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Coordination Compounds Test - 6

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Coordination Compounds Test - 6
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Lithiumtetrahydridoaluminate is represented as

    Solution

    The cation is named first and then the anion. When the anion is the complex then the -ate is added to the name of the central metal. Here there are 4 hydride ligands represented as H​​​​​​- each carries a charge of -1 and hence a total of -4 charge on the ligands. Lithium ion is represented by Liand carries a +1 charge which means the charge on the complex is -1. In the complex, central metal atom/ion is written followed by the ligands in alphabetical order.
    Lithium tetrahydridoaluminate(III) is Li[AlH4].

  • Question 2
    1 / -0

    The correct name of the compound [Cu(NH3)4](NO3)2 is

    Solution

    In ionic compound, cation is named first and then the anion. If cation is the complex then ligands are named first in alphabetical order and then the central metal atom/ion with its oxidation state in paranthesis in roman numerals. Here, NH 3 (ammine) is the neutral ligand and there are 4 NH 3 bound to Cu (copper). Nitrate NO3is the anion there are two NO 3 - outside the square bracket each carries -1 charge so there is a total of -2 charge on anions and thus the complex carries a total of +2 charge. Since ammine is a neutral ligand so Cu has +2 oxidation state. So, [Cu(NH3)4](NO3)is tetraamminecopper(II) nitrate.

  • Question 3
    1 / -0

    Which of the following compound would exhibit coordination isomerism?

    Solution

    Coordination isomerism arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex. Here interchange of CN- and NH3 ligands is possible between Cr and Co to give [Co(NH3)6][Cr(CN)6]. So this complex can exhibit coordination isomerism.

  • Question 4
    1 / -0

    The kind of isomerism exhibited by [Rh(en)2Cl2][Ir(en)Cl4] and [Ir(en)3][RhCl6] is

    Solution

    When there is interchange of ligands between the cationic and anion species of different metal ions present in a complex, then coordination isomerism arises. Here we can find the interchange of en and Cl between Ir and Rh in the complexes.

  • Question 5
    1 / -0

    The metal-carbon bond in metal carbonyls possess

    Solution

    The metal-carbon bond in metal carbonyls possesses both σ and π character. The M–C σ bond is formed by the donation of lone pair of electrons on the carbonyl carbon into a vacant orbital of the metal. The M–C π bond is formed by the donation of a pair of electrons from a filled d orbital of metal into the vacant antibonding π* orbital of carbon monoxide. The metal to ligand bonding creates a synergic effect which strengthens the bond between CO and the metal.

  • Question 6
    1 / -0

    Which of the following complex ions/molecules of nickel is paramagnetic?

    Solution

    Ni has atomic number 28, so Ni2+ has electronic configuration 1s22s22p63s23p63d8. NH3 is a weak field ligand and hence two electrons are unpaired and hence this complex is paramagnetic.

  • Question 7
    1 / -0

    The compounds [Cr(H2O)6]Cl3 and [Cr(H2O)4Cl2]Cl.2H2O exhibit

    Solution

    Hydrate isomers differ by whether water molecules are directly bonded to the central metal atom/ion or are merely present as free water molecules in the crystal lattice. In the first complex the 6 water molecules are directly bonded to the central metal whereas in the second complex 2 water molecules are present as water of crystallisation and 4 water molecules are directly bonded to the central metal. So these exhibit hydrate isomerism.

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