The d- and f- Block Elements Test

Result

The d- and f- Block Elements Test - 45

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Weekly Quiz Competition

Question 1
1 / -0

Atomic numbers of $$Cr$$ and $$Fe$$ are, respectively, $$24$$ and $$26$$. Which of the following is paramagnetic with spin of electron?

A
$$Cr(CO)_6$$

B
$$[Fe(CO)_5]$$

C
$$[Fe(CN)_6]^{4-}$$

D
$$[Cr(NH_3)_6]^{3+}$$

Solution

The increasing order of field strength of the ligands is $$NH_{3}<CN^{-}<CO$$. So, only the complex $$[Cr(NH_{3})_{6}]^{+3}$$ will be a comparatively high-spin complex.

$$Fe^{+2}$$ has $$24$$ electrons and $$Cr^{+3}$$ has $$21$$ electrons. The unpaired electrons of $$Fe$$ and $$Cr$$ can pair up in the complexes containing $$CO$$ and $$CN^{-}$$ ligands because they are strong field ligands. But in the complex $$[Cr(NH_{3})_{6}]^{+3}$$, there is a single unpaired electron present as $$NH_3$$ is a weak field ligand. So, the complex $$[Cr(NH_3)_6]^{3+}$$ will be paramagnetic.

Therefore, the correct option is (D).
Question 2
1 / -0

The d-electron configurations of $$Mn^{2+}, Fe^{2+}, Co^{3+}$$ and $$Ni^{2+}$$ are $$3d^5, 3d^6, 3d^6, 3d^8$$, respectively. Which of the following aqua complexes will exhibit the minimum paramagnetic behavior?

A
$$[Fe(H_2O)_6]^{2+}$$

B
$$[Co(H_2O)_6]^{3+}$$

C
$$[Ni(H_2O)_6]^{2+}$$

D
$$[Mn(H_2O)_6]^{2+}$$

Solution
Question 3
1 / -0

The color of $$Cu^+$$ compounds is?

A
White

B
Blue

C
Orange

D
Yellow

Solution

$$Cu^{+}$$ compounds are generally colourless (white). The electronic configuration is $$3d^{10}4s^{0}$$. So there is no unpaired electron present in the ion. So the electronic transition between two energy levels $$t_{2g}$$ and $$e_{g}$$ (responsible for the colour of transition metals) is not possible. So the correct option is A.
Question 4
1 / -0

$$ K_2 [HgI_4] $$ detects the ion/group:

A
$$ NH^-_2 $$

B
$$NO$$

C
$$ NH_4^+ $$

D
$$ AlCl_3 $$

Solution
Question 5
1 / -0

Yellow color solution of $$ FeCl_{3} $$ changew to light green when

A
$$ SnCl_{2} $$ is added

B
Zn is added

C
$$ H_{2}S $$ gas is passed

D
All are true

Solution

Yellow color solution of FeCl3 changes to light green.It means ferric chloride is reduced to FeCl2 which is light green in color.

all are true
Question 6
1 / -0

For Ni and pt dofferent L.P. in KJ $$ mol^{-1} $$ are given below.
$$ \frac { (IP)_ 1+(IP)_ 2 }{ \overset { Ni }{ Pt } \quad \quad \quad \quad \overset { 2.49 }{ 2.60 } } \frac { (IP)_ 3+(IP)_ 4 }{ \overset { 8.80 }{ 6.70 } } $$

A
Nickel (II) compounds tend to be thermodynami -cally more stable than platinum (II)

B
Platinum (IV) compounds lend to be more stable than nickel (IV)

C
Both are correct

D
None is correct

Solution

Nickel (II) compounds tend to be thermodynami -cally more stable than platinum (II)

and Platinum (IV) compounds lend to be more stable than nickel (IV)
both A and B are correct
Question 7
1 / -0

In $$ Cr_2O_7^{-2} $$ every Cr is linked to :

A
Two O-atoms

B
Three O-atoms

C
Four O-atoms

D
Five O-atoms

Solution
Question 8
1 / -0

The colorless spccits is:

A
$$ VCI_3 $$

B
$$ VOSO_4 $$

C
$$ Na_3 VO_4 $$

D
$$ [V(H_2O]SO_4] H_2O $$

Solution

Trisodium vanadate is an inorganic compound and this is show colorless compound
Question 9
1 / -0

Which of the following electronic configuration will be associated with the lowest magnetic moment?

A
$$ d^2 $$

B
$$ d^3 $$

C
$$ d^4 $$

D
$$ d^9 $$

Solution
Question 10
1 / -0

Arrange the following ions in order of their magnetic moment:
(i) $$ V^{4+} $$
(ii) $$ Mn^{4+} $$
(iii) $$ Fe^{3+} $$
(iv) $$ Ni^{2+} $$
(Atomic number of V = 23, Mn = 25, Fe = 26, Ni = 28)

A
(ii) > (iii) > (i) > (iv)

B
(iii) > (ii) > (iv) > (i)

C
(i) > (iv) > (iii) > (ii)

D
(iv) > (iii) > (i) > (ii)

Solution