Electrostatic P...

The circuit was in the shown state for a long time. Now if the switch S is closed then the met net charge that flows through the switch S, will be

If a thin metal foil of the same area is placed between the two plates of a parallel plate capacitor capacitance C, then new capacitance will be

As shown in the figure, two identical capacitors are connected to a battery of V voltin parallel. When capacitors are fully charged, their stored energy is $$U_1$$. If the key $$K$$ is opened and a material of dielectric constant K=3 is inserted in each capacitor, their stored energy is now $$U_2 \cdot \frac{U_1}{U_2}$$ will be

A parallel plate capacitor of capacitance,$$C$$ (without dielectrics) is filled by dielectric slabs as shown in figure.Then the new capacitance of the capacitor is

Six equal capacitors each of capacitance $$C$$ are connected as shown in the figure. The equivalent capacitance between $$A$$ and $$B$$ is:

Four metal conductors having different shapes are mounted on insulating stands and charged.The one which is best suited to retain the charges for a longer time is.

The equivalent capacitance between the points P and Q in the following arrangement of capacitor is

A number of capacitors, each of capacitance $$1\ \mu F$$ and each one of which gets punctured if a potential difference just exceeding $$500$$ volt is applied are provided. Then an arrangement suitable for giving a capacitor of capacitance $$3\ \mu F$$ across which $$2000$$ volt may be applied requires at least:

A capacitive network of complex combination is shown in the figure.The energy stored in $$ 4 \mu F $$ capacitor is.

The potential difference between the plates of a parallel plate capacitor is $$3.2\times 10^{4}V$$. A charge particle of mass $$4.0\times 10^{-13}kg$$ and charge $$2.4\times 10^{-18}C$$ is inserted between them. What should be the distance between the plates such that the particle remains stationary?