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Application of Derivatives Test - 67

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Application of Derivatives Test - 67
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  • Question 1
    1 / -0
    At any point on the curve $$2x^{2}y^{2}-x^{4}=c$$, the mean proportional between the abscissa and the difference between the abscissa and the sub-normal drawn to the curve at the same point is equal to 
    Solution

  • Question 2
    1 / -0
    If f(x) and g(x) are differentiable function for $$0 \leq x\leq 1$$ such that f(0) = 10 , g(0) = 2, f(1) = 2, g(1) =4, then in the interval (0,1) 
    Solution

  • Question 3
    1 / -0
    Given $$g(x)= \dfrac{x+2}{x-1}$$ and the line 3x + y -10 =0, then the line is 
    Solution

  • Question 4
    1 / -0
    If the is an error of k% in measuring the edge of a cube, then the percent error in estimating its volume is 
    Solution

  • Question 5
    1 / -0
    If the line joining the point (0, 3 ) and (5, -2) is a tangent to the curve $$y= \dfrac{c}{x+1}$$, then the value of c is 
    Solution

  • Question 6
    1 / -0
    $$f(x) = \left\{\begin{matrix} -x^2, & \text{for} \ x < 0 \\ x^2 + 8, & \text{for} \ x \ge 0 \end{matrix}\right.$$
    Let . Then x-intercept of the line, thet is , the tangent to the graph of f(x) is 
    Solution

  • Question 7
    1 / -0
    The equation of the curve $$y = be^{-x/a}$$ at the point where it crosses the y-axis is
    Solution

  • Question 8
    1 / -0
    A curve is represented by the equations $$x=sec^{2}t$$ and $$y=\cot t,$$ where t is a parameter. If the tangent at the point P on the curve, where $$t=\pi /4$$, meets the curve again at the point Q, then $$\left | PQ \right |$$ is equal to
    Solution

  • Question 9
    1 / -0
    Let f be a continuous, differetiable and bijective function. If the tangent to y= f (x) at x = a is also the normal to y = f (x) at x = b then there  exists at least one $$c \epsilon  (a, b)$$ such that 
    Solution

  • Question 10
    1 / -0
    Given the curves $$y=f(x)$$ passing through the point $$(0, 1)$$ and $$y=\displaystyle \int_{-\infty}^{x}{f(t)}$$ passing through the point $$\left( 0, \dfrac{1}{2}\right).$$ The tangents drawn to both the curves at the points with equal abscissae intersect on the $$x$$- axis. Then the curve $$y=f(x)$$ is 
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