Coordination Compounds Test

Directions For Questions

The crystal field theory (C.F.T.) is now much more widely accepted than the valence bond theory. It assume that the attraction between the central metal and the ligands in a complex is purely electrostatic. According to C.F.T. ligands are treated as a point charge and crystal field splitting energy (CFSE) increases the thermodynamic stability of the complexes. Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally. For tetrahedral complexes, $$\Delta$$ is about 4/9 times to $$\Delta _{0}$$ (CFSE for octahedral complexes.) This energy lies in visible region and i.e. why electronic transition are responsible for colour.

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In an octahedral crystal field, the $$d-$$electrons of a metal ion occupy the $$\displaystyle e_{g}$$ set of orbitals before they occupy the $$\displaystyle t_{2g}$$ set of orbitals.

List I	List II
(I) $$[FeF_{6}]^{3-}$$	(A) $$1.73\ BM$$
(II) $$[Ti(H_{2}O)_{6}]^{3+}$$	(B) $$5.93\ BM$$
(III) $$[Cr(NH_{3})_{6}]^{3+}$$	(C) $$0.00\ BM$$
(IV) $$[Ni(H_{2}O)_{6}]^{2+}$$	(D) $$2.83\ BM$$
(V) $$[Fe(CN)_{6}]^{4-}$$	(E) $$3.88\ BM$$

Coordination Co...

Question 1

x- and y

y-only

x-only

z-only

Question 2

Hybridization is the separation of atomic orbitals.

$$sp^{2}-$$ hybrid orbitals are formed form two p- atomic orbitals and one s- atomic orbitals.

$$dsp^{2}-$$ hybrid orbitals are at $$\displaystyle\:90^{\circ}$$ to one another.

$$d^{2}sp^{3}-$$ hybrid orbitals are directed towards the corners of a regular octahedron.

Question 3

I, II, III all are correct.

I, II are correct

II, III are correct

III only correct

Question 4

Chlorophyll is a green pigment in plants and contains calcium

Haemoglobin is the red pigment of blood and contains iron

Cyanocobalamin is $$\displaystyle B_{12}$$ and contains cobalt

Carboxypeptidase A is an enzyme and contains zinc

Question 5

1, 2 and 3 are correct

2 and 3 are correct

1 and 3 are correct

1 and 2 are correct

Question 6

Nitrito $$\displaystyle -$$ N $$\displaystyle -$$ pentaammine cobalt ( III ) chloride.

Nitrito $$\displaystyle -$$ N $$\displaystyle -$$ pentaammine cobalt ( II ) chloride.

Pentaammine nitrito $$\displaystyle -$$ N $$\displaystyle -$$ cobalt ( II ) chloride.

Pentaammine nitrito $$\displaystyle -$$ N $$\displaystyle -$$ cobalt ( III ) chloride.

Question 7

Diamagnetic metal ions cannot have an odd number of electrons.

In an octahedral crystal field, the $$d-$$electrons of a metal ion occupy the $$\displaystyle e_{g}$$ set of orbitals before they occupy the $$\displaystyle t_{2g}$$ set of orbitals.

Low spin complex may be paramagnetic.

In high spin octahedral complex, $$\displaystyle \Delta _{0}$$ is less than the electron pairing energy and is relatively very small.

Question 8

(ii) and (iii)

(i), (ii) and (iii)

(i) and (iii)

(i) and (ii)

Question 9

I, II and IV

I and II

I, II, III and IV

I, II and III

Question 10

$$B A C D E$$

$$B A E D C$$

$$B C D E A$$

$$D E A B C$$

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