Coordination Compounds Test

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Coordination Compounds Test - 27

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following compounds would exhibit co-ordination isomerism?

A
$$[Cr(H_2O)_5]Cl_2$$

B
$$[Cr(NH_3)_5][Co(CN)_5]$$

C
$$[Cr(en)_2]NO_2$$

D
$$[Ni(NH_3)_5][BF_4]_3$$

Solution

Co-ordination isomerism is a form of structural isomerism in which the composition of the complexion varies. In a coordination isomer, the total ratio ligand to metal remains the same, but the ligand attached to specific metal ion change. In B option ratio of metal to the ligand is the same and they can exchange their ligands ($$NH_3, CN)$$.
Question 2
1 / -0

Several octahedral complexes are possible from combinations of $$Co^{3+}, Cl^{-}$$ and $$NH_{3}$$. Primary valence do not have chloride ion. The correct statement(s) regarding the octahedral coordination entities having the formula .$$[Co(NH_{3})_{n}Cl_{6 - n}]^{(n - 3)+}$$ with $$n\geq 3$$, is/ are_____________.

A
At most six octahedral complexes are possible

B
One of the complexes is homoleptic

C
All the complexes are paramagnetic

D
Some of the complexes dissociate in water to give $$Co^{3+}$$ and $$Cl^{-}$$ ions

Solution

$$[Co(NH_3)_nCl_{6-n}]^{(n-3)^+}$$ $$n\ge 3$$
For $$n=3,n=4,n=5,n=6$$
For $$n=6\Rightarrow [Co(NH_3)_6]^{3+}=$$ is homoleptic due to all 6 same ligands. $$Co^{3+} \Rightarrow [Ar]3d^6$$ with strong field ligand, it is diamagnetic.
For $$n=5\Rightarrow [Co(NH_3)_5Cl]^{2+}.$$ $$Co^{2+} \Rightarrow [Ar]3d^7$$ with strong field ligand, it is paramagnetic.
For $$n=4\Rightarrow [Co(NH_3)_4Cl_2]^+$$. $$Co^{+} \Rightarrow [Ar]3d^8$$ with strong field ligand, it is paramagnetic.
For $$n=3\Rightarrow [Co(NH_3)_3Cl_3]$$. $$Co \Rightarrow [Ar]4s^23d^7$$ with strong field ligand, it is paramagnetic.
Only $$4$$ octahedral complex are possible.
One of them is homoleptic.
All the complexes are not paramagnetic.
No complex carries $$Co^{3+}$$ and $$Cl^-$$ both.
Option B is only correct.
Question 3
1 / -0

Which among the following forms octahedral complex?

A
$$d^{4}$$ (low spin)

B
$$d^{8}$$ (high spin)

C
$$d^{6}$$ (low spin)

D
All of these

Solution

writing the respective configurations
Hence, all can form octahedral complexes.
Question 4
1 / -0

Compound $$[Co{(CN)}_{2}{(en)}_{2}]Cl$$ can show:

A
only optical isomerism

B
only geometrical and optical isomerism

C
only structural isomerism

D
structural, geometrical and optical isomerism

Solution

Complex having $$[m(AA)_2B_2]$$ can show cis-trans and when it exits in Cis-, it shows optical isomerism also.
Question 5
1 / -0

Which of the following will give maximum number of isomer?

A
$${ \left[ Co{ \left( py \right) }_{ 3 }{ \left( { NH }_{ 3 } \right) }_{ 3 } \right] }^{ 3+ }$$

B
$${ \left[ Ni(en){ \left( { NH }_{ 3 } \right) }_{ 4 } \right] }^{ 2+ }$$

C
$${ \left[ Fe{ \left( { C }_{ 2 }{ O }_{ 4 } \right) }_{ }{ \left( en \right) }_{ 2 } \right] }^{ 2- }$$

D
$${ \left[ Co{ \left( { NO }_{ 2 } \right) }_{ 2 }{ \left( { NH }_{ 3 } \right) }_{ 4 } \right] }^{ + }$$

Solution

$$[Co(NO_2)_2(NH_3)_4]^+$$ shows the following isomerism:
1) Linkage isomerism through oxygen $$[-ONO]$$ and nitrogen $$[-NO_{2}]$$.
2) Geometrical isomerism: 2 cis isomers and 1 trans isomer
$$[Ni(en)(NH_{3})_{4}]^{2+}$$ and $$[Fe(C_{2}O_{4})(en)_{2}]^{2-}$$ will show optical isomerism. But total isomers are 4. But it has 5 isomerism.
Question 6
1 / -0

Indicate the types of isomerism exhibited by the following complexes and draw the structures for these isomers:

A
$$K\left[ Cr({ H }_{ 2 }{ O })_{ 2 }({ C }_{ 2 }{ O }_{ 4 })_{ 2 } \right]$$

B
$$\left[ Co({ en }{ ) }_{ 3 } \right] { Cl }_{ 3 }$$

C
$$\left[ Co({ NH }_{ 3 }{ ) }_{ 5 }\left( { NO }_{ 2 } \right) \right] ({ NO_{ 3 }) }_{ 2 }$$

D
$$\left[ Pt({ NH }_{ 3 })({ H }_{ 2 }{ O }){ Cl }_{ 2 } \right]$$

Solution

$$A$$ - exhibits cis trans.
$$B$$- Exhibits optical Isomerism.
$$C$$- Exhibits linkage Isomerism $$(NO_2,-ONO)$$
$$D$$- Cis-Trans Isomerism.
Question 7
1 / -0

If the value of C.F.S.E. for "Ni" is $$\Delta_0$$ then it is for Pd should be ?

