Coordination Compounds Test

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Coordination Compounds Test - 37

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Weekly Quiz Competition

Question 1

1 / -0

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, $$38.71\%$$ and H, $$9.67\%$$. The empirical formula of the compound would be?

$$CH_4O$$

$$CH_3O$$

$$CH_2O$$

$$CHO$$

Solution

The empirical formula is to be calculated as:

Element	% Composition	Atomic Mass	Mole Ratio	Simple Ratio
C	38.71	12	$$ \dfrac{38.71}{12} = 3.22 $$	$$ \dfrac{3.22}{3.22} = 1 $$
H	9.67	1	$$ \dfrac{9.67}{1} = 9.67 $$	$$ \dfrac{9.67}{3.22} = 3 $$
O	100-(38.71+9.67) =51.62	16	$$ \dfrac{51.62}{16} = 3.22 $$	$$ \dfrac{3.22}{3.22} = 1 $$

Hence the empirical formula of the compound is $$ CH_{3}O $$

Question 2
1 / -0

The highest value of the calculated spin only magnetic moment (in BM) among all the transition metal complexes is:

A
$$ 5.92$$

B
$$ 3.87$$

C
$$6.93$$

D
$$ 4.90$$

Solution

$$\mu=\sqrt{n(n+2)}$$ BM

$$n=$$ Number of unpaired electrons

$$n=$$ Maximum number of unpaired electron $$=5$$

$$\mu=5.92BM$$

$$EX: Mn^{2+}$$ complex.

Hence option A is correct.
Question 3
1 / -0

The secondary valency of chromium in $$[Cr(en)_3]Cl_3$$ is:

A
$$6$$

B
$$3$$

C
$$2$$

D
$$4$$
Question 4
1 / -0

The complex having the molecular composition $$[CO(NO_{2})(SCN)(en)_{2}]Br$$ exhibits

A
linkage isomerism

B
ionisation isomerism

C
cis-trans isomerism

D
all of these
Question 5
1 / -0

The primary valency of the central transition metal ion in the complex compound $$[Cr(NH_3)_4Cl_2]Cl$$ is:

A
$$3$$

B
$$2$$

C
$$1$$

D
$$0$$
Question 6
1 / -0

The valency of carbon is four. On what principle it can be explained in a better way?

A
Resonance

B
Hybridization

C
Electron transfer

D
None of the above

Solution

Carbon has only two unpaired electrons by its configuration but hybridization is a concept by which we can explaning its valency 4.
Question 7
1 / -0

The units of solubility product of silver chromate $$(Ag_2CrO_4)$$ will be __________.

A
$$mol^2L^{-2}$$

B
$$mol^3L^{-3}$$

C
$$mol L^{-1}$$

D
$$mol L^{-2}$$

Solution

Molar solubility is the number of moles of a substance (the solute) that can be dissolved per liter of solution before the solution becomes saturated. It can be calculated from a substance's solubility product constant (K_sp) and stoichiometry. The units are mol/L, sometimes written as M.
Question 8
1 / -0

The hybridisation of $$S$$ in $$SF_6$$ molecule is

A
$$sp^3$$

B
$$sp^3d^2$$

C
$$sp^3d$$

D
None

Solution

Sulphur forms $$6$$ bond pairs. It thus needs $$6$$ hybrid orbitals and therefore, hybridization is $$sp^3d^2$$this molecule has octahedral structure.
Question 9
1 / -0

What is the proportion of sigma $$(\sigma)$$, and pi $$(\pi)$$ bond in $$1, 4- Benzoquinone$$?

A
$$1 : 3$$

B
$$3 :2$$

C
$$2 : 1$$

D
$$2 : 3$$

Solution
Question 10
1 / -0

The unpaired electrons in $$[Ni(CO)_4]$$ are:

A
zero

B
one

C
three

D
four

Solution

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Re-Attempt Weekly Quiz Competition

Coordination Compounds Test - 37

Result

Coordination Compounds Test - 37

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SHARING IS CARING

Question 1

$$CH_4O$$

$$CH_3O$$

$$CH_2O$$

$$CHO$$

Solution

Question 2

$$ 5.92$$

$$ 3.87$$

$$6.93$$

$$ 4.90$$

Solution

Question 3

$$6$$

$$3$$

$$2$$

$$4$$

Question 4

linkage isomerism

ionisation isomerism

cis-trans isomerism

all of these

Question 5

$$3$$

$$2$$

$$1$$

$$0$$

Question 6

Resonance

Hybridization

Electron transfer

None of the above

Solution

Question 7

$$mol^2L^{-2}$$

$$mol^3L^{-3}$$

$$mol L^{-1}$$

$$mol L^{-2}$$

Solution

Question 8

$$sp^3$$

$$sp^3d^2$$

$$sp^3d$$

None

Solution

Question 9

$$1 : 3$$

$$3 :2$$

$$2 : 1$$

$$2 : 3$$

Solution

Question 10

zero

one

three

four

Solution

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