Coordination Compounds Test

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Coordination Compounds Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

The properties of a compound are:

A
Similar to the properties of its constituents

B
Similar to the properties of one of the constituents

C
Different from the properties of its constituents

D
None of these

Solution

A compound is a substance formed when two or more chemical elements are chemically bonded together. The elements in any compound are always present in fixed ratios. Example: Pure methane is a compound made from two elements - carbon and hydrogen. The ration of hydrogen to carbon in methane is always 4:1. The properties of a compound are different from the properties of its constituents
Question 2
1 / -0

The ionizable valency of Ni in Ni(CO)$$_{4}$$ is __________.

A
2

B
4

C
0

D
1

Solution

Ionizable valency is the one which is associated with the net charge on complex sphere and since in this case it is zero so it has no ionizable valency.
Question 3
1 / -0

The brown complex obtained in the detection of nitrate radical is formulated as $$\displaystyle \left[ { Fe\left( { H }_{ 2 }O \right) }_{ 5 }NO \right] { SO }_{ 4 }$$. What is the oxidation number of $$\displaystyle Fe$$ in this complex?

A
+1

B
+2

C
+3

D
0

Solution

The brown colour complex obtained in the detection of nitrate radical is formulated as $$\displaystyle \left[ { Fe\left( { H }_{ 2 }O \right) }_{ 5 }NO \right] { SO }_{ 4 }$$. In this complex, oxidation state of iron is +1. The univalent character of iron in the complex is justified by the presence of a coordinated $$\displaystyle { NO }^{ + }$$ group.
Question 4
1 / -0

Orange is the complimentary colour of blue spectral colour.
If true 1 else 0.

A
1

Solution

Here, it can be seen that,
Question 5
1 / -0

According to Werner’s theory of valency, transition metals possess:

A
only one type of valency

B
two types of valencies

C
three types of valencies

D
four types of valencies

Solution

According to Werner’s theory of valence, transition metals has two valencies are primary valencies and secondary valency.

The primary valency relates to the oxidation state and the secondary valency relates to the coordination number or it is the number of ligands attached to metal ions.

Hence, the correct option is $$B$$
Question 6
1 / -0

Transition metals are coloured due to the following electronic transition

A
d - s

B
d - d

C
s - p

D
f - s

Solution

Transition metals are coloured due to the d-d electronic transition.
It's a transition where an electron jumps from one d orbital to another. Normally these are degenerate (the d orbitals have the same energy), but under some conditions, such as the presense of ligands, the degeneracy can be removed so that there is a specific energy (and therefore wavelength) associated with these transitions. These sorts of transitions sometimes have energies located in the visible band, and it's one reason transition metal ions (and complex ions in particular) tend to be highly colored.
Question 7
1 / -0

Which complex compound will give three isomers?

A
$$\left[ Fe(en)_{ 3 } \right] C{ l }_{ 3 }$$

B
$$\left[ Co(en)_{ 2 }C{ l }_{ 2 } \right] C{ l }$$

C
$$\left[ Fe(PP{ h }_{ 3 })_{ 3 }N{ H }_{ 3 }ClBr \right] C{ l }$$

D
$$\left[ Co(PP{ h }_{ 3 })_{ 3 }Cl \right] C{ { l }_{ 3 } }$$

Solution
Question 8
1 / -0

Hybridisation involves:

A
addition of an electron pair

B
combination and redistribution of atomic orbitals

C
removal of an electron pair

D
separation of orbitals

Solution

$$\bf{Hint:-}$$ Mixing of different energy orbitals to form new equal energy orbitals known as hybridization.

$$\bf{Explanation-}$$
$$\bullet$$ Hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals.

$$\bullet$$ Atomic orbitals with similar energy combine to give degenerated hybrid orbitals.

$$\bullet$$ The number of combining atomic orbitals is equal to the hybridised orbitals.

$$\bullet$$ They involve redistribution of electrons of combined atomic orbital to hybrid orbitals.

$$\bf{Conclusion-}$$ Hence, option $$B$$ is correct.
Question 9
1 / -0

Which of the following compounds will exhibit the highest magnetic moment?

A
(a)$$[Ti{(NH_3)}_6]^{3+} $$

B
(b)$$[Cr{(NH_3)}_6]^{3+} $$

C
(c)$$[Co{(NH_3)}_6]^{3+} $$

D
(d)$$[Zn{(NH_3)}_6]^{2+} $$

Solution
Question 10
1 / -0

The hybridization of Ag in a $$[Ag(N{ H }_{ 3 }{ ) }_{ 2 }{ ] }^{ (+) }$$ is:-

A
sp

B
$${ sp }^{ 2 }$$

C
$${ sp }^{ 3 }$$

D
$${ dsp }^{ 2 }$$

Solution

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Coordination Compounds Test - 12

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Coordination Compounds Test - 12

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Question 1

Similar to the properties of its constituents

Similar to the properties of one of the constituents

Different from the properties of its constituents

None of these

Solution

Question 2

2

4

0

1

Solution

Question 3

+1

+2

+3

0

Solution

Question 4

1

Solution

Question 5

only one type of valency

two types of valencies

three types of valencies

four types of valencies

Solution

Question 6

d - s

d - d

s - p

f - s

Solution

Question 7

$$\left[ Fe(en)_{ 3 } \right] C{ l }_{ 3 }$$

$$\left[ Co(en)_{ 2 }C{ l }_{ 2 } \right] C{ l }$$

$$\left[ Fe(PP{ h }_{ 3 })_{ 3 }N{ H }_{ 3 }ClBr \right] C{ l }$$

$$\left[ Co(PP{ h }_{ 3 })_{ 3 }Cl \right] C{ { l }_{ 3 } }$$

Solution

Question 8

addition of an electron pair

combination and redistribution of atomic orbitals

removal of an electron pair

separation of orbitals

Solution

Question 9

(a)$$[Ti{(NH_3)}_6]^{3+} $$

(b)$$[Cr{(NH_3)}_6]^{3+} $$

(c)$$[Co{(NH_3)}_6]^{3+} $$

(d)$$[Zn{(NH_3)}_6]^{2+} $$

Solution

Question 10

sp

$${ sp }^{ 2 }$$

$${ sp }^{ 3 }$$

$${ dsp }^{ 2 }$$

Solution

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