Nuclei Test - 2...

The binding energy per nucleon of $$C^{12}$$ is $$7.68$$ MeV and that of $$C^{13}$$  is $$7.47$$ Mev. The energy required to remove one neutron from $$C^{13}$$ is

The atomic mass of $$_{7}N^{15}$$ is $$15.000108 amu$$ and that of $$_{8}O^{16}$$ is $$15.994915 amu$$. The minimum energy required to remove the least tightly bound proton is (mass of proton is $$1.007825 amu)$$

If $$2g$$ of hydrogen is converted into $$1.986 gm$$ Helium in a thermonuclear reaction,  the energy released is

$$_{7}N^{14} +_{2}He^{4}\rightarrow $$ X+$$_{1}H^{1}$$ ;  X is

Bombardment of lithium with proton gives rise to the following reaction :
$$^{7}_{3}Li+^{1}_{1} H \rightarrow $$2($$^{4}_{2}He) + Q $$
The Q-value is 
(atomic masses of lithium, proton and helium are $$7.016$$ amu, $$1.008$$ amu and $$4.004$$ amu respectively)

The masses of neutron and proton are $$1.0087$$ and $$1.0073$$ amu respectively. If the neutrons and protons combine to form a Helium nucleus of mass $$4.0015 amu$$, the binding energy of the Helium nucleus will be :

A  $$\gamma $$ -ray photon creates an electron-positron pair. The rest mass equivalent of electron is 0.5 MeV. KE of the electron - positron system is 0.78 MeV. Then the energy of $$\gamma $$ -ray photon is

Assertion (A) : All the radioactive elements are ultimately converted into lead
Reason (R): All the elements above lead are unstable

Assertion (A): Binding energy per nucleon is the measure of the stability of the nucleus.

In the nuclear fusion reaction : $$^{2}_{1}H+ ^{3}_{1}H \rightarrow $$ $$^{4}_{2}He+n $$ , given that the repulsive potential energy between the two nuclei is $$\sim 7.7 \times 10^{-14}$$J, the temperature to which the gases must be heated to initiate the reaction is nearly 
(Boltzmann's constant $$k=$$1.38 x 10$$^{-23}$$J)