Coordination Compounds Test

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Coordination Compounds Test - 22

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Weekly Quiz Competition

Question 1
1 / -0

In the complex $$CoCl_3\cdot 5NH_3$$, the number of ions satisfying primary and secondary valencies of cobalt(III) are:

A
3, 0

B
2, 1

C
1, 2

D
0, 3

Solution

Complex $$CoCl_3\cdot 5NH_3$$ has octahedral structure so atleast one $$Cl^-$$ ion satisfies primary valency of cobalt(III) and remaining chloride ions satisfies secondary valency.
Question 2
1 / -0

Which element is not present in chlorophyll?

A
Carbon

B
Calcium

C
Magnesium

D
Hydrogen

Solution

In chlorophyll the central ion is magnesium, and the large organic molecule is a porphyrin. The porphyrin contains four nitrogen atoms that form bonds to magnesium in a square planar arrangement. There are several forms of chlorophyll.
So, an element not present in chlorophyll is calcium.
So, the correct answer is option B.
Question 3
1 / -0

In the electronic configurations of elements A and B are $$1s^2, 2s^2 2p^6, 3s^1$$ and $$1s^2, 2s^2, 2p^6, 3s^2, 3p^4$$ respectively, then the formula of the compound formed by the combination of these elements will be

A
$$AB$$

B
$$AB_3$$

C
$$AB_2$$

D
$$A_2B$$

Solution

Electronic configuration of A is $$1S^2 2s^22p^6 3s^1$$
Electronic configuration of B is $$1S^2 2s^22p^6 3s^23p^4$$
Valency of A =1
Valency of B $$= 8 -6 = 2$$
$$\therefore The compound formed by A & B is
Question 4
1 / -0

Use the figure below to answer the question that follows.
For which of the molecules in the figure does the central atom, or atoms, have $$sp^{2}$$ hybridization?

A
III only

B
IV only

C
III and IV only

D
II and IV only

Solution

$$N$$ in $$NO_2^-$$ is having $$sp^2$$ hybridization.
As hybridization =
$$\cfrac{1}{2}$$[number of valence electrons in central atom - number of monovalent atom attached - cationic charge + anionic charge]
= $$\cfrac{1}{2}[5+1] = 3 = sp^2$$
Question 5
1 / -0

The complex ion having minimum magnitude of $${ \Delta }_{ 0 }(CFSE)$$ is :

A
$${ \left[ Cr{ \left( CN \right) }_{ 6 } \right] }^{ 3- }$$

B
$${ \left[ Co{ \left( { NH }_{ 3 } \right) }_{ 6 } \right] }^{ 3+ }$$

C
$${ \left[ Co{ \left( Cl \right) }_{ 6 } \right] }^{ 3- }$$

D
$${ \left[ Cr{ \left( { H }_{ 2 }{ O } \right) }_{ 6 } \right] }^{ 3+ }$$

Solution

As $$Cl^-$$ is a weak field ligand so the complex formed with $$Cl^-$$ as ligand will have minimum $$\Delta_o (CFSE)$$.
Question 6
1 / -0

What is the correct name of $$I{F}_{7}$$?

A
Iron heptafluoride

B
Iodine heptafluoride

C
Iodine septafluoride

D
Iron (IV) septafluoride

Solution

Iodine heptafluoride, also known as iodine(VII) fluoride or iodine fluoride, is an interhalogen compound with the chemical formula $$IF_7$$. It has an unusual pentagonal bipyramidal structure.
Question 7
1 / -0

Select the correct IUPAC name for $$[FeF_4(OH_2)_2]{^-}$$.

