The d- and f- Block Elements Test

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The d- and f- Block Elements Test - 70

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Weekly Quiz Competition

Question 1
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Which of the following is a correct statement?

A
Aqueous solutions of $$Cu^+$$ and $$Zn^{2+}$$ are colourless

B
Aqueous solutions of $$Cu^{2+}$$ and $$Zn^{2+}$$ are colourless

C
Aqueous solutions of $$Fe^{3+}$$ is green in colour

D
Aqueous solutions of $$MnO_4^-$$ is colourless

Solution
Question 2
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Mark the correct statements(s):
1. Manganese coloured ions
2. Zinc forms coloured ions
3. $$[CoF_6]^{3-}$$ is diamagnetic
4. $$Sc$$ from $$+4$$ oxidation state
5. Zinc exhibits only $$+2$$ oxidation state

A
$$1$$ and $$2$$

B
$$1$$ and $$5$$

C
$$2$$ and $$4$$

D
$$3$$ and $$4$$

E
$$2$$ and $$5$$

Solution

The most common oxidation states of manganese are $$+2, +3, +4, +6$$ and $$+7$$. The most stable oxidation state for manganese is $$+2$$, which has a pale pink color.

Zinc has no unpaired electrons in its d orbital and has a stable fully filled d orbital state. Hence, due to the absence of an unpaired electron in Zinc, it cannot show specific colouration in its salts.

$$[CoF_6]^{3-}$$ ion, $$Co$$ is in $$+3$$ oxidation state. $$F^-$$ is a weak field ligand so there will be 4 unpaired electrons in the $$d-$$ orbital so the compound is paramagnetic.

$$Sc$$ has $$3d^14s^2$$ configuration. So its common oxidation state is $$+3$$.

Zinc has an electron configuration of $$[Ar] 3d^{10} 4s^{2}$$. On the outermost electron shell, Zinc has only two electrons. Losing all the electrons on the fourth shell would mean Zn lost two negative charges, making it the ion $$Zn^{2+}$$.
Hence the correct answer is option B.
Question 3
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The catalysic activity of transition elements and their compounds is described to:

A
their chemical reactivity

B
their magnetic behaviour

C
their unfilled $$d-$$orbital

D
their ability to adopt multiple oxidation states and their complexing ability.

Solution

Option D) is correct

The catalytic activity of transition elements and their compounds is ascribed to their ability to adopt multiple oxidation states and their complexing ability.

Catalysis at a solid surface involves the formation of bonds between reactant molecules and atoms of the surface of the catalyst (first-row transition metals utilize 3d and 4s electrons for bonding).

This has the effect of increasing the concentration of the reactants at the catalyst surface and also the weakening of the bonds in the reacting molecules (the activation energy is lowering).

Also because the transition metal ions can change their oxidation states, they become more effective as catalysts. For example, iron(III) catalyzes the reaction between iodide and persulphate ions.
Question 4
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A transition metal $$A$$ has spin only magnetic moment value of $$1.8\ B.M$$. When it is reacted with dilute $$H_2SO_4$$ in presence of air, its compound $$B$$ reacts with compound $$C$$ to give compound $$D$$ with liberation of iodine. Then the metal $$A$$, and compounds $$B, C$$ and $$D$$ are respectively:

A
$$Ti, TiSO_4, KI$$ and $$TiI_2$$

B
$$An, ZnSO_4, KI$$ and $$ZnI_2$$

C
$$Cu, CuSO_4, KI$$ and $$Cu_2I_2$$

D
$$Cu, CuSO_4, KI$$ and $$CuI_2$$

Solution
Question 5
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Wilkinson's catalyst is :

A
$$TiCl_4$$ and $$Al(C_2H_5)_3$$

B
$$[(Ph_3P)_3RhCl]$$

C
$$TiCl_4$$ and $$(C_6H_5)_3P$$

D
$$none\ of\ these$$

Solution
Question 6
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Among the following, the lowest degree of paramagnetism per mole of the compound will be shown by:

A
$$MnSO_4. 4H_2O$$

B
$$CuSO_4. 5H_2O$$

C
$$FeSO_4. 7H_2O$$

D
$$NiSO_4. 6H_2O$$

Solution
Question 7
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Arrange the following ions in their magnetic moment:
(i) $$V^{4+}$$
(ii) $$Mn^{4+}$$
(iii) $$Fe^{3+}$$
(iv) $$Ni^{2+}$$
[At. Nos. $$V=23, Mn=25, Fe=26, Ni=28$$]

A
$$(ii)>(iii)>(i)>(iv)$$

B
$$(iii)>(iv)>(ii)>(i)$$

C
$$(iii)>(ii)>(iv)>(i)$$

D
$$(i)<(iv)<(iii)<(ii)$$

Solution

Magnetic moment depends upon the number of unpaired electrons:

(i) $$V^{4+}\,(Z=23):[Ar]3d^1$$ $$1$$ unpaired electron

(ii) $$Mn^{4+}\,(Z=25):[Ar]3d^3$$ $$3$$ unpaired electron

(iii) $$Fe^{3+}\,(Z=26):[Ar]3d^5$$ $$5$$ unpaired electron

(iv) $$Ni^{2+}\,(Z=28):[Ar]3d^8$$ $$2$$ unpaired electron

Number of unpaired electrons are maximum in $$Fe^{3+}$$. Hence it shows maximum magnetic moment and $$V^{4+}$$ shows least magnetic moment because it has minimum number of unpaired electrons.

