Coordination Compounds Test

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Coordination Compounds Test - 50

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Weekly Quiz Competition

Question 1
1 / -0

Which is right combination?

(a) Hydrate isomerism-$$[Co(H_2O)_3Cl_3]3H_2O$$ and $$[Co(H_2O)_6]Cl_3$$

(b) Ionisation isomerism-$$[Co(NH_3)_5Br]SO_4$$ and $$[Co(NH_3)_5SO_4]Br$$

(c) Geometrical isomerism-$$MCl_2Br_2$$

A
a and b

B
b and c

C
a and c

D
a , b and c

Solution

a) Hydrate isomers differ by whether or not a hydrate molecule is directly bonded to the metal ion or merely present as free solvent molecules in the crystal lattice. In the given example also same thing occured. So they are hydrate isomers.

b) Here $$SO_4^{-2}$$ of first complex which is a counter ion, acts as a ligand to the second complex. This type of isomerism is called ionization isomerism.

c) $$MCl_2Br_2$$ are geometrical isomersim if they have required planar structure.

All are correct.
Question 2
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In complexes of weak field ligands, $$\Delta_o < P$$ (pairing energy), the energy difference between $$t_{2g}$$ and $$e_g$$ sets is relatively less. Under the influence of strong field ligands, $$\Delta_o > P$$ (pairing energy), the energy difference between $$t_{2g}$$ and $$e_g$$ sets is relatively high.
The correct statement regarding $$[Cr(en)_2Cl_2]^+$$ and $$[Co(C_2O_4)_2(NH_3)_2]^-$$ complex ions is :

A
both are equally stable complexes

B
both have equal number of stereoisomers

C
both are diamagnetic complexes

D
none of the above

Solution

(A) The complexes $$[Cr(en)_2Cl_2]^+ and [Co(C_2O_4)_2(NH_3)_2]^-$$ contain different ligands and different metal ions. Hence, they have different stabilities. Thus, option A is incorrect.
(B) Both complexes are of the type $$[M(AA)_2]a_2]^{n \pm}$$. Hence, they have equal number of sterioisomers. Hence, option B is correct.
(C) $$[Cr(en)_2Cl_2]^+$$ is paramagnetic with 3 unpaired electrons and $$ [Co(C_2O_4)_2(NH_3)_2]^-$$ is diamagnetic with zero unpaired electrons. Hence, option C is incorrect.
Question 3
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Directions For Questions

...view full instructions

The d-orbitals, which are stabilized in an octahedral magnetic field, are :

A
$$d_{xy}$$ and $$d_{z^2}$$

B
$$d_{x^2-y^2}$$ and $$d_{z^2}$$

C
$$d_{xy}, d_{xz}$$ and $$d_{yz}$$

D
$$d_{x^2}$$ only

Solution

In presence of octahedral field of ligands, the five degenerate $$d$$ orbitals of metal split into $$t_{2g} and e_g$$ levels.
$$t_{2g}$$ level is stabilized and $$e_g$$ level is destabilized.
$$t_{2g}$$ level contains $$d_{xy}, d_{xz} \ and\ d_{yz}$$ orbitals and $$e_g$$ level contains $$d_{x^2-y^2}\ and \ d_{z^2}$$ orbitals.
Thus $$d_{xy}, d_{xz}\ and\ d_{yz}$$ orbitals are stabilized and $$d_{x^2-y^2} \ and \ d_{z^2}$$ orbitals are destabilized in an octahedral field.
Question 4
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Maximum number of electrons in a subshell with l = 3 and n = 4 is :

A
14

B
16

C
10

D
12

Solution

$$n$$ = 4, $$l$$ =3
In f subshell, there are 7 orbitals and each orbital can accommodate a maximum of two electrons, so, maximum no. of electrons in 4f subshell = $$7\times2$$ = 14
Question 5
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Directions For Questions

A metal complex having composition $$Cr(NH_3)_4Cl_2Br$$ has been isolated in two forms, (X) and (Y). The form (X) reacts with $$AgNO_3$$ to give a white precipitate readily soluble in dilute aqueous ammonia, whereas (Y) gives a pale yellow precipitate soluble in concentrate ammonia.

...view full instructions

Choose the correct statement regarding the complexes X and Y:
(I) Both complexes have the same six geometrical isomers.
(II) Both complexes have nearly the same conductivity in $$H_2O$$.
(III) In both complexes, $$NH_3$$ is involved only to secondary valency.
(IV) In both complexes, electronic configuration of $$t_{2g}$$ is same.

A
I, II, and III

B
I, II, III, and IV

C
II, III, and IV

D
I, III, and IV
Question 6
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Which of the following gives the maximum number of isomers ?

