Coordination Compounds Test

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Coordination Compounds Test - 51

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Weekly Quiz Competition

Question 1
1 / -0

The number of total possible stereoisomers for [Pd(NH$$_2$$ - CH(CH$$_3$$) - CO$$_2^{-}$$)$$_2$$]$$^0$$ is?

A
10

B
4

C
8

D
6
Question 2
1 / -0

The total number of possible isomer for the complex compound : $$[Cu(NH_3)_4] [PtCl_4]$$

A
3

B
6

C
5

D
4

Solution

Option (D) is correct.
$$[Cu(NH_3)_3Cl] [Pt(Cl_3)NH_3]$$

$$[Cu(NH_3)_2Cl_2] [PtCl_2(NH_3)_2]$$

$$[Cu(NH)_3Cl] [PtCl(NH_3)_3]$$

$$[CuCl_4] [Pt(NH_3)_4]$$
Question 3
1 / -0

How many of the following reactions/ statements are correct ?
(I) $$\displaystyle CrO_{5}$$ shows blue colour in organic solvent but in aq. solution blue colour fades because $$\displaystyle CrO_{5}$$ decomposes to $$\displaystyle Cr^{3+}$$ and $$\displaystyle O_{2}$$
(II) $$\displaystyle [Co(SCN)_{4}]^{2-}$$ shows blue colour in aq. solution
(III) The pink ppt of $$\displaystyle Co(OH)_{2}$$ converts slowly to brown ppt $$\displaystyle Co(OH)_{3}$$ on exposure to air while green ppt of $$\displaystyle Ni(OH)_{2}$$ can be black $$\displaystyle Ni(OH)_{3}$$ with an oxidising reagent like NaOCI only

A
(i) only

B
(i) and (II) only

C
(iii) only

D
(I), (II) and (III) all are correct

Solution

(I) [True] $$Cr{ O }_{ 5 }$$ has a strained structure as shown, so it decomposes to $${ Cr }^{ 3+ }$$ and $${ O }_{ 2 }$$ as soon as it gets attacked by water.

(II) [True] $$[Co(SCN{ ) }_{ 4 }{ ] }^{ 2- }$$ has bright blue colour.

(III) [True] Oxidation of $${ Co }^{ 2+ }\rightarrow { Co }^{ 3+ }$$ is a spontaneous process as $${ Co }^{ 3+ }$$ is more stable than $${ Co }^{ 2+ }$$. But oxidation of $${ Ni }^{ 2+ } [{ 4s }^{ 0 }{ 3d }^{ 8 }]$$ to $${ Ni }^{ 3+ } [{ 4s }^{ 0 }{ 3d }^{ 7 }]$$ is not spontaneous as the previous electronic configuration is more stable than the latter.

Option [D]- All statements are correct.
Question 4
1 / -0

In which of the following molecules/species, all following characteristics are found?
(a) Tetrahedral hybridisation.
(b) Hybridisation can be considered to have taken place with the help of empty orbital(s).
(c) All bond lengths are identical, i.e., all $$A - B$$ bond lengths are identical.

A
$$B_4H_6$$

B
$$Al_2Cl_6$$

C
$$BeCl_2\, (g)\, $$

D
$${BF_4}^-$$

Solution

In $${BF_4}^-$$ ion, all following characteristics are found.
(a) Tetrahedral hybridisation which is $$sp^3$$ hybridization due to the presence of $$4$$ bond pairs of electrons and zero lone pairs of electrons..
(b) Hybridisation can be considered to have taken place with the help of empty orbital. $$B$$ contains $$3$$ valence electrons, whereas $$4$$ orbitals participate in the hybridization. Thus, one empty orbital participates in the hybridization.
(c) All bond lengths are identical, i.e., all $$A - B$$ bond lengths are identical as there are four identical $$B-F$$ single bonds.
Question 5
1 / -0

Which plays a major role in the formation of complex compound?

A
Transition metal

B
Lanthanides & Actinoides

C
Representative elements

D
p-Block elements

Solution

Two conditions for a compound to form complexes are
(i)The size of central metal cation must be small.
(ii)The cation must have vacant orbitals to accept electrons from ligands.
Both the conditions are fulfilled by transition elements.
Question 6
1 / -0

Amongst $$Ni(Cl_4)^{2-}, { \left[ Ni{ \left( { H }_{ 2 }O \right) }_{ 6 } \right] }^{ 2+ }$$,$$\left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] $$,$$\left[ Ni{ (CO) }_{ 4 } \right] $$ and $${ \left[ Ni{ (CN) }_{ 4 } \right] }^{ 2- }$$, the paramagnetic species are:

A
$${ \left[ Ni{ Cl }_{ 4 } \right] }^{ 2- },{ \left[ Ni{ \left( { H }_{ 2 }O \right) }_{ 6 } \right] }^{ 2+ },\left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] $$

B
$$\left[ Ni{ (CO) }_{ 4 } \right] ,\left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] ,{ \left[ Ni{ Cl }_{ 4 } \right] }^{ 2- }$$

C
$${ \left[ Ni{ (CN) }_{ 4 } \right] }^{ 2- },{ \left[ Ni{ \left( { H }_{ 2 }O \right) }_{ 6 } \right] }^{ 2+ },{ \left[ Ni{ Cl }_{ 4 } \right] }^{ 2- }$$

D
$$ \left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] ,\left[ Ni{ (CO) }_{ 4 } \right] ,{ \left[ Ni{ (CN) }_{ 4 } \right] }^{ 2- }$$

Solution
Question 7
1 / -0

What is hybridization?

