Coordination Compounds Test

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Coordination Compounds Test - 49

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Question 1
1 / -0

Directions For Questions

When hybridisation involving $$d$$-orbitals is considered all the five $$d$$-orbitals are not degenerate, rather $$d_{x^2-y^2}, d_z^{2}$$ and $$d_{xy}$$, $$d_{yz}$$, $$d_{zx}$$ form two different sets of orbitals and orbitals of appropriate set are involved in the hybridisation.

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Which of the following orbitals can not undergo hybridisation amongst themselves?
(I) $$3d$$, $$4s$$
(II) $$3d$$, $$4d$$
(III) $$3d$$, $$4s$$ and $$4p$$
(IV) $$3s$$, $$3p$$ and $$4s$$

A
only II

B
II and III

C
I, II and IV

D
II and IV

Solution

The order in which s, p, d and f orbitals are filled with electrons are governed by their energy levels. The lower energy orbital is filled first, followed by the very next orbital [1s energy is less than 2s] hence, 3d, 4d and 3s, 3p, 4s can not undergo hybridisation among themselves, because these orbitals are not in the sequential order of increasing energy.
Question 2
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Which of the following will have two stereoisomeric forms?
(I) $$[Cr(NO_{3})_{3}(NH_{3})_{3}]$$ (II) $$K_{3}[Fe(C_{2}O_{4})_{3}]$$ (III) $$[CoCl_{2}(en)_{2}]^{+}$$ (IV) $$[CoBrCl(ox)_{2}]^{3-}$$.

A
I only

B
I and II

C
III and IV

D
All of these

Solution

The compound $$[Cr(NO_3)_3(NH_3)_3]$$ has two stereoisomers fac and mer-isomers. Both are optically inactive.

The compound $$K_3[FE(C_2O_4)_3]$$ has two stereoisomers. Both are optically active.
One is d form and the other is l form.

The compound $$[CoCl_2(en)_2^+$$ has three stereoisomers. Two are geometrical isomers cis and trans.
The cis isomer has two optical isomers d form and l form.
trans isomer is meso in nature.

The compound $$[CoBrCl(Ox)_2]^{3-}$$ has three stereoisomers. Two are geometrical isomers cis and trans.
Th cis isomer has two optical isomers d form and l form.
trans isomer is meso in nature.
Question 3
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Complex compound $$[Cr(NCS)(NH_3)_5][ZnCl_4]$$ will be :

A
colourless and diamagnetic.

B
green coloured and shows coordination isomerism.

C
green coloured and shows linkage as well as coordiantion isomerism.

D
diamagnetic and shows linkage isomerism.

Solution

In the compound $$[Cr(NCS)(NH_3)_5][ZnCl_4]$$, the cation contains chromium with +3 oxidation state.
3 electrons are present in $$t_{2g}$$ levels. Hence, the complex is green in colour.
NCS is ambidentate ligand and can be linked through either N atom or thorough S atom. This gives rise to linkage isomerism.
Since, both cationic and anionic parts are complex ions, hence, coordination isomerism is also possible.
Question 4
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The most stable complex species is:

A
$$[Fe(C_2O_4)_3]^{3-}$$

B
$$[Fe(CN)_6]^{3-}$$

C
$$[Fe(CN)_6]^{4-}$$

D
$$[Fe(H_2O)_6]^{3+}$$

Solution

The stability of the complex depends on the charge density of the central metal ion.

The charge density of $$Fe^{3+}$$ ion is higher than that of $$Fe^{2+}$$ ion.

Thus the $$[Fe(CN)_6]^{4-}$$ complex containing $$Fe^{2+}$$ ion is least stable.

The stability of the complex also depends on the basic strength of the ligand.

Greater is the base strength of the ligand, greater is the stability of the complex. Also if the ligand forms the ring structure it's more stable.

Hence, the most stable ion is $$[[Fe(C_2O_4)_3]^{3−}$$.
Question 5
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Select the correct code about complex $$[Cr(NO_{2})(NH_{3})_{5}][ZnCl_{4}]$$:
(I) IUPAC name of compound is pentaamminenitrito-N-chromium (III) tetrachlorozincate(II)
(II) It shows geometrical isomerism
(III) It shows linkage isomerism
(IV) It shows coordination isomerism.

A
III, IV

B
I, III and IV

C
II, III and IV

D
I, II, III and IV

Solution

(i) The IUPAC name of the compound $$[Cr(NO_2)(NH_3)_5][ZnCl_4]$$ is pentaamminenitrito-N-chromium(III) tetrachlorozincate (II). Here N indicates that nitro group is attached to metal atom through N atom.
(ii) Geometrical isomerism is not possible in this compound.
(iii) Linkage isomerism is possible as nitro ligand is ambidentate ligand and has two donor atoms N and O.
(iv) It exhibits coordination isomers. The coordination isomers are $$[CrCl(NH_3)_5][ZnCl_3(NO_2)], [CrCl_2(NH_3)_4][ZnCl_2(NO_2)NH_3] and [Zn(NO_2)(NH_3)_3][CrCl_4(NH_3)_2]$$.
Question 6
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What is electronic arrangement of metal atom/ ion in octahedral complex with $$d^{4}$$ configuration, if $$\triangle_{0} <$$ pairing energy?

