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Ray Optics and Optical Test - 37

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Ray Optics and Optical Test - 37
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  • Question 1
    1 / -0
    Which of the following comes under laws of refraction?
    Solution
    The laws of refraction are as follows:

    1. According to the first law of refraction, the incident ray, the refracted ray and the normal to the point of incidence, all lie in the same plane.

    2. According to the second law of refraction, also, known as the Snell's law, the ratio of sine of the angle of incidence to the sine of angle of refraction is a constant for a given pair of media. 
    Sin iSin r=Constant \Rightarrow \dfrac{Sin\ i}{Sin\ r} = Constant
      
    This constant is known as the refractive index.

    Hence, the correct answer is option C.
  • Question 2
    1 / -0
    Mirror formula can also be written as:
    Solution
    Focal length, f=R2f = \dfrac {R}{2}, where RR = radius of curvature
    So, 1v+1u=1f\dfrac {1}{v} + \dfrac {1}{u} = \dfrac {1}{f} can be written as
    1v+1u=2R\Rightarrow \dfrac {1}{v} + \dfrac {1}{u} = \dfrac {2}{R}
  • Question 3
    1 / -0
    Correct mirror formula is:
    Solution
    Mirror formula is:
    1v+1u=1f\dfrac {1}{v} + \dfrac {1}{u} = \dfrac {1}{f}
    That is; 1Object Distance+1Image Distance=1Focal length of the mirror\dfrac {1}{\text {Object Distance}} + \dfrac {1}{\text {Image Distance}} = \dfrac {1}{\text {Focal length of the mirror}}
  • Question 4
    1 / -0
    Mirror formula is valid for:
    Solution
    Mirror formula is:
    1v+1u=1f\dfrac {1}{v} + \dfrac {1}{u} = \dfrac {1}{f}
    That is; 1Object Distance+1Image Distance=1Focal length of the mirror\dfrac {1}{\text {Object Distance}} + \dfrac {1}{\text {Image Distance}} = \dfrac {1}{\text {Focal length of the mirror}}
    This relationship is applicable for both concave and convex mirrors.
  • Question 5
    1 / -0
    Change in the direction of light when it passes from one medium to another is called ............
    Solution
    Reflection \bf{Reflection} is the phenomenon in which light rays on striking a polished surface(such as a mirror) bounce back or are sent back into the same medium. 

    Refraction \bf{Refraction} of light is the phenomenon of bending of light or change in the direction of light, when it passes obliquely from one transparent medium to another.

    Diffraction \bf{Diffraction} is the phenomenon of bending of light waves around the corners of an obstacle or aperture, placed in the path of light beam. 

    Scattering\bf{Scattering} is the phenomenon by which a beam of light is redirected or deflected in many different directions when it passes through an imperfect medium due to the interaction with the particles of the medium.

    Hence, the correct answer is OPTION B. 
  • Question 6
    1 / -0
    Centre of curvature of a concave mirror lies .......
    Solution
    The reflecting surface of a spherical mirror forms a part of the sphere and the centre of this sphere is called the centre of curvature of the spherical mirror.  The centre of curvature of a concave mirror lies in front of it. 
  • Question 7
    1 / -0
    Fill in the blanks:
    ________ is geometric centre of spherical mirror.
    Solution
    The geometric centre of a spherical mirror is called Centre of curvature (C). It is the center of a hollow spherical surface from which this mirror is taken off.

  • Question 8
    1 / -0
    When light travels from air to water there is ...........................
    Solution
    Reflection \bf{Reflection} is the phenomenon in which light rays striking a polished surface(such as a mirror) bounce back or are sent back into the same medium. 

    Refraction \bf{Refraction} of light is the phenomenon of bending of light or change in the direction of light when it passes obliquely from one transparent medium to another.

    Diffraction \bf{Diffraction} is the phenomenon of bending of light waves around the corners of an obstacle or aperture placed in the path of the light beam.

    Scattering\bf{Scattering} is the phenomenon by which a beam of light is redirected or deflected in many different directions when it passes through an imperfect medium due to the interaction with the particles of the medium.

    Therefore, when light travels from air to water, there is refraction of light. 

    Hence, the correct answer is OPTION B.
  • Question 9
    1 / -0
    The centre of the sphere from which the spherical mirror has been formed is called ....................
    Solution
    The reflecting surface of a spherical mirror is a part of a sphere. The centre of the sphere is called the centre of curvature of the spherical mirror.  It is represented by the letter CC
    Hence option B is correct
  • Question 10
    1 / -0
    For a light ray undergoing refraction, sinisinr=\dfrac{sin i}{sin r}=
    Solution
    According to Snell's law of refraction, μ1sini=μ2sinr\mu_1sini=\mu_2sinr 
     sinisinr=μ2μ1\frac{sini}{sinr}=\frac{\mu_2}{\mu_1}
    Where μ1\mu_1 and μ2\mu_2 are refractive index of first and second medium respectively.
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