A
The mixing of two or more atomic orbitals to form new orbitals that describe the covalent bonding in molecules.

B
The mixing of electrons in the electron sea model to account for the number of bonds in a molecule.

C
The mixing of two or more atomic orbitals to form new orbitals that describe the location of electrons in atoms.

D
The mixing of two or more molecules

E
The mixing of two or more atoms to make a new compound or molecule.

Solution

(A): The mixing of two or more atomic orbitals to form new orbitals that describe the covalent bonding in molecules.

The intermixing of two or more pure atomic orbitals of an atom with almost same energy to give same number of identical and degenerate new type of orbitals is known as hybridization.

The new orbitals formed are also known as hybrid orbitals.

Therefore, option A is correct.
Question 8
1 / -0

What is the first thing you need to know to use the hybridization theory?

A
The number of valence electrons in the participating atoms.

B
The number of total electrons in the participating atoms.

C
Where the element lies on the periodic table.

D
How many of each molecule are being made.

E
The valence bond theory.

Solution

(A): The number of valence electrons in the participating atoms are required to know to use the hybridization theory. Hybridization theory: The intermixing of two or more pure atomic orbitals of an atom with almost same energy to give same number of identical and degenerate new type of orbitals is known as hybridization.
Question 9
1 / -0

Which of the following statements is incorrect?

A
In $$K_{3}[Fe(CN)_{6}]$$, the ligand has satisfied only the secondary valency of ferric ion

B
In $$K_{3}[Fe(CN)_{6}]$$, the ligand has satisfied both primary and secondary valencies of ferric ion

C
In $$K_{4}[Fe(CN)_{6}]$$ the ligand has satisfied both primary and secondary valencies of ferrous ion

D
In $$[Cu(NH_{3})_{4}]SO_{4}$$ the ligand has satisfied only the secondary valency of copper

Solution

In $$\displaystyle K_{3}[Fe(CN)_{6}]$$, the ligand has satisfied both primary and secondary valencies of ferric ion. The +3 charge of ferric ion (primary valency) is satisfied by the negative charge on cyanide ions. The coordination sphere (secondary valency) is satisfied by six cyanide ligands.

So, A is the correct option.
Question 10
1 / -0

In addition reactions of aldehydes, the carbonyl carbon atom changes from:

A
$$sp^3$$ to $$sp^2$$

B
$$sp^2$$ to $$sp^3$$

C
$$sp$$ to $$sp^3$$

D
$$sp^3$$ to $$sp$$

Solution

In addition reactions of aldehyde,carbonyl carbon atom changes from $$sp^2 \rightarrow sp^3$$ as the $$C=O$$ bond breaks to $$C-O^-$$ bond.

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Re-Attempt Weekly Quiz Competition

Coordination Compounds Test - 51

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Coordination Compounds Test - 51

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SHARING IS CARING

Question 1

10

4

8

6

Question 2

3

6

5

4

Solution

Question 3

(i) only

(i) and (II) only

(iii) only

(I), (II) and (III) all are correct

Solution

Question 4

$$B_4H_6$$

$$Al_2Cl_6$$

$$BeCl_2\, (g)\, $$

$${BF_4}^-$$

Solution

Question 5

Transition metal

Lanthanides & Actinoides

Representative elements

p-Block elements

Solution

Question 6

$${ \left[ Ni{ Cl }_{ 4 } \right] }^{ 2- },{ \left[ Ni{ \left( { H }_{ 2 }O \right) }_{ 6 } \right] }^{ 2+ },\left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] $$

$$\left[ Ni{ (CO) }_{ 4 } \right] ,\left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] ,{ \left[ Ni{ Cl }_{ 4 } \right] }^{ 2- }$$

$${ \left[ Ni{ (CN) }_{ 4 } \right] }^{ 2- },{ \left[ Ni{ \left( { H }_{ 2 }O \right) }_{ 6 } \right] }^{ 2+ },{ \left[ Ni{ Cl }_{ 4 } \right] }^{ 2- }$$

$$ \left[ Ni{ \left( P{ Ph }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] ,\left[ Ni{ (CO) }_{ 4 } \right] ,{ \left[ Ni{ (CN) }_{ 4 } \right] }^{ 2- }$$

Solution

Question 7

The mixing of two or more atomic orbitals to form new orbitals that describe the covalent bonding in molecules.

The mixing of electrons in the electron sea model to account for the number of bonds in a molecule.

The mixing of two or more atomic orbitals to form new orbitals that describe the location of electrons in atoms.

The mixing of two or more molecules

The mixing of two or more atoms to make a new compound or molecule.

Solution

Question 8

The number of valence electrons in the participating atoms.

The number of total electrons in the participating atoms.

Where the element lies on the periodic table.

How many of each molecule are being made.

The valence bond theory.

Solution

Question 9

In $$K_{3}[Fe(CN)_{6}]$$, the ligand has satisfied only the secondary valency of ferric ion

In $$K_{3}[Fe(CN)_{6}]$$, the ligand has satisfied both primary and secondary valencies of ferric ion

In $$K_{4}[Fe(CN)_{6}]$$ the ligand has satisfied both primary and secondary valencies of ferrous ion

In $$[Cu(NH_{3})_{4}]SO_{4}$$ the ligand has satisfied only the secondary valency of copper

Solution

Question 10

$$sp^3$$ to $$sp^2$$

$$sp^2$$ to $$sp^3$$

$$sp$$ to $$sp^3$$

$$sp^3$$ to $$sp$$

Solution

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