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Basic Science Test 19

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Basic Science Test 19
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  • Question 1
    1 / -0
    A man holds a ball of (1/2) kg in his hand. He throws it vertically upward. During this process his hand moves up by 40 cm and the ball leaves his hand with an upward velocity of 4 m/s. The constant force with which the man pushes the ball is
  • Question 2
    1 / -0
    A square plate having mass m and side length 'a', its moment of inertia along the axis passing through its diagonal is-
  • Question 3
    1 / -0
    A force of 100 N need to be applied parallel to a smooth! inclined plane just to hold a body on it. The angle inclination of the inclined plane is $$30^{0}$$. How much horizontal force need to be applied to do the same?
    Solution
    $$mg \sin 30 = 100$$
    $$mg/2 = 100$$
    $$mg = 200 \space N$$
    $$ma \cos \theta = mg \sin \theta$$
    $$ma \cos \theta = 100$$
    $$ma \sqrt{3}/2 = 100$$
    $$\Rightarrow ma = 200/\sqrt{3} \approx 115 \space N $$

  • Question 4
    1 / -0
    Moment of inertia of a thin circular plate of mass M, radius R about an axis passing through its diameter I. The moment of inertia of a circular ring of mass M, radius R about an axis perpendicular to its plane and passing through its centre is 
    Solution
    We know a moment of inertia of a disc, axis  passing through its diameter is $$I = \dfrac{MR^2}{4}$$
    $$\therefore I' = MR^2$$
    $$I'=4I$$
  • Question 5
    1 / -0
    A man and woman are both heterozygous for the recessive allele that causes cystic fibrosis. What is the probability that their first two off spring will have the disorder ?
    Solution
    Correct option: C

    Explanation:
    • Cystic fibrosis is an autosomal recessive disorder, which means the cell should have both affected chromosome to become affected.
    • The Man and Female are both heterozygous with affected recessive allele i.e., $$X^CY$$ and $$X^CX$$ are crossed.
      $$X^C$$ $$Y$$
     $$X^C$$ $$X^CX^C$$ $$X^CY$$
     $$X$$ $$X^CX$$ $$XY$$
    • Out of 4 only 1/4 is affected. Therefore, the probability of having the disorder in first two off spring would be 1/4 X 1/4 = 1/16.
    • Thus, Option C is correct.
  • Question 6
    1 / -0
    Let us consider a system of units in which mass and angular momentum are dimensionless. If the length has dimension of L, then the dimension of power is
    Solution
    $$[M] = mass = M^0L^0T^0$$
    $$J(R)$$ = angular momentum
    $$e = mvR = \dfrac{mL^2}{T}$$
    $$m \rightarrow$$ Dimensionless
    $$T = L^{2}$$
    L is also Dimensionless
    Now $$P = mv = \dfrac{mL}{T}$$
    m is dimensionless
    $$[P] = L^{-1}$$
    Power = $$\dfrac{mL^2}{T^2 . T} = \dfrac{L^2}{L^2T^2L} = L^{-4}$$
  • Question 7
    1 / -0
    A long capillary tube with both ends open is filled with water and set in a vertical position. The radius of the capillary is $$0.1\ cm$$ and surface tension of water is $$70$$ dynes/ cm. The length of the water column remaining in the capillary tube will be approximately.
    Solution
    Weight of fliuid = Surface tension force at both end
    $$\pi r^2 d_0gh =2F=4\pi r\alpha$$

    $$h=\dfrac {4\alpha}{d_0 gr}$$

    here $$\alpha$$ is surface position

    $$h=3\ cm$$

    $$3.14\times (0.1)^2 \times 10^{-4}\times 100\times 10\times h$$

    $$=4\times 3.14\times 0.1\times 10^{-2}x$$

    $$h=\dfrac {4\times 70\times 10^{-5}/ 10^{-2}}{1000\times 10\times 0.1\times 10^{-2}}$$

    $$=\dfrac {280\times 10^{-5}}{10^{-1}}$$

    $$=280\times 10^{-4}m$$

    $$=0.28\times 10^{-2}m$$

    $$=0.28\ cm$$
  • Question 8
    1 / -0
    A torque of magnetude 200 Nm acting body produces an angular acceleration of 8 $$ rad / s ^{ 2} .$$ . The moment of inertia of the body is 
  • Question 9
    1 / -0
    A torque of magnetude 200 Nm acting body produces an angular acceleration of 8 $$ rad / s ^{ 2} .$$ . The moment of inertia of the body is 
  • Question 10
    1 / -0
    If $$Z= \frac{A}{A-B}$$ and $$A$$ and $$B$$ are measured with error $$\Delta A$$ and $$\Delta B$$ respectively, then relative error in $$Z$$, that is $$\frac{\Delta Z}{Z}$$ is equal to
    Solution
    $$Z= \dfrac{A}{A-B}$$

    take log both sides

    $$\log z= \log \left[ \dfrac{A}{A- B} \right]$$

    $$\log z = \log A - \log (A - B)$$

    differentiate -

    $$\dfrac{\Delta Z}{Z}=\dfrac{\Delta A}{A} - \dfrac{\Delta A - \Delta B}{A- B}$$
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