Current Electricity Test

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Current Electricity Test - 13

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Weekly Quiz Competition

Question 1
1 / -0

Kirchhoff's first law, i.e., ΣI = 0 at a junction, deals with the conservation of

A
Momentum

B
Angular momentum

C
Charge

D
Energy
Question 2
1 / -0

The resistance of a metallic conductor increases due to

A
Increase in the number of collisions between the carriers

B
Change in carrier density

C
Increase in the rate of collisions between the carriers and vibrating atoms of the conductor

D
Change in dimensions of the conductor

Solution

When temperature increases, the thermal speed of the electrons increases as well as, the amplitude of vibration of the positive ions inside the metal conductor also increase, about their mean positions. Thus, the collisions between the electrons and the positive metal ions become more frequent and this decreases the relaxation time, t, leading to an increase in the resistivity of the conductor.

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Question 3
1 / -0

A piece of copper and another of germanium are cooled from room temperature to 80K. The resistance of

A
copper increases and that of germanium decreases

B
each of them increases

C
each of them decreases

D
copper decreases and that of germanium increases

Solution

Copper is a conductor and we know that for conductors, resistance is directly proportional to temperature. Therefore on decreasing temperature resistance also decreases.
Whereas, germanium is a semiconductor and for semiconductors, resistance is inversely proportional to temperature. So on decreasing temperature resistance increases.

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Question 4
1 / -0

Power dissipated in a resistance R through which current I is flowing is

A
I²R

B
IR²

C
IR

D
I²R²

Solution

The power dissipated
P = V × I
Since V = IR
P = I²R

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Question 5
1 / -0

According to Kirchhoff’s Junction Rule,

A
At any junction of circuit elements, the sum of currents entering and leaving the junction must be negative.

B
At any junction of circuit elements, the sum of currents entering the junction must equal the sum of currents leaving it.

C
none of these

D
At any junction of circuit elements, the sum of currents entering and leaving the junction must be positive.

Solution

Kirchhoff’s junction rule is based on the principle of conservation of charge. For steady currents, there can be no accumulation of charge in a junction. The currents entering a junction bring charge to the junction and the currents leaving a junction carry away the charge brought to the junction.

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Question 6
1 / -0

Direction of the conventional current

A
is the direction in which positive charges move

B
is the direction in which no charges move

C
is the direction in which negative charges move

D
none of these

Solution

Current flows in a conductor due to the flow of negatively charged electrons. However, the direction of conventional current is taken to be opposite to the direction of flow of electrons. It can therefore be considered as the direction in which positive charges move.

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Current Electricity Test - 13

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Current Electricity Test - 13

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Question 1

Momentum

Angular momentum

Charge

Energy

Question 2

Increase in the number of collisions between the carriers

Change in carrier density

Increase in the rate of collisions between the carriers and vibrating atoms of the conductor

Change in dimensions of the conductor

Solution

Question 3

copper increases and that of germanium decreases

each of them increases

each of them decreases

copper decreases and that of germanium increases

Solution

Question 4

I2R

IR2

IR

I2R2

Solution

Question 5

At any junction of circuit elements, the sum of currents entering and leaving the junction must be negative.

At any junction of circuit elements, the sum of currents entering the junction must equal the sum of currents leaving it.

none of these

At any junction of circuit elements, the sum of currents entering and leaving the junction must be positive.

Solution

Question 6

is the direction in which positive charges move

is the direction in which no charges move

is the direction in which negative charges move

none of these

Solution

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I²R

IR²

I²R²