Coordination Compounds Test

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Coordination Compounds Test - 70

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Weekly Quiz Competition

Question 1
1 / -0

The geometry of $$[Ni(CN)_4]^{2-}$$ and $$[NiCl_4]^{2-}$$ are:

A
both square planar

B
both tetrahedral

C
tetrahedral and square planar respectively

D
square planar and tetrahedral respectively

Solution
Question 2
1 / -0

The number of isomers possible for distributed borazine, $$B_3N_3H_4X_2$$ is:

A
$$3$$

B
$$4$$

C
$$6$$

D
$$5$$

Solution
Question 3
1 / -0

Number of unpaired electrons in $$[Co(F)_6]^{3-}$$ is:

A
$$4$$

B
$$2$$

C
$$3$$

D
$$1$$
Question 4
1 / -0

Directions For Questions

$$CuSO_{4}.5H_{2}O+KCN$$ (excess) $$\rightarrow A$$ (cyano complex)
$$CuSO_{4}.5H_{2}O+NH_{4}OH$$ (excess) $$\rightarrow B$$ (ammine complex)

...view full instructions

The formulae of $$A$$ and $$B$$ are:

A
$$K_{2}[Cu(CN)_{4}],[Cu(NH_{3})_{4}]SO_{4}$$

B
$$K_{3}[Cu(CN)_{4}], [Cu(NH_{3})_{4}]SO_{4}$$

C
$$K[Cu(CN)_{4}], [Cu(NH_{3})_{6}]SO_{4}$$

D
$$K_{3}[Cu(CN)_{6}], [Cu(NH_{3})_{6}]SO_{4}$$

Solution
Question 5
1 / -0

The formula of the compound which gives violet colour in Lassaigne's test for sulphur with sodium nitroprusside is:

A
$$Na_{4}[Fe(CN)_{6}S]$$

B
$$Na_{4}[Fe(CN)_{5}NCS]$$

C
$$Na_{4}[Fe(CN)_{5}NOS]$$

D
$$Na_{2}[Fe(CN)_{5}NOS]$$

Solution

While preparation of Lassaigne's extract, sulphur from the organic compound reacts with sodium to form sodium sulphide.

$$Na+S\rightarrow Na_2S$$

Sodium sulphide reacts with sodium nitroprusside to form violet colour compound, which confirms presence of Sulphur.

$$Na_2S+Na_2[Fe(CN)_5NO]\rightarrow Na_4[Fe(CN)_5NOS]$$

Hence the correct option is $$(C)$$.

Question 6

1 / -0

Match the List $$I$$ and List $$II$$ and pick the correct matching from the codes given below:

List $$I$$	List $$II$$
$$[Ag(CN)_2]^-$$	Square planer and $$1.73\ B.M$$
$$[Cu(CN)_4]^{3-}$$	Linear and zero
$$[Cu(CN)_6]^{4-}$$	Octahedral and zero
$$[Cu(NH_3)_4]^{2+}$$	Tetrahedral and zero
$$[Fe(CN)_6]^{4-}$$	Octahedral and $$1.73\ B.M$$

$$2, 4, 5, 1, 3$$

$$5, 4, 1, 3, 2$$

$$1, 3, 4, 2, 5$$

$$4, 5, 2, 1, 3$$

Solution

Question 7
1 / -0

Blood haemoglobin contains the metal

A
$$ Al $$

B
$$ Mg $$

C
$$ Cu $$

D
$$ Fe $$

Solution

Blood haemoglobin contains the metal $$ Fe $$.
Hence, Option "D" is the correct answer.
Question 8
1 / -0

When $$ CuSO_4 $$ solution is added to $$ K_4[Fe(CN)_6] $$ the formula of the product formed is

A
$$ Cu_2Fe(CN)_6 $$

B
$$ KCN $$

C
$$ Cu(CN)_3 $$

D
$$ Cu(CN)_2 $$

Solution

When $$ CuSO_4 $$ solution is added to $$ K_4[Fe(CN)_6] $$ the formula of the product formed is $$ Cu_2[Fe(CN)_6]. $$

$$ 2CuSO_4 +K_4(Fe(CN)_6] \rightarrow Cu_2[Fe(CN)_6] + 2K_2SO_4 $$
Question 9
1 / -0

$$S_{1}$$ : The species $$\left [ CuCl_{4} \right ]^{2-}$$ exists but $$\left [ Cul_{4} \right ]^{2-}$$ does not.
$$S_{2}: \left [ RhCl\left ( Ph_{3}P_{3} \right ) \right ]$$ and $$\left [ Ni(CO)_{4} \right ]$$ both are tetrahedral and diamagnetic.
$$S_{3}:N\left ( Me \right )_{3}$$ and $$N\left ( SiMe_{3} \right )_{3}$$ are isostructural

A
T T F

B
T F F

C
F T F

D
F T T

Solution

$$S_1: I^−\text{ ion is a stronger reducing agent than }Cl^−\text{ ion. It reduces }Cu^{2+} to \ Cu^0+ \ ion.$$
$$S_2:\text{ Both diamagnetic but }[Ni(CO)_4]\text{ is tetrahedral and }[RhCl(Ph_3P_3)]\text{ is a square planar.}$$

Option B is correct.
Question 10
1 / -0

$$[Co(NH_3)_5Br]SO_4$$ and $$[Co(NH_3)_5SO_4]Br$$ are examples of which type of isomerism

A
Linkage

B
Geometrical

C
Ionization

D
Optical

Solution

The two given compounds have the same composition but in solution, both will give different ions. The isomerism is known as ionisation isomerism.

$$[Co(NH_3)_5Br]SO_4\to [Co(NH_3)_5Br]^{2+}+SO_4^{2-}$$

$$[Co(NH_3)_5SO_4]Br\to [Co(NH_3)_5SO_4]^++Br^-$$

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Coordination Compounds Test - 70

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Coordination Compounds Test - 70

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Question 1

both square planar

both tetrahedral

tetrahedral and square planar respectively

square planar and tetrahedral respectively

Solution

Question 2

$$3$$

$$4$$

$$6$$

$$5$$

Solution

Question 3

$$4$$

$$2$$

$$3$$

$$1$$

Question 4

$$K_{2}[Cu(CN)_{4}],[Cu(NH_{3})_{4}]SO_{4}$$

$$K_{3}[Cu(CN)_{4}], [Cu(NH_{3})_{4}]SO_{4}$$

$$K[Cu(CN)_{4}], [Cu(NH_{3})_{6}]SO_{4}$$

$$K_{3}[Cu(CN)_{6}], [Cu(NH_{3})_{6}]SO_{4}$$

Solution

Question 5

$$Na_{4}[Fe(CN)_{6}S]$$

$$Na_{4}[Fe(CN)_{5}NCS]$$

$$Na_{4}[Fe(CN)_{5}NOS]$$

$$Na_{2}[Fe(CN)_{5}NOS]$$

Solution

Question 6

$$2, 4, 5, 1, 3$$

$$5, 4, 1, 3, 2$$

$$1, 3, 4, 2, 5$$

$$4, 5, 2, 1, 3$$

Solution

Question 7

$$ Al $$

$$ Mg $$

$$ Cu $$

$$ Fe $$

Solution

Question 8

$$ Cu_2Fe(CN)_6 $$

$$ KCN $$

$$ Cu(CN)_3 $$

$$ Cu(CN)_2 $$

Solution

Question 9

T T F

T F F

F T F

F T T

Solution

Question 10

Linkage

Geometrical

Ionization

Optical

Solution

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