Coordination Compounds Test

Result

Coordination Compounds Test - 55

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following complex ions will not show optical activity?

A
$$Pt[(Br)(Cl)(I)({NO}_{2})(Py){NH}_{3}]$$

B
cis-$$[Co{(en)}_{2}{Cl}_{2}]$$

C
$$[Co(en){({NH}_{3})}_{2}{Cl}_{2}]$$

D
$$[Cr{({NH}_{3})}_{4}{Cl}_{2}]$$
Question 2
1 / -0

No. of $$5$$ membered ring in $${[(Ca(EDTA)]}^{-2}$$ is:

A
5

B
6

C
7

D
8

Solution

The EDTA ligand is a hexadentate ligand and the number of 5 membered ring in $$[Ca(EDTA)]^{-2}$$ is 5 as can be seen in the image. Hencethe ciorrect option is A.
Question 3
1 / -0

Which of the following a bidentate mono iron ligands?

A
Acetyl Acetoneate

B
Oxalate ion

C
Both of these

D
None of the above

Solution
Question 4
1 / -0

In the complex ion $$ML_{6}^{n+}, M^{n+}$$ has five d-electrons and $$L$$ is weak field ligand. According to crystal field theory the magnetic properties of the complex ion corresponds to how many unpaired electrons?

A
$$0$$

B
$$5$$

C
$$2$$

D
$$3$$

Solution

In the complex ion $$[ML_6]^{n+}$$ if the metal ion have 5 d electrons and L is a weak field ligand then, the number of unpaired electrons is 5 because in the case of octahedral complexes with a weak field ligand the $$\Delta_o$$ < P.E(pairing energy) and hence the electrons are filled as $$t_g^3eg^2$$. Therefore the correct answer is B.
Question 5
1 / -0

How many number of unpaired electrons is present in the complex Hg[Co(SCN)$$_4]$$?

A
One

B
Two

C
Three

D
Four

Solution
Question 6
1 / -0

Which of the following complex will give white precipitate with $$BaCl_2(aq)$$

A
$$[Co(NH_3)_4SO_4]NO_2$$

B
$$[Cr(NH_3)_5SO_4]Cl$$

C
$$[Cr(NH_3)_5Cl]SO_4$$

D
Both $$(B)$$ and $$(C)$$

Solution

The white precipitate with $$BaCl_2(aq)$$ is due to the formation of $$BaSO_4.$$

$$[Cr(NH_3)_5Cl]SO_4 \to [Cr(NH_3)_5Cl]^{2+}+SO_4^{2-}$$

$$(Cr(NH_3)_5Cl]^{2+}+SO_4^{2-}+BaCl_2\to [Cr(NH_3)_5Cl]Cl_2+BaSO_4\downarrow+HCl$$.
Question 7
1 / -0

Which of the following is not correctly matched ?

A
$$[Fe (CN)_6]^{3-} d^2 sp^3$$, paramagnetic

B
$$[Ni (CO)_4] -sp^3$$, diamagnetic

C
$$[Fe(en)_3]^{+3} - sp^3 d^2$$, paramagnetic

D
$$[FeCl_2 (H_2O)_2] sp^3$$, paramagnetic

Solution
Question 8
1 / -0

Hydrogen peroxide oxidises $$\left[ Fe\left( CN \right) _{ 6 } \right] ^{ 4- }$$ to $$\left[ Fe\left( CN \right) _{ 6 } \right] ^{ 3- }$$ in acidic medium but reduces $$\left[ Fe\left( CN \right) _{ 6 } \right] ^{ 3- }$$ to $$\left[ Fe\left( CN \right) _{ 6 } \right] ^{ 4- }$$ in alkaline medium. The other products formed are, respectively:

A
$${ H }_{ 2 }O$$ and $$({ H }_{ 2 }O+{ O }_{ 2 })$$

B
$${ H }_{ 2 }O$$ and $$({ H }_{ 2 }O+{ O }{ H }^{ - })$$

C
$$({ H }_{ 2 }O+{ O }_{ 2 })$$ and $${ H }_{ 2 }O$$

D
None of these

Solution
Question 9
1 / -0

$${ \left[ Ni{ (CN) }_{ 4 } \right] }^{ 2- }$$ is isostructural with:

A
$${ HeF }_{ 4 }$$

B
$${ SiF }_{ 4 }$$

C
$${ SF }_{ 4 }$$

D
$$\left[ Pt{ (NH) }_{ 4 } \right] { Cl }_{ 2 }$$

Solution
Question 10
1 / -0

Hybridization of central atoms in the molecules $$N(CH_3)_3$$ and $$N(SiH_3)_3$$ respectively are:

A
$$sp^2$$ nad $$sp^2$$

B
$$sp^3$$ and $$sp^3$$

C
$$sp^2$$ and $$sp^3$$

D
$$sp^3$$ and $$sp^2$$