A
$$t_{2g}^{4}e_{g}^{0}$$

B
$$e_{g}^{4}t_{2g}^{0}$$

C
$$t_{2g}^{3}e_{g}^{1}$$

D
$$e_{g}^{2}t_{2g}^{2}$$

Solution

When $$\Delta_0 < P$$, the electrons will remain unpaired. Three d-electrons will enter $$t_{2g}$$ level and fourth d-electron will enter $$e_g$$ level. Thus, the electronic arrangement of the metal ion will be $$t_{2g}^3e_g^1$$.
Question 7
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Consider the following isomerism:
(i) Ionization (ii) Hydrate (iii) Coordination (iv) Geometrical (v) Optical
Which of the above isomerisms are exhibited by $$[Cr(NH_{3})_{2}(OH)_{2}Cl_{2}]^{-}$$?

A
(i) and (v)

B
(ii) and (iii)

C
(iii), (ii) and (i)

D
(iv) and (v)

Solution

The complex $$[Cr(NH_3)_2(OH)_2Cl_2^-$$ exhibits geometrical isomerism. Two geometrical isomers are cis and trans isomers.
It contains no element of symmetry and is optically active.
It can be resolved into d form and l form.
Question 8
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Which of the following statement is true?

A
In $$[PtCl_2(NH_3)_2]^{2+}$$ the cis form is optically inactive while trans form is optically active

B
In $$[Fe(C_2O_4)_3]^{3-}$$, geometrical isomerism does not exist while optical isomerism exists

C
In Mabcd, square planar complexes show both optical as well as geometrical isomerism

D
In Mabcd tetrahedral complex, optical isomerism cannot be observed

Solution

(A) Both cis and trans isomers of $$[PtCl_2(NH_3)_2]^{2+}$$ contain a plane of symmetry and are optically inactive. Thus statement A is incorrect.

(B) The complex $$[Fe(C_2O_4)_3]^{3-}$$ is of the type $$[M(AA)_3]^{n \pm}$$. It contains no symmetry element and exhibits only optical isomerism. Geometrical isomerism is not possible. Thus statement B is correct.

(C) In square planar [Mabcd] complex, plane of symmetry is present. Hence, they do not show optical isomerism. In this complex three geometrical isomers are possible. Thus statement C is incorrect.

(D) In [Mabcd] tetrahedral complex, no element of symmetry is present. Hence, optical isomerism is possible. Hence, the statement D is incorrect.
Question 9
1 / -0

At S.T.P. the density of $$CCl_4$$ vapours in g/L will be nearest to :

A
6.87

B
3.42

C
10.26

D
4.57

Solution

According to avogadro's law, 1 mole of every substance occupy 22.4 Liters at STP and weighs equal to its molecular mass.

Thus mass of $$CCl_4$$ at STP = 154 g

Volume occupied by $$CCl_4$$ at STP = 22.4 L

Density is defined as the mass contained per unit volume.

Density = $$\dfrac{Mass }{volume}$$= $$\dfrac{154}{22.4}$$= $$6.87 g/L$$
Question 10
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The number of complexes that can be can be made with varying $$NH_3$$ ligands to satisfy primary and secondary valencies of platinum are:

Complex; [$$PtCl_4\cdot xNH_3$$]

A
5

B
3

C
4

D
2

Solution

The correct answer is 5.
The number of complexes that can be can be made with $$PtCl_4\cdot xNH_3$$ are :

I. $$[Pt(NH_3)_6]Cl_4$$

II. $$[Pt(NH_3)_5Cl]Cl_3$$

III. $$[Pt(NH_3)_4Cl_2]Cl_2$$

IV: $$ [Pt(NH_3)_3Cl_3]Cl$$

V: $$[Pt(NH_3)_2Cl_4]$$

Option A is correct.

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Coordination Compounds Test - 49

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Coordination Compounds Test - 49

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Question 1

only II

II and III

I, II and IV

II and IV

Solution

Question 2

I only

I and II

III and IV

All of these

Solution

Question 3

colourless and diamagnetic.

green coloured and shows coordination isomerism.

green coloured and shows linkage as well as coordiantion isomerism.

diamagnetic and shows linkage isomerism.

Solution

Question 4

$$[Fe(C_2O_4)_3]^{3-}$$

$$[Fe(CN)_6]^{3-}$$

$$[Fe(CN)_6]^{4-}$$

$$[Fe(H_2O)_6]^{3+}$$

Solution

Question 5

III, IV

I, III and IV

II, III and IV

I, II, III and IV

Solution

Question 6

$$t_{2g}^{4}e_{g}^{0}$$

$$e_{g}^{4}t_{2g}^{0}$$

$$t_{2g}^{3}e_{g}^{1}$$

$$e_{g}^{2}t_{2g}^{2}$$

Solution

Question 7

(i) and (v)

(ii) and (iii)

(iii), (ii) and (i)

(iv) and (v)

Solution

Question 8

In $$[PtCl_2(NH_3)_2]^{2+}$$ the cis form is optically inactive while trans form is optically active

In $$[Fe(C_2O_4)_3]^{3-}$$, geometrical isomerism does not exist while optical isomerism exists

In Mabcd, square planar complexes show both optical as well as geometrical isomerism

In Mabcd tetrahedral complex, optical isomerism cannot be observed

Solution

Question 9

6.87

3.42

10.26

4.57

Solution

Question 10

5

3

4

2

Solution

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