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Electrostatic P...

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  • Question 1
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    In the circuit figure, find the charge of the condenser having capacity $$3\mu F$$

  • Question 2
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    In the figure, a proton moves a distance d in a uniform $$\vec{E}$$ as shown in the figure. If W is work done by the electric field and $$\Delta U$$ is change in the electric potential energy of the proton then.

  • Question 3
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    A capacitor $${ C }_{ 1 }=1\mu F$$ is charged to a potential of $$100 V$$ . The charging battery is taken removed and it is connected to another capacitor of capacity $${ C }_{ 2 }=2\mu F$$. One plate of $${ C }_{ 2 }$$ is earthed as shown in figure. The charges on $${ C }_{ 1 }$$and $${ C }_{ 2 }$$ in steady state will be :

  • Question 4
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    Three identical charged capacitors each of capacitance 5 $$\mu F$$ are connected as shown in figure. Potential difference across capacitor (3), long time after the switches $$K_1$$ and $$K_2$$ are closed, is  

  • Question 5
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    You are given three condensers, each of capacitance $$ 30 \mu F $$ and $$2$$ battery of emf $$200 V$$. They can be joined in series or in parallel. Which arrangement of the condensers will give the minimum energy?

  • Question 6
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    A point charge $$q = 1\ C$$ and mass $$1\ kg$$ is projected with speed $$10\ ms^{-1}$$ in the perpendicular direction of uniform electric field $$E = 100\ Vm^{-1}$$ The value of latus rectum of the path followed by charged particle (in meter) is :

  • Question 7
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    The effective capacitance between points $$A$$ and $$B$$ is 

  • Question 8
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    If potential of  $$A$$  is  $$10 V  ,$$  then potential of  $$B$$  is :-

  • Question 9
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    Two parallel plate capacitors whose capacitance are  $$C$$  and  $$2 C$$  respectively, are joined in parallel, these are charged by  $$V$$  potential difference. if the battery is now removed and a dielectric of dielectric constant  $$K$$  is filled in between the plates of the capacitor  $$C,$$  then what will be the potential difference across each capacitor:

  • Question 10
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    The equivalent capacitance between point $$A$$ and $$B$$ of the circuit shown will be:

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