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Relations and Functions Test - 34

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Relations and Functions Test - 34
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  • Question 1
    1 / -0
    If $$ f: R->R$$ is defined by $$f(x) = |x|$$, then
    Solution
    For a function $$f(x)$$ to be invertible, the function must be one-one and onto.

    The range of $$f(x) = |x|$$ is $$[0, \infty)$$, while the co-domain of $$f(x)$$ is given as $$\mathbb{R}$$. Hence $$f(x)$$ is not onto.

    Also, since $$f(x) = f(-x)$$, $$f(x)$$ is also not one-one in its domain.

    Hence, f(x) is not invertible, ie, the function $$f^{-1}(x)$$ does not exist.
    Option C is the right answer.
  • Question 2
    1 / -0
    If $$a \times b =2 a - 3b + ab$$, then $$3 \times 5+5\times 3$$ is equal to
    Solution

    $$ a\times b = 2a-3b+ab $$

    find $$ 3\times 5+5\times 3$$

    $$ 3\times 5[a = 3, b = 5]$$

    $$ \therefore 3\times 5 = 2(3)-3(5)+3(5)$$

    $$ 3\times 5= 6 $$

    $$ 5\times 3 [a = 5, b = 3]$$

    $$ \therefore 5\times 3 = 2(5)-3(3)+(5)(3)$$

    $$ = 10-9+15$$

    $$  5\times 3= 16$$

    $$ \therefore 3\times 5+5\times 3 = 6+16$$

    $$ 3\times 5+5\times 3= 22 $$

  • Question 3
    1 / -0
    If $$x \times y = x^{2}+y^{2}-xy$$ then the value of $$9 \times 11$$ is :
    Solution
    $$ x \times  y = x^{2}+y^{2}-xy $$
    $$ 9\times 11 = 9^{2}+11^{2}-9(11) $$
    $$ = 81+121-99 $$
    $$ 9\times 11  = 103 $$ 
  • Question 4
    1 / -0
    Let $$R$$ be the relation on $$Z$$ defined by $$R = \{(a, b): a, b \in z, a - b$$ is an integer$$\}$$. Find the domain and Range of $$R$$.
    Solution
    Given:

    $$R=\{ (a, b) : a, b, \in z, a-b \text{  is an integer}\}$$

    As difference of integers are also integers so,

    Domain of $$R = z$$

    Range of $$R = z$$, as

    $$a-b$$ spans the whole integer values.
  • Question 5
    1 / -0
    Let $$f(x)={x}^{3}-6{x}^{2}+15x+3$$. Then, 
    Solution
    $$f(x)=x^3-6x^2+15x+3$$

    $$f'(x)=3x^2-12x+15$$
    $$=3(x^2-4x+5)$$
    $$=3(x^2-4x+4+1)$$

    $$f'(x)=3(x-2)^2+{3} > 0$$

    Therefore $$f(x)$$ is strictly increasing function

    $$\Rightarrow f^{-1}(x)$$ exists

    Hence $$f(x)$$ is a invertible function.
  • Question 6
    1 / -0
    Read the following information and answer the three items that follow :
    Let $$f(x) = x^2 + 2x - 5 $$ and $$g(x) = 5x + 30$$
    If $$h(x) = 5f(x) - xg (x)$$, then what is the derivative of $$h(x)$$ ?
    Solution
    Given,

    $$f(x)=x^2+2x-5$$

    $$g(x)=5x+30$$

    $$h(x)=5f(x)-xg(x)$$

    $$=5(x^2+2x-5)-x(5x+30)$$

    $$=5x^2+10x-25-5x^2-30x$$

    $$h(x)=-20x-25$$

    $$\dfrac{d}{dx}[h(x)]=\dfrac{d}{dx}(-20x-25)$$

    $$=-20$$

  • Question 7
    1 / -0
    The number of binary operation on {1, 2, 3... n} is..
    Solution
    we have general formula,

    for the $$n$$ number of series, the number of binary operation is given by,

    $$2^n$$
  • Question 8
    1 / -0
    Read the following information and answer the three items that follow :
    Let $$f(x) = x^2 + 2x - 5 $$ and $$g(x) = 5x + 30$$
    Consider the following statements:
    1. $$f[g(x)]$$ is a polynomial of degree 3.
    2. $$g[g(x)]$$ is a polynomial of degree 2.
    Which of the above statements is/are correct ?
    Solution
    Neither 1 nor 2

    Given,

    $$f(x)=x^2+2x-5$$

    $$g(x)=5x+30$$

    (i)

    $$f[g(x)]$$

    $$=f[5x+30]$$

    $$=(5x+30)^2+2(5x+30)-5$$

    upon solving the above equation, we get,

    $$f[g(x)]=25x^2+310x+955$$

    degree $$=2$$

    (ii)

    $$g[g(x)]$$

    $$=g[5x+30]$$

    $$=5(5x+30)+30$$

    $$=25x+150+30$$

    $$=25x+180$$

    $$g[g(x)]=25x+180$$

    degree $$=1$$
  • Question 9
    1 / -0
    Let $$f(x)=\cfrac { 1 }{ 1-x } $$. Then $$\left\{ f\circ \left( f\circ f \right)  \right\} (x)$$
    Solution
    $$f(x)=\dfrac{1}{1-x}$$ for $$x\in R-\{1\}$$

    $$\{fof\}(x)=\dfrac{1}{1-\dfrac{1}{1-x}}=\dfrac{1}{\dfrac{1-x-1}{1-x}}=\dfrac{x-1}{x}=1-\dfrac{1}{x}$$ for $$x\in R - \{0,1\}$$

    $$\{fofof\}(x)=\dfrac{1}{1-fof(x)}=\dfrac{1}{1-\dfrac{x-1}{x}}=\dfrac{1}{\dfrac{x-x+1}{x}}=x$$ for $$x\in R-\{0,1\}$$
  • Question 10
    1 / -0
    Read the following information and answer the three items that follow :
    Let $$f(x) = x^2 + 2x - 5 $$ and $$g(x) = 5x + 30$$
    What are the roots of the equation $$g[f(x)] = 0$$ ?
    Solution
    Given,

    $$f(x)=x^2+2x-5$$

    $$g(x)=5x+30$$

    $$g[f(x)]=0$$

    $$g[x^2+2x-5]=0$$

    $$5(x^2+2x-5)+30=0$$

    $$5x^2+10x-25+30=0$$

    $$5x^2+10x+5=0$$

    $$x^2+2x+1=0$$

    $$(x+1)^2=0$$

    $$\therefore x=-1,-1$$
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