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The d- and f- Block Elements Test - 66

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The d- and f- Block Elements Test - 66
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Identify the incorrect statement in the following
  • Question 2
    1 / -0
    The calculated spin-only magnetic moments (BM) of the anionic and cationic species of $$[Fe(H_2O)_6]_2$$ and $$[Fe(CN)_6]$$, respectively, are:
    Solution
    Solution:- (C) $$0$$ and $$4.9$$

    Complex is $$[Fe(H_2O)_6]_2 [Fe(CN)_6]$$

    Complex 
    ion

      Configuration 

     No. of 
    unpaired electrons

     Magnetic 
    moment
    $$[Fe(H_2O)_6]^{2+}$$

    $$[Fe(CN)_6]^{4-}$$
     $$t_{2g}^4 \,e_g^2$$
     
    $$t_{2g}^6 \,e_g^0$$
     $$4$$

     $$0$$
     $$4.9 \,BM$$

     $$0$$
  • Question 3
    1 / -0
    $$\left[ Cr\left( { H }_{ 2 }O \right) _{ 6 }{ Cl }_{ 3 } \right] $$ has a magnetic moment of 3.83 BM. The correct distribution of 3d electrons in the chromium atom in the complex is:
  • Question 4
    1 / -0
    For which of the following elements all of its existing ion, $$M^{x+}$$, will be diamagnetic?
    Solution

    A neutral sodium atom is likely to achieve an octet in its outermost shell by losing its one valence electron. The cation produced in this way is Na$$^+$$, having electronic configuration [Ne] 3s$$^0$$ which means there is no unpaired electron. 

    Hence, Na is diamagnetic in its existing ion form. 

  • Question 5
    1 / -0
    Match the catalysts (Column I) with products column (II)
    Column IColumn II
    (A) $${V}_{2}{O}_{5}$$(i) Polyethylene
    (B) $$Ti{Cl}_{4}/Al{(Me)}_{3}$$(ii) ethanal
    (C) $$Pd{Cl}_{2}$$(iii) $${H}_{2}{SO}_{4}$$
    (D) Iron Oxide(iv) $${NH}_{3}$$
    Solution
    $$V_2O_5$$   is used as a catalyst in contact process for $$H_2SO_4$$

    $$TiCl_4/Al(Me)_3 is used as a catalyst in  Ziegler Natta salt used as the catalyst for polymerisation of ethane to produce Polyethylene

    $$PdCl_2 \rightarrow$$ used as catalyst for ethanal (Wacker process)

    Iron oxide $$\rightarrow$$ is used as a catalyst in Haber's synthesis of ammonia.

    Hence, the correct option is $$D$$
  • Question 6
    1 / -0
    Consider the hydrates ions of $$Ti^{2+}, V^{2+}, Ti^{3+}$$ and $$Sc^{3+}$$. The correct order of their spin-only magnetic moments is:
    Solution
    Solution:- (A) $$Sc^{3+} < Ti^{3+} < Ti^{2+} < V^{2+}$$

    $$a)\ Ti^{2+} = 1s^2 2s^2 2p^6 3s^2 3p^6 3d^2$$

    Unpaired electrons $$=2$$

    Spin only magnetic moment $$(\mu) = \sqrt{2(2+2)}$$
                                                           $$=\sqrt{8} B.M$$

    $$b)\ Ti^{3+} = 1s^22s^22p^6 3s^2 3p^6 3d^1$$

    Unpaired electrons $$=1$$

    $$\mu =\sqrt{1(1+2)} = \sqrt{3} B.M$$

    $$c)\ V^{2+} = 1s^2 2s^2 2p^6 3s^2 3p^6 3d^3$$

    $$\mu = \sqrt{3(3+2)} = \sqrt{15} B.M$$

    $$d)\ Sc^{3+} = 1s^2 2s^2 2p^6 3s^2 3p^6$$

    $$\mu = 0$$
  • Question 7
    1 / -0
    In the hydrogenenation of oil :-
    Solution
    Nickel is the preferred catalyst for hydrogenation of fats and oils, hence option (D) is correct.
  • Question 8
    1 / -0
    Photochromic glass, used for sunglasses, darkens when exposed to bright light and becomes
    more transparent again when the light is less bright. The darkness of the glass is related to the
    concentration of silver atoms.
    The following reactions are involved.
    reaction 1 $$Ag^{+}  + Cl^{-}\rightleftharpoons Ag + Cl$$
    reaction 2 $$Cu^{+} + Cl \rightarrow Cu^{2+} + Cl^{-}$$
    reaction 3 $$Cu^{2+} + Ag \rightarrow Cu^{+}  + Ag^{+}$$
    Which statement about these reactions is correct?
    Solution
    Statement $$1$$ is correct as the $${Cu}^{2+}$$ and $${Cu}^{+}$$ ions are regenerated at the end of reactions $$2$$ and $$3$$ respectively, hence they act as catalysts.
    Statement $$2$$ is incorrect as the oxidation number of $$Cl$$ changes from $$0$$ to $$-1$$, hence the $${Cu}^{+}$$ ions act as a reducing agent.
    Statement $$3$$ is incorrect as silver atoms are converted to silver ions. Silver atoms increase the darkness of the glass whereas silver ions cause the glass to become more transparent.
    Statement $$4$$ is incorrect as the oxidation number of silver increases from $$0$$ to $$+1$$, hence the silver atoms are oxidised.
  • Question 9
    1 / -0
    The INCORRECT statement is:
    Solution
    (1) $$[Fe(H_{2}O)_{6}]^{2+}, Fe^{2+} \rightarrow 3d^{6} \rightarrow 4$$ unpaired electron

    $$[Cr(H_{2}O)_{6}]^{2+}, Cr^{2+}\rightarrow 3d^{4}\rightarrow 4$$ unpaired electron

    (2) $$[Ni(NH_{3})_{4}(H_{2}O)_{2}]^{2+} ,\ Ni^{2+}\rightarrow 3d^{8}\rightarrow 2$$ unpaired electron

    $$\mu_{m} = 2.83\ B.M$$

    (3) In gemstone, ruby has $$Cr^{3+}$$ ion occupying the octahedral sites of aluminium oxide $$(Al_{2}O_{3})$$ normally occupied by $$Al^{3+}$$ ion.

    (4) The complementary color of violet is yellow.
  • Question 10
    1 / -0
    Select the paramagnetic complex compound.
    Solution

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