Current Electricity Test

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Current Electricity Test - 33

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Weekly Quiz Competition

Question 1
1 / -0

________ represents the most significant digits of the resistance value in finding the resistance of carbon resistor.

A
Last two color bands

B
First two color bands

C
Last color band only

D
First color band only

Solution

Since first and second color bands has higher multiplier, they represents the most significant digits of the resistance value in finding the resistance of carbon resistor.
Therefore, B is correct option.
Question 2
1 / -0

In the 5 band color resistor,which color bands are considered as significant digits?

A
First band only

B
First three bands

C
First two bands

D
Last band

Solution

A 5-bandcolor resistor is represented as
$R=abc\times d\pm e\%$
Where, $a$ represents the $1^{st}$ significant digit, which is the first band color of resistor.
$b$ represents the $2^{nd}$ significant digit, which is the second band color of resistor.
$c$ represents the $3^{rd}$ significant digit, which is the third band color of resistor.
$d$ represents the $4^{th}$ significant digit, which is the fourth band color of resistor and this is the multiplier value used in formula.
$e$ represents the $5^{th}$ significant digit, which is the fifth band color of resistor and this is the tolerance value of resistor.
Question 3
1 / -0

Which color band in the color coding of a resistor has the tolerance $\pm2$ %?

A
Orange

B
Black

C
Silver

D
Red

Solution

Red color band in the color coding of a resistor has the tolerance of $\pm2\%$
Question 4
1 / -0

If three resistors 2 ohm, 3 ohm and 4 ohm are connected in series, then effective resistance in a circuit will be _______ ohm.

A
9

B
6

C
1

D
5

Solution

$R_{eq}=R_1 + R_2 + R_3$

$=2+3+4= 9 \Omega$
Question 5
1 / -0

Consider the following two statements:
1) Kirchoff's junction law follows from the conservation of charge
2) Kirchoff's loop law follows from the conservation of energy.
Which of the following is correct?

A
both 1 and 2 are wrong

B
1 is correct and 2 is wrong

C
1 is wrong and 2 is correct

D
both 1 and 2 are correct

Solution

Kirchhoff's loop law follows conservation of energy, nature of electric field.
Kirchhoff's junction law follows from the conservation of charge.
Question 6
1 / -0

Kirchoff's junction law is equivalent to ___________.

A
Conservation of energy

B
Conservation of charge

C
Conservation of electric potential

D
Conservation of electric flux

Solution

Kirchhoff's junction rule is an application of the principle of conservation of electric charge: current is flow of charge per time, and if current is constant, that which flows into a point in a circuit must equal that which flows out of it.
Question 7
1 / -0

A steady current flows in a metallic conductor of non-uniform cross-section. The quantity/quantities constant along the length of the conductor is /are

A
current , electric current and drift velocity

B
drift speed only

C
current and drift speed only

D
current only

Solution

Current does not depends on the area of conductor , hence it remains a constant.
Current density is inversely a constant.
Current density is inversely proportional to area (i.e.,) $J\propto \dfrac 1A$ electric field drift speed is also inversely proportional to area (i.e.,) $E\propto\dfrac 1A , V_d\propto \dfrac 1A$
Hence current is constant along the conductor.
Question 8
1 / -0

Potentiometer measures potential more accurately because

A
it measures potential in the open circuit .

B
it uses sensitive galvanometer for null deflection .

C
it uses high resistance potentiometer wire .

D
it measures potential in the closed circuit .

Solution

A potentiometer has very large resistance. To read load voltage or voltage across any circuit element, potentiometer is connected parallel across it. Thus, the load voltage or circuit voltage gets applied across the potentiometer but as the resistance is very high compared to load resistance, you can safely assume their is almost no current flowing through potentiometer. As power= $VI$ , the power loss in potentiometer is almost equal to zero as current through it remains zero.
Therefore it measures the potential in the open circuit.
Question 9
1 / -0

If the equivalent resistance is to be increased, then the number of resistances should be connected in:

A
Series

B
Parallel

C
Mixed arrangement

D
None of the above

Solution

Equivalent resistance is maximum and current flow is minimum when number of resistances are connected in series. $R_{eq}= R_1 + R_2 + R_3$ ; where $R_1,R_2,R_3$ are resistances.
Question 10
1 / -0

The equivalent resistance due to series connection of $10\ \Omega$ and $10\ \Omega$ resistors is

A
$5\ \Omega$

B
$10\ \Omega$

C
$0\ \Omega$

D
$20\ \Omega$

Solution

For series connection(Current remains same):
$R_{ (total)} = R_1 + R_2$
In series combination equivalent resistance is total sum of the resistances.
$\Rightarrow R_{total}=10+10$
$\Rightarrow R_{total}=20\Omega$

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Current Electricity Test - 33

Result

Current Electricity Test - 33

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SHARING IS CARING

Question 1

Last two color bands

First two color bands

Last color band only

First color band only

Solution

Question 2

First band only

First three bands

First two bands

Last band

Solution

Question 3

Orange

Black

Silver

Red

Solution

Question 4

9

6

1

5

Solution

Question 5

both 1 and 2 are wrong

1 is correct and 2 is wrong

1 is wrong and 2 is correct

both 1 and 2 are correct

Solution

Question 6

Conservation of energy

Conservation of charge

Conservation of electric potential

Conservation of electric flux

Solution

Question 7

current , electric current and drift velocity

drift speed only

current and drift speed only

current only

Solution

Question 8

it measures potential in the open circuit .

it uses sensitive galvanometer for null deflection .

it uses high resistance potentiometer wire .

it measures potential in the closed circuit .

Solution

Question 9

Series

Parallel

Mixed arrangement

None of the above

Solution

Question 10

5 Ω5\ \Omega5 Ω

10 Ω10\ \Omega10 Ω

0 Ω0\ \Omega0 Ω

20 Ω20\ \Omega20 Ω

Solution

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$5\ \Omega$

$10\ \Omega$

$0\ \Omega$

$20\ \Omega$