A
$$[Co(NH_3)_4Cl_2]$$

B
$$[Ni(en)(NH_3)_4]^{2+}$$

C
$$[Ni(C_2O_4)(en)_2]$$

D
$$[Cr(SCN)_2(NH_3)_4]^+$$

Solution

$$[Cr(SCN)_2(NH_3)_4]^+$$ gives maximum number of isomers.
These includes cis trans isomers and linkage isomers.
In cis isomer, two SCN ligands are adjacent and in trans isomers, they are opposite. Linkage isomerism is due to ambidentate nature of the ligand SCN as it can coordinate either through S or through N.
Question 7
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Which chromium compound in widely used in training of leather?

A
$${Cr}_{2}{O}_{3}$$

B
$$Cr{O}_{2}{Cl}_{2}$$

C
$$Cr{Cl}_{3}$$

D
$${K}_{2}{SO}_{4}.{Cr}_{2}{({SO}_{4})_{3}}.24{H}_{2}O$$

Solution

Chrome alum is used in the tanning of leather, as chromium(III) stabilizes the leather by cross-linking the collagen fibers within the leather.

Chrome alum $${K}_{2}{SO}_{4}.{Cr}_{2}{({SO}_{4})_{3}}.24{H}_{2}O$$ is double sulphate of chromium.
Question 8
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The total number of possible coordination isomer for the given compound $$[Pt(NH_3)_4Cl_2][PtCl_4]$$ is:

A
2

B
4

C
5

D
3
Question 9
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$$[Cr(H_2O)_6]Cl_3$$ (atomic number of $$Cr=24$$) had a magnetic moment of $$3.83\ B.M.$$ The correct distribution of $$3d$$electrons in the chromium present in the complex is :

A
$$3d^1_{xy}, 3d^1_{yz}, 3d^1_{zx}$$

B
$$3d^1_{xy}, 3d^1_{yz}, 3d^1_{z^2}$$

C
$$3d^1_{(x^2-y^2)}, 3d^1_{z^2}, 3d^1_{zx}$$

D
$$3d^1_{xy}, 3d^1_{x^2-y^2}, 3d^1_{xz}$$

Solution

$$[Cr(H_2O)_6]Cl_3$$
+3 n = 3
magnetic moment
$$\mu = \sqrt {n(n+2)}$$ B.M.
and in octahedral complex these three electron have $$3d^1_{xy}, 3d^1_{yz}, 3d^1_{zx}$$ configuration
Question 10
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Both geometrical and optical isomerisms are shown by :

A
$$[Co(en)_2Cl_2]^+$$

B
$$[Co(NH_3)_5Cl_2]^{2+}$$

C
$$[Co(NH_3)_4Cl_2]^+$$

D
$$[Cr(OX)_3]^{3-}$$

Solution

$$[Co(en)_2Cl_2]^+$$ shows cis/trans isomerism.
also it have 2 optical isomers as

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Coordination Compounds Test - 50

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Coordination Compounds Test - 50

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SHARING IS CARING

Question 1

a and b

b and c

a and c

a , b and c

Solution

Question 2

both are equally stable complexes

both have equal number of stereoisomers

both are diamagnetic complexes

none of the above

Solution

Question 3

$$d_{xy}$$ and $$d_{z^2}$$

$$d_{x^2-y^2}$$ and $$d_{z^2}$$

$$d_{xy}, d_{xz}$$ and $$d_{yz}$$

$$d_{x^2}$$ only

Solution

Question 4

14

16

10

12

Solution

Question 5

I, II, and III

I, II, III, and IV

II, III, and IV

I, III, and IV

Question 6

$$[Co(NH_3)_4Cl_2]$$

$$[Ni(en)(NH_3)_4]^{2+}$$

$$[Ni(C_2O_4)(en)_2]$$

$$[Cr(SCN)_2(NH_3)_4]^+$$

Solution

Question 7

$${Cr}_{2}{O}_{3}$$

$$Cr{O}_{2}{Cl}_{2}$$

$$Cr{Cl}_{3}$$

$${K}_{2}{SO}_{4}.{Cr}_{2}{({SO}_{4})_{3}}.24{H}_{2}O$$

Solution

Question 8

2

4

5

3

Question 9

$$3d^1_{xy}, 3d^1_{yz}, 3d^1_{zx}$$

$$3d^1_{xy}, 3d^1_{yz}, 3d^1_{z^2}$$

$$3d^1_{(x^2-y^2)}, 3d^1_{z^2}, 3d^1_{zx}$$

$$3d^1_{xy}, 3d^1_{x^2-y^2}, 3d^1_{xz}$$

Solution

Question 10

$$[Co(en)_2Cl_2]^+$$

$$[Co(NH_3)_5Cl_2]^{2+}$$

$$[Co(NH_3)_4Cl_2]^+$$

$$[Cr(OX)_3]^{3-}$$

Solution

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