Coordination Compounds Test

Result

Coordination Compounds Test - 43

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Weekly Quiz Competition

Question 1
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Haemoglobin is

A
An enzyme

B
A globular protein

C
A vitamin

D
A carbohydrate

Solution

Haemoglobin is a globular protein.
Question 2
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Chlorophyll contains

A
Fe

B
Na

C
Mg

D
Zn

Solution

$$\text{Chlorophyll has magnesium as its central metal ion,}$$ and the large organic molecule to which it bonds is known as a $$porphyrin.$$
Question 3
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The valency of cuprammonium ion is

A
$$+4$$

B
$$+2$$

C
$$-2$$

D
$$-4$$

Solution

Cuprammonium ion is$$[Cu(NH_3)_4]^{2+}$$. So, copper has $$+2$$ valency.
Question 4
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Number of unhybridised orbitals in vinyl acetylene are

A
$$2$$

B
$$3$$

C
$$4$$

D
$$6$$

Solution

Number of unhybridised orbitals in vinyl acetylene is 6 as unhybridised orbitals are used in $$\pi-$$bonding.
Question 5
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The compound $$[Cr(H_{2}O)_{6}]Cl_{3}, [Cr(H_{2}O)_{5}Cl] Cl_{2} . H_{2}O$$ and $$[Cr(H_{2}O)_{4}Cl_{2}]Cl.2H_{2}O$$ exhibits:

A
Linkage isomerism

B
Geometrical isomerism

C
Ionization isomerism

D
Hydrate isomerism

Solution
Question 6
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Choose the correct statement regarding $$SeOCI_2$$ molecule :

A
It does not contain plane of symmetry

B
$$'Cl \hat{Se} Cl'$$ bond angle is greater than $$Cl \hat{Se} O'$$ bond angle

C
Lone pair has greater than $$33.3 \%$$ s-character

D
Central atom used one d-orbital in bonding

Solution

The structure of $$SeOCl_2$$ is as follows :

Thus is does have plane of symmetry.
Question 7
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Which among the following molecules is not perfect flat?

A
$$B_3N_3H_6$$

B
$$C_3N_3(NH_2)_3$$

C
$$SO_3$$

D
$$C_3N_3(N_3)_3$$

Solution

Option B is the answer. Its having $$N=N=N$$ structure which makes it to lie in different plane. That is with respect to the base plane $$N=N=N$$ lies perpendicular.
Question 8
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The compounds $$ [Co(So_4)(NH_3)_5]Br $$ and $$ [Co(SO_4)(NH_3)_5]Cl $$ represent

A
Linkage isomerism

B
Ionisation isomersim

C
coordination isomerism

D
no isomerism

Solution

Isomers means having same molecular but different structural formula but in the above question the molecular formula is different. Hence they are not isomers.
Question 9
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Directions For Questions

The concept of redistribution of energy in different orbitals of an atom associated with different energies to give new orbitals of equal (or sometimes it may be non-equal) energy oriented in space in definite directions is called hybridisation and formed new orbitals are called hybrid orbitals. The bonds formed by such orbitals are called hybrid bonds. The process of mixing of orbitals itself requires some energy. Thus, some additional energy, is needed for the hybridisation (mixing) of atomic orbitals.

...view full instructions

Which of the following statement is correct ?

A
In $$BrF_3$$, maximum three halogen atoms can lie in same plane

B
In $$CH_2SF_2(CH_3)_2$$ molecule all hydrogen atoms which bonded to $$s - sp^2$$ overlapping, lie in equatorial plane

C
In $$OSCl_4$$, Cl - S - Cl equatorial bond angle is greater than $$120^0$$

D
Molecules$$IOF_5$$ and $$XeO_2F_4$$ have similar shape but have different number of lone pairs in whole molecule

Solution
Question 10
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Which of the following isomerism, exhibited by $$[CrCl_{2}(OH)_{2}(NH_{3})_{2}]^{-}$$?

A
Ionization

B
Geometrical

C
Hydrate

D
Linkage

Solution

$$[CrCl_2(OH)_2(NH_3)_2]−$$ exhibits geometrical isomerism. The geometrical isomers are cis and trans isomers. Cis isomer is optically active.