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Electrostatic Potential and Capacitance Test - 80

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Electrostatic Potential and Capacitance Test - 80
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Weekly Quiz Competition
  • Question 1
    1 / -0
    In the given figure, each capacitor is of capacitance $$1 \mu F$$.Calculate the equivalen capacitance between A and B.

    Solution

  • Question 2
    1 / -0
    An infinite number of charges each equal to Q are placed along the x-axis at x=1,x=2,x=4,x=8,.......... and so on.Find the potential and electric filed at the point x=0  , due to this set of charges:
    Solution

  • Question 3
    1 / -0
    The electric potential in a certain region is expressed by $$V = 6x-8xy^2-8y + 6yz - 4z^2$$ volts. The magnitude of the force acting on a charge of $$2C$$ sityuated at the origin wil be:-
    Solution

  • Question 4
    1 / -0
    Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is $$2\times\ 10^5\ V/m$$. When the space is filled with dielectric, the electric field becomes $$1\times\ 10^5\ V/m$$. The dielectric constant of a dielectric material is:
    Solution

  • Question 5
    1 / -0
    The resultant capacity between point $$A$$ and point $$B$$ in the following circuit will be:

    Solution

  • Question 6
    1 / -0
    Four condensers are connected as shown in the figure. The effective capacity in $$\mu F$$ between the points $$A$$ and $$B$$ are :

    Solution

  • Question 7
    1 / -0
    Fig. shows a network of four capacitors. Determine the equivalent capacitance between points $$A$$ and $$B$$. If a $$10V$$ battery is connected between $$A$$ and $$B$$, how much total charge will be stored on the capacitors ?

  • Question 8
    1 / -0
    In the given circuit, if potential difference between points $$A$$ and $$B$$ is $$4V$$, then, resistance $$X$$ is:-

    Solution

  • Question 9
    1 / -0
    The potential difference between points $$A$$ and $$D$$ in the given circuit is:-

    Solution
    Hint: The potential drop on parallel connection is same.

    Step 1: Equivalent resistance through ADC,
    The equivalent resistance in the series connection is defined as,
    $$R=R_1+R_2+R_3$$
    $$R=5\Omega+5\Omega+5\Omega$$
    $$R=15\Omega$$

    Step 2: Finding the current through ADC,
    As the potential drop in the parallel connection, therefore the potential drop across $$15\Omega$$ is same.
    According to Ohm's law,
    $$V=IR$$
    $$I=\dfrac{V}{R}$$
    $$I=\dfrac{2}{15}$$

    Step 3: Finding the potential drop.
    Using the Ohm's law, the potential drop across AD is,
    $$V=IR$$
    $$V=\dfrac{2}{15}\times 5$$
    $$V=\dfrac{2}{3}$$
  • Question 10
    1 / -0
    Two condensers of capacities $$C$$ farad and $$2C$$ farad are connected in parallel and then connected in series with a third condenser of capacity $$3C$$ farad. The combination is charged with $$V$$ volt. The charge (in coulomb) on condenser of capacity $$C$$ farad is:
    Solution
    $$Q = \dfrac{3C}{2}V$$
    $$\dfrac{Q_1}{Q_2} = \dfrac{C}{2C} = \dfrac{1}{2}$$
    $$\dfrac{Q_1}{Q_1 + Q_2} = \dfrac{1}{1+2} = \dfrac{1}{3}$$
    $$\dfrac{Q_1}{\dfrac{3CV}{2}} = \dfrac{1}{3}$$
    $$R_2 = \dfrac{CV}{2}$$

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