Coordination Compounds Test

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Coordination Compounds Test - 29

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Weekly Quiz Competition

Question 1
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Two isomers of a compound $$[Co(NH_3)_3Cl_3]$$ $$(MA_3B_3\,$$ type) are shown in the figures. The isomers can be classified as:

A
(i) fac-isomers (ii) mer-isomer

B
(i) optical-isomer (ii) trans-isomer

C
(i) mer-isomer (ii) fac-isomer

D
(i) trans-isomer (ii) cis-isomer.

Solution

In fac-isomer, three $$Cl$$ atoms are present on one face of the octahedron. Similarly, 3 ammonia molecules are present on one face of the octahedron. All 3 same ligands have $$90^{o}$$ bond angle between them.

In mer-isomer, there is a $$90^{o};90^{o};180^{o}$$ bond angle between three same ligands.
Question 2
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Which of the following complexes exists as pair of enantiomers?

A
$$[Co(NH_3)_4Cl_2]^+$$

B
$$[Cr(en)_3]^{3+}$$

C
$$[Co(P(C_2H_5)_3)_2ClBr]$$

D
$$trans- [Co(en)_2Cl_2]^+$$

Solution

Optical isomerism is common in octahedral complexes of the formula $$[Ma_2b_2c_2], \, [M(AA)_3],$$ etc.$$[Cr(en)_3]^{3+}$$ is octahedral complex of the formula $$ [M(AA)_3].$$ It shows optical isomerism and exists as a pair of enantiomers. Enantiomers are non superimposable mirror images of each other.
$$[Co(NH_3)_4Cl_2]^+$$, $$[Co(P(C_2H_5)_3)_2ClBr]$$ and $$trans- [Co(en)_2Cl_2]^+$$ are optically inactive.
Question 3
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The correct labeling of different terms used in coordination compounds is:

A
(i) Central atom, (ii) Ionisation sphere, (iii) Coordination number, (iv) Ligands

B
(i) Ligands, (ii) Coordination number, (iii) Valency, (iv) Ionisation sphere

C
(i) Ionisation sphere, (ii) Ligands, (iii) Coordination number, (iv) Central atom

D
(i) Ligands, (ii) Ionisation sphere, (iii) Coordination number, (iv) Central atom

Solution

Ammonia is a ligand. It donates lone pair of electrons to Cobalt (central metal atom) and forms co-ordinate bond.

Co-ordination number is 6 as 6 ammonia ligand coordinate to central metal.

(ii) represents ionisation sphere ,$$[Co(NH_3)_6]$$ has $$+3$$ charge.

Hence ,option D is correct.
Question 4
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The hybridisation involved in $$[Co(C_2O_4)_3]^{3-}$$ is ?

A
$$ sp^3d^2$$

B
$$ sp^3d^3$$

C
$$dsp^3$$

D
$$d^2sp^3$$

Solution

$$[Co(C_2O_4)_3]^{3-}=CO^{3+}=[Ar]3d^6=$$ Refer to image 01
$$C_2O_4^{2-}=$$ Strong field ligand.
$$=d^2sp^3$$ Hybridisation.
$$=$$ Octahedral.
$$(C_2O_4)^{-2}=$$Bidentate Ligand
Question 5
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$$CrCl_3.6H_2O$$ exists in different isomeric forms which show different colours like violet and green. This is due to:

A
ionisation isomerism

B
coordination isomerism

C
optical isomerism

D
hydrate isomerism.

Solution

Water molecules are exchanged inside and outside coordination sphere. The number of water molecules is different inside and outside the coordination sphere. These are called hydrate isomers.
(i) $$[Cr(H_2O)_6]Cl_3$$ has six water molecules inside the coordination sphere and zero water molecules outside the coordination sphere. It is violet in colour.
(ii) $$[Cr(H_2O)_5Cl]Cl_2.H_2O$$ has five water molecules inside the coordination sphere and one water molecules outside the coordination sphere. It has a blue-green colour.
(iii) $$[Cr(H_2O)_4Cl_2]Cl.2H_2O$$ has four water molecules inside the coordination sphere and two water molecules outside the coordination sphere. it has a green colour.
Question 6
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Which of the following shows maximum number of isomers?

A
$$[Co(NH_3)_4Cl_2]$$

B
$$[Ni(en)(NH_3)_4]^{2+}$$

C
$$[Ni(C_2O_4)(en)_2]^{2-}$$

D
$$[Cr(SCN)_2(NH_3)_4]^+$$

Solution

$$[Cr(SCN)_2(NH_3)_4]^+$$ shows maximum number of isomers. It shows geometrical (cis trans) isomerism as well as linkage isomerism. $$SCN^-$$ is ambidentate ligand and can coordinate through either S or N atom.
Question 7
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$$[Pt(NH_3)_4][CuCl_4]$$ and $$[Cu(NH_3)_4][PtCl_4]$$ are known as:

A
ionisation isomers

B
coordination isomers

C
linkage isomers

D
polymerisation isomers.

Solution

Different complex ions have the same molecular formula. Ligands are interchanged between the complex cation and complex anion. These type of complexes are called coordination isomers.
In $$[Pt(NH_3)_4][CuCl_4]$$, ammonia ligands are attached to $$Pt$$ metal and chloride ligands are attached to $$Cu$$ metal.
In $$[Cu(NH_3)_4][PtCl_4]$$, ammonia ligands are attached to $$Cu$$ metal and chloride ligands are attached to $$Pt$$ metal.
Question 8
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Which of the following sets of examples and geometry of the compounds is not correct?

A
Octahedral - $$[Co(NH_3)_6]^{3+}, [Fe(CN)_6]^{3-}$$

B
Square planar - $$[Ni(CN)_4]^{2-}, [Cu(NH_3)_4]^{2+}$$

C
Tetrahedral- $$[Ni(CO)_4], [ZnCl_4]^{2-}$$

D
Trigonal bipyramidal - $$[Fe(NH_3)_6]^{2+}, [CuCl_4]^{2-}$$

Solution

$$[Fe(NH_3)_6]^{2+}=Fe^{2+}=[Ar]3d^6=$$ Octahedral.
Hybridisation is $$=sp^3d^2$$ .

$$[CuCl_4]^{2+}=Cu^{2+}=[Cu]3d^{9}=$$ Tetrahedral.
Hybridisation $$=$$ $$sp^3$$

These two do not have trigonal bipyramidal geometry.
Question 9
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The synthetic steroid ethynylestardiol (1) is a compound used in the birth control pill. How many $$sp^3$$ hybridised carbon atoms are present in compound (1) ?

A
8

B
9

C
10

D
11

E
12

Solution

$$sp^3$$ hybridised carbon are those carbon having $$4$$ single bond with $$4$$ different groups.
(Refer to Image)
There are $$12$$ $$sp^3$$ hybridised carbon atoms.
Question 10
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The synthetic steroid ethynylestardiol (1) is a compuond used in the birth control pill. How many $$sp^2$$ hybridised carbon atoms are present in compound (1)?

A
4

B
5

C
6

D
7

E
8

Solution

$$sp^2$$ hybridised carbon are those carbon which form double bond
(Refer to Image)
There re $$6$$ $$sp^2$$ hybridised carbon.