$$\pm$$3, $$\sqrt{35}$$ BM

$$\pm$$$$\frac{3}{2}$$, $$\sqrt{48}$$ BM

$$\pm$$$$\frac{5}{2}$$, $$\sqrt{35}$$ BM

Question 2

$$Cu$$

$$Hg$$

$$Pb$$

$$K$$

Solution

Question 3

3 fm

4 fm

5 fm

2 fm

Solution

Question 4

lanthenides

actinides

transition elements

none

Solution

Question 5

$$AgI > AgBr > AgCl > AgF$$

$$AgF > AgCl > AgBr > AgI$$

$$AgCl > AgF > AgBr > AgI$$

$$AgBr > AgF > AgI > AgCl$$

Solution

Question 6

three outermost shells are partially filled

they show oxidation of $$+3$$ ( common)

they are called inner transition elements

they are radioactive in nature

Solution

Question 7

Ac, Cf

Hf, Ta

Tc, Re

La, Ac

Solution

Question 8

Dioxygen

Chromium (IV) oxide

Benzene

Dihydrogen monoxide

Solution

Question 9

$$Ti{Cl}_{4}$$

$$Cr{Cl}_{3}$$

$$Zn{Cl}_{2}$$

$$CuCl$$

Solution

Question 10

coloured compounds and ions

coloured anions and cations

coloured particles and ions

unpaired electrons

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.