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Coordination Compounds Test - 18

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Coordination Compounds Test - 18
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  • Question 1
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    Directions For Questions

    The crystal field theory (C.F.T.) is now much more widely accepted than the valence bond theory. It assume that the attraction between the central metal and the ligands in a complex is purely electrostatic. According to C.F.T. ligands are treated as a point charge and crystal field splitting energy (CFSE) increases the thermodynamic stability of the complexes. Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally. For tetrahedral complexes, $$\Delta$$  is about 4/9 times to $$\Delta _{0}$$ (CFSE for octahedral complexes.) This energy lies in visible region and i.e. why electronic transition are responsible for colour.

    ...view full instructions

    $$\displaystyle Ti^{3+}\left ( aq \right )$$ is violet while $$\displaystyle Ti^{4+}\left ( aq \right )$$ is colourless because $$\displaystyle -$$
    Solution
    $$Ti^{+3}$$:  $$d^1$$ configuration have one unpaired d-electron so it is colourful but
    $$Ti^{+4}$$:  $$d^0$$ configuration have zero unpaired d-electron so it is colourless.
  • Question 2
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    The IUPAC nomenclature for the complex $$Na[PtBrCl(NO_{2})(NH_{3})]$$ is
    Solution
    The IUPAC name of the complex $$Na[PtBrCl(NO_2)(NH_3)]$$ is sodium amminebromochloronitro-N-platinate(II).
    The cation is sodium ion and the anion is the complex ion.
    The ligands present are ammine, bromo, chloro, and nitro-N. Here N represents that the nitro group coordinates through the N atom.
    The names of the ligands are written in the alphabetical order.
    The oxidation state of platinum is +2. The oxidation state is written in Roman numerals inside the parenthesis.
  • Question 3
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    Which of the following is considered to be an anticancer species ?
    Solution
    Cisplatin (CDDP) is a chemotherapy drug. It was the first member of a class of platinum-containing anti-cancer drugs, which now also includes carboplatin and oxaliplatin. 
    It is used to treat various types of cancers, including sarcomas, some carcinomas (e.g. small cell lung cancer, and ovarian cancer), lymphomas, bladder cancer, cervical cancer and germ cell tumors. It is used in combinations with bleomycin and vinblastine in testicular cancer.

  • Question 4
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    The IUPAC name of $$[PtCl(NH_2CH_3)(NH_3)_2]Cl$$ is :
    Solution
    The IUPAC name of $$[PtCl(NH_2CH_3)(NH_3)_2]Cl$$ is diamminechloro(methylamine)platinum(II)chloride.
    The ligands present are ammine, chloro and methyl amine. The ligands are named according to the alphabetical order.
    The prefix di indicates two.
    The oxidation state of platinum is +2. The oxidation state is written in roman numerals inside parenthesis.
  • Question 5
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    Type of isomerism exhibited by $$\displaystyle \left [ Cr\left ( NCS \right )\left ( NH_{3} \right )_{5} \right ]\left [ ZnCl_{4} \right ]$$ is :
    Solution
    As -NCS and -SCN are isomer, both acts as ligand here, so linkage isomer due to this.
    Also in this Cl and NCS can change coordinate sphere so coordination ismerism due to this.
  • Question 6
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    Which one of the following platinum complexes is used in cancer chemotherapy?
    Solution
    $$cis-[PtCl_2(NH_3)_2]$$ known as cis-platin.

    Cisplatin is a chemotherapy medication used to treat several cancers. These include testicular cancer, ovarian cancer, cervical cancer, breast cancer, bladder cancer, head and neck cancer, oesophagal cancer, lung cancer, mesothelioma, brain tumours and neuroblastoma. It is given by injection into a vein.

    Hence, the correct option is $$\text{A}$$
  • Question 7
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    Four one–litre flasks are separately filled with the gases hydrogen, helium, oxygen and ozone at the same room temperature and pressure. The ratio of total number of atoms of these gases present in the different flasks would be:
    Solution

    Hint: At the same temperature, pressure, and volume, each of the given gas will have an equal number of moles.

    Explanation:

    $$1\ mole\ H_2$$ molecule contains $$\rightarrow $$ $$2$$ moles of $$H$$ atoms.

    $$1\ mole\ He$$ molecule contains $$\rightarrow $$ $$1$$ mole of $$He$$ atoms.

    $$1\ mole\ O_2$$ molecule contains $$\rightarrow $$ $$2$$ moles of $$O$$ atoms.

    $$1\ mole\ O_3$$ molecule contains $$\rightarrow $$ $$3$$ moles of $$O$$ atoms.

    Since, number of moles of atoms is directly proportional to the number of atoms, ratio of number of atoms is $$2:1:2:3$$

    Final Answer:

    Therefore the ratio of total number of atoms of all the gases is $$2:1:2:3$$

    Hence, the correct answer is option $$C.$$

  • Question 8
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    Which kind of isomerism is exhibited by octahedral $$[Co(NH_3)_4Br_2]Cl$$?
    Solution
    The octahedral complex $$[Co(NH_3)_4Br_2]Cl$$ exhibits geometrical as well as ionization isomerism.
    The geometrical isomers are cis and trans isomers.
    The ionization isomers are $$[Co(NH_3)_4Br_2]Cl  and  [Co(NH_3)_4Cl]Br_2$$ .

  • Question 9
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    Coordination compounds have great importance in biological systems. In this context which of the following statements is incorrect?
    Solution
    Chlorophylls are green pigments in plants and contain magnesium.
    They are useful during photosynthesis to store energy in the form of glucose from carbon dioxide and water in presence of sunlight.
  • Question 10
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    The two compounds pentaamminesulphatocobalt (III) bromide and pentaamminesulphatocobalt (III) chloride represent :
    Solution
    Pentaamminesulphatocobalt (III) bromide is $$[Co(SO_4)(NH_3)_4]Br$$ and pentaamminesulphatocobalt (III) chloride is $$[Co(SO_4)(NH_3)_5]Cl$$.
    The two compounds pentaamminesulphatocobalt (III) bromide and pentaamminesulphatocobalt (III) chloride represent no isomerism.
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