Given,
Both capacitors
are in series
Capacitance
of A & B, CA=2μF&CB=3μF
Total
Potential is VT=(VA+VB)=10V
Let,
Potential difference
on capacitor A & B, VA,VB
In series,
Capacitor have equal charge
QA=QB
CAVA=CBVB
VBVA=CACB
VBVA+VB=CACB+CA
VB=CB+CACA(VA+VB)=52×10=4V
VB=4V
Similarly, VBVA=CACB⇒VA=CAVB×CB
⇒VA=24×3=6V
Potential difference
on capacitor A & B, VA=6V,VB=4V