The order of magnetic moment is as: $$Fe^{3+}>Mn^{4+}>Ni^{2+}>V^{4+}$$

Hence correct answer is $$(iii)>(ii)>(iv)>(i)$$
Question 8
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In $$K_2Cr_2O_7$$, every $$Cr$$ is linked to:

A
two O- atoms

B
three O- atoms

C
four O- atoms

D
five O- atoms

Solution
Question 9
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Directions For Questions

Two types of magnetic behavior are found in substances :
(a) Diamagnetism and (b) Paramagnetism

Diamagnetic substances are those which are repelled by an applied magnetic field. Such substances have no unpaired electron. Paramagnetic substances are those which are attracted by an applied magnetic field. Transition metals and many of their compounds show paramagnetic behavior where there are unpaired electrons or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecules. The magnetic moment of $$n$$ unpaired electrons is given as,

$$\mu =\sqrt { n\left( n+2 \right) } $$ Bohr Magneton

Magnetic moment increases as the number of unpaired electrons increases.

...view full instructions

In $$3d$$ series, the maximum magnetic moment is shown by:

A
$$Sc (At\ no.\ 21)$$

B
$$V(23)$$

C
$$Cr(24)$$

D
$$Fe(26)$$
Question 10
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Match the List $$I$$ with List $$II$$ and List $$III$$
List $$I$$ List $$II$$ List $$III$$
a. Reduction i. Adam's catalyst 1. $$TiCl_4$$
b. Polythene production ii. Wacker process 2. $$Pt$$
c. Aldehyde manufacture iii. Natta catalyst 3. $$PbCl_2$$

A
$$a\to i \to 2$$

B
$$b\to ii \to 1$$

C
$$c\to iii\to 3$$

D
none

Solution

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List $$I$$	List $$II$$	List $$III$$
a. Reduction	i. Adam's catalyst	1. $$TiCl_4$$
b. Polythene production	ii. Wacker process	2. $$Pt$$
c. Aldehyde manufacture	iii. Natta catalyst	3. $$PbCl_2$$

The d- and f- Block Elements Test - 70

Result

The d- and f- Block Elements Test - 70

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SHARING IS CARING

Question 1

Aqueous solutions of $$Cu^+$$ and $$Zn^{2+}$$ are colourless

Aqueous solutions of $$Cu^{2+}$$ and $$Zn^{2+}$$ are colourless

Aqueous solutions of $$Fe^{3+}$$ is green in colour

Aqueous solutions of $$MnO_4^-$$ is colourless

Solution

Question 2

$$1$$ and $$2$$

$$1$$ and $$5$$

$$2$$ and $$4$$

$$3$$ and $$4$$

$$2$$ and $$5$$

Solution

Question 3

their chemical reactivity

their magnetic behaviour

their unfilled $$d-$$orbital

their ability to adopt multiple oxidation states and their complexing ability.

Solution

Question 4

$$Ti, TiSO_4, KI$$ and $$TiI_2$$

$$An, ZnSO_4, KI$$ and $$ZnI_2$$

$$Cu, CuSO_4, KI$$ and $$Cu_2I_2$$

$$Cu, CuSO_4, KI$$ and $$CuI_2$$

Solution

Question 5

$$TiCl_4$$ and $$Al(C_2H_5)_3$$

$$[(Ph_3P)_3RhCl]$$

$$TiCl_4$$ and $$(C_6H_5)_3P$$

$$none\ of\ these$$

Solution

Question 6

$$MnSO_4. 4H_2O$$

$$CuSO_4. 5H_2O$$

$$FeSO_4. 7H_2O$$

$$NiSO_4. 6H_2O$$

Solution

Question 7

$$(ii)>(iii)>(i)>(iv)$$

$$(iii)>(iv)>(ii)>(i)$$

$$(iii)>(ii)>(iv)>(i)$$

$$(i)<(iv)<(iii)<(ii)$$

Solution

Question 8

two O- atoms

three O- atoms

four O- atoms

five O- atoms

Solution

Question 9

$$Sc (At\ no.\ 21)$$

$$V(23)$$

$$Cr(24)$$

$$Fe(26)$$

Question 10

$$a\to i \to 2$$

$$b\to ii \to 1$$

$$c\to iii\to 3$$

none

Solution

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