Nuclei Test - 5...

Consider the following reaction:
$${ _{  }^{ 1 }{ H } }_{ 2 }+{ _{  }^{ 1 }{ H } }_{ 2 }\rightarrow { _{ 1 }^{  }{ He } }^{ 4 }+Q$$
If $$m({ _{ 1 }^{  }{ H } }^{ 2 })=2.0141u$$; $$m({ _{ 2 }^{  }{ He } }^{ 4 })=4.0024u$$, the energy $$Q$$ released (in MeV) in this fusion reacion is

In the nuclear reaction
$${ _{ 1 }^{  }{ H } }^{ 2 }+{ _{ 1 }^{  }{ H } }^{ 2 }\rightarrow { _{ 2 }^{  }{ He } }^{ 3 }+{ _{ 0 }^{  }{ n } }^{ 1 }$$
if the mass of the deuterium atom $$=2.014741a.m.u$$, mass of $${ _{ 2 }^{  }{ He } }^{ 3 }=3.016977a.m.u$$ and mass of neutron $$=1.008987a.m.u$$, then the $$Q$$ value of the reaction is nearly

Binding energy per nucleon for $${C}^{12}$$ is $$7.68MeV$$ and for $${C}^{13}$$ is $$7.74MeV$$. The energy required to remove a neutron from $${C}^{13}$$ is

Binding energy per nucleon of $${ _{ 1 }^{  }{ H } }^{ 2 }$$ and $${ _{ 2 }^{  }{ He } }^{ 4 }$$ are $$1.1MeV$$ and $$7.0MeV$$, respectively. Energy released in the process $${ _{ 1 }^{  }{ H } }^{ 2 }+{ _{ 1 }^{  }{ H } }^{ 2 }\rightarrow{ _{ 2 }^{  }{ He } }^{ 4 }$$ is

When a nucleus in an atom undergoes radioactive decay, the electronic energy levels of the atom

Tritium is an isotope of hydrogen whose nucleus Triton contains $$2$$ neutrons and $$1$$ proton. Free neutrons decay into $$p+\vec { e } +\vec { v } $$.  If one of the neutrons in Triton decays, it would transform into $${ _{ 2 }^{  }{ He } }^{ 3 }$$. This does not happen. This is because

Heavy stable nucleus have more neutrons than protons. This is because of the fact that

The particle used in nuclear fission for bombardment is:

Nuclear binding energy is equivalent to 

The accepted unit of atomic and molecular mass is: