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Linear Programming Test - 16

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Linear Programming Test - 16
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  • Question 1
    1 / -0

    Objective of linear programming for an objective function is to

      Solution
      In linear programming, the objective function is the linear equation which is representing some quantity (such as profit gained, cost, ...) which is to be maximized or minimized subject to the given constraints.
    1. Question 2
      1 / -0
      If the feasible region for a solution of linear inequations is bounded, it is called as:
      Solution
      A bounded feasible region will have both a maximum value and a minimum value for the objective function. It is bounded if it can be enclosed in any shape.
      A convex polygon is a simple not self-intersecting closed shape in which no line segment between two points on the boundary ever goes outside the polygon.
      Hence, the answer is convex polygon.
    2. Question 3
      1 / -0
      If an iso-profit line yielding the optimal solution coincides with a constaint line, then
      Solution
      If an iso profit line which is yielding the optimal solution coincide with a constant line;then
      $$\rightarrow$$ the solution will b bounded ,i.e there will be a definite bounded area where the solution would be optional.
      $$\rightarrow$$ Since the area is bounded,the solution is feasible
      $$\rightarrow $$And the constant which coincides is not a redundant
      Hence None of above is the answer
    3. Question 4
      1 / -0
      Graphical method can be used only when the decision variables is
      Solution
      Graphical method can be used only when the decision variables is two.
    4. Question 5
      1 / -0
      Objective of LPP is
      Solution
      The objective of Linear Programming Problems (LPP) is to minimize or maximize the function.
      So, option B is correct.
    5. Question 6
      1 / -0
      The shaded part of a given figure indicates the feasible region, then the constraints are

      Solution
      Now, as the graph is in first quadrant. So, $$x\ge 0,y\ge 0$$,
      The region lies to the left of the line $$x=5$$, So $$ x\le 5$$ 
      It lies below the line $$y=3$$, So $$y\le 3$$
      Also, the region lies to the right of the line $$x=y$$. So, $$ x\ge y$$  or  $$ x-y\ge 0$$
      answer (b)
    6. Question 7
      1 / -0
      The feasible solution of an LP problem, is ________
      Solution
      the feasibe solution of a inear programming probem(LP) is a solution that must satisfy all of the problem's constraints simultaniously
    7. Question 8
      1 / -0
      The corner points of the feasible region determined by the system of linear constraints are $$(0, 10),(5, 5), (25, 20)$$ and $$(0, 30)$$. Let $$Z = px + qy$$, where $$p, q > 0$$. Condition on $$p$$ and $$q$$ so that the maximum of $$Z$$ occurs at both the points $$(25, 20)$$ and $$(0, 30)$$ is _______.
      Solution
      Maximum of $$Z$$ occurs at $$(25,20)$$ and at $$(0,30)$$.
      Hence, equating the vales of $$Z$$ at these points, we get
      $$25p+20q=30q$$
      $$\therefore 25p=10q$$
      $$\therefore 5p=2q$$
      This is the required relation.
      Also as $$p,q>0$$, the value of $$Z$$ is always positive and hence, is greater at $$(25,20)$$ and at $$(0,30)$$ than at $$(0,10)$$ and $$(5,5)$$.
    8. Question 9
      1 / -0
      The given table shows the number of cars manufactured in four different colours on a particular day. Study it carefully and answer the question.
       Colour   Number of cars manufactured
       Vento CretaWagonR 
       Red 65 88 93
       White 54 42 80
       Black 66 52 88
       Sliver37 49 74
      What was the total number of black cars manufactured?
      Solution
      The number of Black cars manufactured 

      $$=$$ no. of black $$Vento$$ +no. of black $$Creta$$ +no. of black $$WagonR$$ 

      $$=66+52+88 =206$$          
    9. Question 10
      1 / -0
      The taxi fare in a city is as follows: For the first kilometre, the fare is Rs. $$8$$ and the subsequent distance it is Rs. $$5$$ per km. Taking the distance covered as x km and fare as Rs y, write a linear equation.
      Solution
      for x km
      $$ 1,km $$
      fare
      $$= 8$$
      $$ (x-1)\,km $$
      fare
      $$ = (x - 1)5 $$
      $$ y = 5(x - 1)+8  = 3 + 5x $$ 
      B is correct

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