A
$$1.1\, \Delta_0$$

B
$$0.5\, \Delta_0$$

C
$$1.5\, \Delta_0$$

D
none of the above

Solution

Ongoing from $$3d$$ to $$4d$$ series C.F.S.E increases by $$50\%$$
Now, for $$Ni$$ CFSE $$=\triangle_o$$
$$\Rightarrow$$ For $$P_t=\triangle _o+\cfrac{50}{100}\triangle_o$$
$$=1.5\triangle_o$$
Question 8
1 / -0

Which one of the following complexes has largest value of $$\Delta_{0}$$?

A
$$[Cr(H_{2}O)_{6}]^{+2}$$

B
$$[Cr(H_{2}O)_{6}]^{+3}$$

C
$$[Mn(H_{2}O)_{6}]^{+2}$$

D
$$[Mn(H_{2}O)_{6}]^{+3}$$

Solution

The value of $$\triangle_o$$ increases with increase in oxidation state of central metal, since maximum charges causes more left and hence orbital contracts lead to more $$CFSE(\triangle _o)$$
$$cr^{3+}\rightarrow t_{2g}^3eg^{o}\rightarrow CFSE=|-6/5|\triangle _o$$
$$Mn^{3+}\rightarrow d^{4}\rightarrow t_2g^3eg^1\rightarrow CFSE=-6/5\triangle_o+3/5\triangle_o=|-3/5|\triangle_o$$
$$\therefore \triangle_o=cr^{3+}>Mn^{3+}$$
Question 9
1 / -0

According to Werner's theory of coordination compounds:

A
primary valency is ionisable

B
secondary valency is ionisable

C
primary and secondary valencies are ionisable

D
neither primary nor secondary valency is ionisable

Solution

Primary valency is ionisable according to Werner's theory of coordination compounds.
According to Werner's coordination theory, there are two kinds of valency, primary and secondary. The primary valency of a central metal ion is satisfied with anions.
For example, in $$[Cu(NH_3)_4]SO_4$$ primary valency is 2 and secondary valency is 4.
Secondary valence refers to coordination number. Since copper is coordinated to 4 ammonia ligands, secondary valence is 4. Primary valence is satisfied by anions. Since sulphate ion has $$-2$$ charge, primary valence is 2.
Question 10
1 / -0

What is the oxidation number of gold in the complex $$[AuCl_4]^{1-}$$?

A
$$+4$$

B
$$+3$$

C
$$+2$$

D
$$+1$$

Solution

Oxidation state of chlorine $$Cl$$ is $$-1$$.
Let the oxidation number of gold $$Au$$ be $$x$$.
$$\therefore$$ $$x + 4\times (-1) = -1$$
$$\implies \ x = +3$$
Thus oxidation number of gold is $$+3$$.
Correct answer is option B.

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Re-Attempt Weekly Quiz Competition

Coordination Compounds Test - 27

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Coordination Compounds Test - 27

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Question 1

$$[Cr(H_2O)_5]Cl_2$$

$$[Cr(NH_3)_5][Co(CN)_5]$$

$$[Cr(en)_2]NO_2$$

$$[Ni(NH_3)_5][BF_4]_3$$

Solution

Question 2

At most six octahedral complexes are possible

One of the complexes is homoleptic

All the complexes are paramagnetic

Some of the complexes dissociate in water to give $$Co^{3+}$$ and $$Cl^{-}$$ ions

Solution

Question 3

$$d^{4}$$ (low spin)

$$d^{8}$$ (high spin)

$$d^{6}$$ (low spin)

All of these

Solution

Question 4

only optical isomerism

only geometrical and optical isomerism

only structural isomerism

structural, geometrical and optical isomerism

Solution

Question 5

$${ \left[ Co{ \left( py \right) }_{ 3 }{ \left( { NH }_{ 3 } \right) }_{ 3 } \right] }^{ 3+ }$$

$${ \left[ Ni(en){ \left( { NH }_{ 3 } \right) }_{ 4 } \right] }^{ 2+ }$$

$${ \left[ Fe{ \left( { C }_{ 2 }{ O }_{ 4 } \right) }_{ }{ \left( en \right) }_{ 2 } \right] }^{ 2- }$$

$${ \left[ Co{ \left( { NO }_{ 2 } \right) }_{ 2 }{ \left( { NH }_{ 3 } \right) }_{ 4 } \right] }^{ + }$$

Solution

Question 6

$$K\left[ Cr({ H }_{ 2 }{ O })_{ 2 }({ C }_{ 2 }{ O }_{ 4 })_{ 2 } \right]$$

$$\left[ Co({ en }{ ) }_{ 3 } \right] { Cl }_{ 3 }$$

$$\left[ Co({ NH }_{ 3 }{ ) }_{ 5 }\left( { NO }_{ 2 } \right) \right] ({ NO_{ 3 }) }_{ 2 }$$

$$\left[ Pt({ NH }_{ 3 })({ H }_{ 2 }{ O }){ Cl }_{ 2 } \right]$$

Solution

Question 7

$$1.1\, \Delta_0$$

$$0.5\, \Delta_0$$

$$1.5\, \Delta_0$$

none of the above

Solution

Question 8

$$[Cr(H_{2}O)_{6}]^{+2}$$

$$[Cr(H_{2}O)_{6}]^{+3}$$

$$[Mn(H_{2}O)_{6}]^{+2}$$

$$[Mn(H_{2}O)_{6}]^{+3}$$

Solution

Question 9

primary valency is ionisable

secondary valency is ionisable

primary and secondary valencies are ionisable

neither primary nor secondary valency is ionisable

Solution

Question 10

$$+4$$

$$+3$$

$$+2$$

$$+1$$

Solution

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