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Coordination Compounds Test - 5

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Coordination Compounds Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    KCl.MgCl2.6H2O is a

    Solution

    A double salt is a salt which crystallises as a single substance but when it is dissolved it gets ionised as two salts and loses its identity in solution.KCl.MgCl2.6H2O is double salt.

  • Question 2
    1 / -0

    Which of the following ligands gives chelate complexes?

    Solution

    Oxalate is a bidentate ligand. So it is a chelate ligand and gives chelate complexes.

  • Question 3
    1 / -0

    In the formation of complex entity, the central atom/ion acts as

    Solution

    The central metal atom/ion behaves as a Lewis acid while the ligand acts as a lewis base. The ligand can be a negatively charged ion or a neutral molecule which donates its electron pair to the central metal atom/ion which acts as an electron pair acceptor (Lewis acid).

  • Question 4
    1 / -0

    Which of the following is a negatively charged ligand?

    Solution

    C5H5- is cyclopentadienyl anion and it is a negatively charged ligand.

  • Question 5
    1 / -0

    The correct IUPAC name of Mn3(CO)12 is

    Solution

    In the nomenclature of coordination compounds the ligands are named first followed by the name of central metal atom/ion followed by the oxidation state of the metal in parenthesis. Here CO is the carbonyl ligand, there are 12 CO ligands and they are attached to 3 Mn i.e. Manganese metal atoms. CO is a neutral ligand and carries no charge and hence the oxidation state of Mn is 0. So the IUPAC name is Dodecacarbonyltrimanaganese(0).

  • Question 6
    1 / -0

    Which is used in cancer therapy?

    Solution

    Cis-platin ( cis – [Pt(NH3)2(Cl)2] ) is a coordination compounds used in treatment of cancer. It inhibits the growth of tumors.

  • Question 7
    1 / -0

    The correct IUPAC name of [Fe(C5H​​​​5)2] is

    Solution

    C5H5- is cyclopentadienyl ligand. Name of ligand is written first followed by the name of the central metal and its oxidation state in parenthesis in roman numerals. C5H5- carries -1 charge and there are two such ligands. The overall charge on the complex is 0 so to balance the -2 charge of the ligands iron must be in +2 oxidation state. Hence, the IUPAC name of the complex is Bis(cyclopentandienyl)iron(II).

  • Question 8
    1 / -0

    Which of the following species is expected to be colourless?

    Solution

    Ti has atomic number 22. And its electronic configuration is 1s22s22p63s23p64s23d2.

    In given complex, there are four NO3​​​​- groups bonded to Ti. Each NO​​​​​3​​​​- carries -1 charge, hence there is -4 charge on the ligands and overall the complex is neutral which means Ti is in +4 oxidation state. So Ti​​​​​4+ has an electronic configuration 1s22s22p63s23pmeans there are no electrons in d orbital and hence d-d transition is not possible. So it is expected to be colourless.

  • Question 9
    1 / -0

    The correct IUPAC name of K2[Zn(OH)4] is

    Solution

    In an ionic compound cation is named first and then the anion. When the complex is anion we add -ate to the central metal. Here the cation is Potassium K+ and the anion is the complex. There are 2 Kand hence a total of +2 charge which is balanced by -2 charge on the complex. OH - is hydroxido ligand. Ligand is named first followed by the name of the central metal atom/ion with its oxidation state in paranthesis in roman numerals. Here there are 4 OH - and each carries a -1 charge. Let the oxidation state of Zn be x. Then

    x + 4(-1) = -2
    x - 4 = -2
    x = -2 + 4 = +2
    So, oxidation state of Zn=+2
    So, the IUPAC name is Potassium tetrahydroxidozincate(II).

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