A
Diaquatetrafluoroiron(III) ion

B
Diaquatetrafluoroferrate(III) ion

C
Diaquatetrafluoroiron(I) ion

D
Diaquatetrafluoroferrate(I) ion

Solution

In $$[FeF_4(OH_2)_2]^-$$ the oxidation state of iron is $$+3$$ so correct IUPAC name is diaquatetrafluoroferrate(III) ion.
Question 8
1 / -0

In C-C bond is $$C_2H_6$$ undergoes heterolytic fission, the hybridisation of two resulting carbon atoms is/are :

A
$$sp^2$$ both

B
$$sp^3$$ both

C
$$sp^2,sp^3 $$

D
$$sp,sp^2$$

Solution

$${ H }_{ 3 }C-{ CH }_{ 3 }\quad \underrightarrow { heterolytic } \quad \underbrace { { CH }_{ 3 }^{ + } } \quad \underbrace { { CH }_{ 3 }^{ - } } $$
$${ SP }^{ 2 }$$ $${ SP }^{ 3 }$$
Question 9
1 / -0

The formula for lithium iodotris(trifluorophosphine)nickelate(0) is:

A
$$Li[Ni(PF_3)_3]$$

B
$$Li[Ni(PF_3)_3I_3]$$

C
$$Li[(PF)_3I_3]$$

D
none of these

Solution

Trifluorophosphine is $$PF_3$$
The formula should be $$Li[Ni(PF_3)_3I]$$.
Question 10
1 / -0

Among the following coordination compounds, the one giving a white precipitate with $$BaCl_2$$ solution is:

A
$$[Cr(H_2O)_5 Br]SO_4$$

B
$$[Cr(H_2O)_5 SCN]$$

C
$$[Co(NH_3)_5 SO_4]Br$$

D
$$[Pt(NH_3)_6]Cl_4$$

Solution

Among the following coordination compounds, the one giving a white precipitate with $$\displaystyle BaCl_2$$ solution is $$\displaystyle [Cr(H_2O)_5 Br]SO_4$$.

It dissociates in aqueous solution to give sulphate ions. Sulphate ions react with barium chloride to form a white precipitate of barium sulphate.

$$\displaystyle [Cr(H_2O)_5 Br]SO_4 \rightarrow [Cr(H_2O)_5 Br]^{2+} + SO_4^{2-}$$

$$\displaystyle SO_4^{2-} + BaCl_2 \rightarrow BaSO_4 \downarrow + 2Cl^-$$

Hence, option $$A$$ is correct.

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Coordination Compounds Test - 22

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Coordination Compounds Test - 22

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Question 1

3, 0

2, 1

1, 2

0, 3

Solution

Question 2

Carbon

Calcium

Magnesium

Hydrogen

Solution

Question 3

$$AB$$

$$AB_3$$

$$AB_2$$

$$A_2B$$

Solution

Question 4

III only

IV only

III and IV only

II and IV only

Solution

Question 5

$${ \left[ Cr{ \left( CN \right) }_{ 6 } \right] }^{ 3- }$$

$${ \left[ Co{ \left( { NH }_{ 3 } \right) }_{ 6 } \right] }^{ 3+ }$$

$${ \left[ Co{ \left( Cl \right) }_{ 6 } \right] }^{ 3- }$$

$${ \left[ Cr{ \left( { H }_{ 2 }{ O } \right) }_{ 6 } \right] }^{ 3+ }$$

Solution

Question 6

Iron heptafluoride

Iodine heptafluoride

Iodine septafluoride

Iron (IV) septafluoride

Solution

Question 7

Diaquatetrafluoroiron(III) ion

Diaquatetrafluoroferrate(III) ion

Diaquatetrafluoroiron(I) ion

Diaquatetrafluoroferrate(I) ion

Solution

Question 8

$$sp^2$$ both

$$sp^3$$ both

$$sp^2,sp^3 $$

$$sp,sp^2$$

Solution

Question 9

$$Li[Ni(PF_3)_3]$$

$$Li[Ni(PF_3)_3I_3]$$

$$Li[(PF)_3I_3]$$

none of these

Solution

Question 10

$$[Cr(H_2O)_5 Br]SO_4$$

$$[Cr(H_2O)_5 SCN]$$

$$[Co(NH_3)_5 SO_4]Br$$

$$[Pt(NH_3)_6]Cl_4$$

Solution

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