Self Studies

Nuclei Test - 2...

TIME LEFT -
  • Question 1
    1 / -0

    The binding energy per nucleon of C12C^{12} is 7.687.68 MeV and that of C13C^{13}  is 7.477.47 Mev. The energy required to remove one neutron from C13C^{13} is

  • Question 2
    1 / -0

    The atomic mass of 7N15_{7}N^{15} is 15.000108amu15.000108 amu and that of 8O16_{8}O^{16} is 15.994915amu15.994915 amu. The minimum energy required to remove the least tightly bound proton is (mass of proton is 1.007825amu)1.007825 amu)

  • Question 3
    1 / -0

    If 2g2g of hydrogen is converted into 1.986gm1.986 gm Helium in a thermonuclear reaction,  the energy released is

  • Question 4
    1 / -0

    7N14+2He4_{7}N^{14} +_{2}He^{4}\rightarrow X+1H1_{1}H^{1} ;  X is

  • Question 5
    1 / -0

    Bombardment of lithium with proton gives rise to the following reaction :
    37Li+11H^{7}_{3}Li+^{1}_{1} H \rightarrow 2(24He)+Q^{4}_{2}He) + Q
    The Q-value is 
    (atomic masses of lithium, proton and helium are 7.0167.016 amu, 1.0081.008 amu and 4.0044.004 amu respectively)

  • Question 6
    1 / -0

    The masses of neutron and proton are 1.00871.0087 and 1.00731.0073 amu respectively. If the neutrons and protons combine to form a Helium nucleus of mass 4.0015amu4.0015 amu, the binding energy of the Helium nucleus will be :

  • Question 7
    1 / -0

    γ\gamma -ray photon creates an electron-positron pair. The rest mass equivalent of electron is 0.5 MeV. KE of the electron - positron system is 0.78 MeV. Then the energy of γ\gamma -ray photon is

  • Question 8
    1 / -0

    Assertion (A) : All the radioactive elements are ultimately converted into lead
    Reason (R): All the elements above lead are unstable

  • Question 9
    1 / -0

    Assertion (A): Binding energy per nucleon is the measure of the stability of the nucleus.

    Reason (R): Binding energy per nucleon is more for heavier nuclides.

  • Question 10
    1 / -0

    In the nuclear fusion reaction : 12H+13H^{2}_{1}H+ ^{3}_{1}H \rightarrow 24He+n^{4}_{2}He+n , given that the repulsive potential energy between the two nuclei is 7.7×1014\sim 7.7 \times 10^{-14}J, the temperature to which the gases must be heated to initiate the reaction is nearly 
    (Boltzmann's constant k=k=1.38 x 1023^{-23}J)

Submit Test
Self Studies
User
Question Analysis
  • Answered - 0

  • Unanswered - 10

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Submit Test
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now