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Atoms Test - 60...

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  • Question 1
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    Wavelength of the first line of Balmer series is 600nm600nm. The wavelength of second line of the Balmer series will be:

  • Question 2
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    Ionized hydrogen atoms and α\alpha-particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths rH:rαr_H : r_{\alpha} will be :

  • Question 3
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    The total energy of an electron revolving in the second orbit of hydrogen atom is?

  • Question 4
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    The period of revolution of an electron in the ground state of hydrogen atom is T. The period of revolution of the electron in the first excited state is?

  • Question 5
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    In HH-atm spectrum VV is the wave number
    V1=Vmin+VmaxV_1 = V_{min} + V_{max} for Lyman series
    V1=Vmin+VmaxV_1 = V_{min} + V_{max} for Balmer series then V1:V2V_1 : V_2

  • Question 6
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    An excited He+He^+ ion emits two photons in succession, with wavelengths 108.5nm108.5 nm and 30.4nm30.4 nm, in making a transition to ground state. The quantum number nn, corresponding to its initial excited state is (for photon of wavelength λ\lambda, energy E=1240eVλ(innm)E = \dfrac{1240 eV}{\lambda (in\, nm)})

  • Question 7
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    The number density of molecules of a gas depends on their distance rr from the origin as, n(r)=n0eαr4n(r) = n_0 e^{-\alpha r^4}. Then the total number of molecules is proportional to:

  • Question 8
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    The ratio of mass densities of nuclei of 40Ca^{40} Ca and 16O^{16} O is close to :

  • Question 9
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    Taking the wavelength of first Balmer line in hydrogen spectrum (n=3n=3 to n=2n=2) as 660nm660nm, the wavelength of the 2nd Balmer line (n=4n=4 to n=2n=2) will be:

  • Question 10
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    In Li++Li^{++}, electron in first Bohr orbit is excited to a level by a radiation of wavelength λ\lambda. when the ion gets deexcited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of λ\lambda ?
    (Given : h=6.63×1034Jsh = 6.63 \times 10^{34} Jsc=3×108ms1 \, c = 3 \times 10^8 ms^{-1})

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